MCQ Questions for Class 12 Maths Chapter 1 Relations and Functions with Answers

Students can access the NCERT MCQ Questions for Class 12 Maths Chapter 1 Relations and Functions with Answers Pdf free download aids in your exam preparation and you can get a good hold of the chapter. Use MCQ Questions for Class 12 Maths with Answers during preparation and score maximum marks in the exam. Students can download the Relations and Functions Class 12 MCQs Questions with Answers from here and test their problem-solving skills. Clear all the fundamentals and prepare thoroughly for the exam taking help from Class 12 Maths Chapter 1 Relations and Functions Objective Questions.

Relations and Functions Class 12 MCQs Questions with Answers

Students are advised to solve the Relations and Functions Multiple Choice Questions of Class 12 Maths to know different concepts. Practicing the MCQ Questions on Relations and Functions Class 12 with answers will boost your confidence thereby helping you score well in the exam.

Explore numerous MCQ Questions of Relations and Functions Class 12 with answers provided with detailed solutions by looking below.

Question 1.
Let R be the relation in the set (1, 2, 3, 4}, given by:
R = {(1, 2), (2, 2), (1, 1), (4, 4), (1, 3), (3, 3), (3, 2)}.
Then:
(a) R is reflexive and symmetric but not transitive
(b) R is reflexive and transitive but not symmetric
(c) R is symmetric and transitive but not reflexive
(d) R is an equivalence relation.

Answer

Answer: (b) R is reflexive and transitive but not symmetric


Question 2.
Let R be the relation in the set N given by : R = {(a, b): a = b – 2, b > 6}. Then:
(a) (2, 4) ∈ R
(b) (3, 8) ∈ R
(c) (6, 8) ∈ R
(d) (8, 7) ∈ R.

Answer

Answer: (c) (6, 8) ∈ R


Question 3.
Let A = {1, 2, 3}. Then number of relations containing {1, 2} and {1, 3}, which are reflexive and symmetric but not transitive is:
(a) 1
(b) 2
(c) 3
(d) 4.

Answer

Answer: (a) 1


Question 4.
Let A = (1, 2, 3). Then the number of equivalence relations containing (1, 2) is
(a) 1
(b) 2
(c) 3
(d) 4.

Answer

Answer: (b) 2


Question 5.
Let f: R → R be defined as f(x) = x4. Then
(a) f is one-one onto
(b) f is many-one onto
(c) f is one-one but not onto
(d) f is neither one-one nor onto.

Answer

Answer: (d) f is neither one-one nor onto.


Question 6.
Let f : R → R be defined as f(x) = 3x. Then
(a) f is one-one onto
(b) f is many-one onto
(c) f is one-one but not onto
(d) f is neither one-one nor onto.

Answer

Answer: (a) f is one-one onto


Question 7.
If f: R → R be given by f(x) = (3 – x³)1/3, then fof (x) is
(a) x1/3
(b) x³
(c) x
(d) 3 – x³.

Answer

Answer: (c) x


Question 8.
Let f: R – {-\(\frac { 4 }{3}\)} → R be a function defined as: f(x) = \(\frac { 4x }{3x+4}\), x ≠ –\(\frac { 4 }{3}\). The inverse of f is map g : Range f → R -{-\(\frac { 4 }{3}\)} given by
(a) g(y) = \(\frac { 3y }{3-4y}\)
(b) g(y) = \(\frac { 4y }{4-3y}\)
(c) g(y) = \(\frac { 4y }{3-4y}\)
(d) g(y) = \(\frac { 3y }{4-3y}\)

Answer

Answer: (b) g(y) = \(\frac { 4y }{4-3y}\)


Question 9.
Let R be a relation on the set N of natural numbers defined by nRm if n divides m. Then R is
(a) Reflexive and symmetric
(b) Transitive and symmetric
(c) Equivalence
(d) Reflexive, transitive but not symmetric.

Answer

Answer: (b) Transitive and symmetric


Question 10.
Set A has 3 elements and the set B has 4 elements. Then the number of injective mappings that can be defined from A to B is:
(a) 144
(b) 12
(c) 24
(d) 64

Answer

Answer: (c) 24


Question 11.
Let f: R → R be defined by f(x) = sin x and g : R → R be defined by g(x) = x², then fog is
(a) x² sin x
(b) (sin x)²
(c) sin x²
(d) \(\frac { sin x }{x^2}\)

Answer

Answer: (c) sin x²


Question 12.
Let f: R → R be defined by f(x) = x² + 1. Then pre-images of 17 and – 3 respectively, are
(a) ø, {4,-4}
(b) {3, -3}, ø
(c) {4, -4}, ø
(d) {4, -4}, {2,-2}.

Answer

Answer: (c) {4, -4}, $


Question 13.
Let f: R → R be defined by
f(x)= \(\left\{\begin{array}{lr}
2 x ; & x>3 \\
x^{2} ; & 1<x<3 \\
3 x ; & x \leq 1
\end{array}\right.\)
(a) 9
(b) 14
(c) 5
(d) None of these.

Answer

Answer: (a) 9


Question 14.
The domain of the function f (x) = \(\frac { 1 }{\sqrt{|x|-x}}\) is
(a) (-∞, ∞)
(b) (0, ∞)
(c) (-∞, 0)
(d) (-∞, ∞) – {0}.

Answer

Answer: (c) (-∞, 0)
Hint:
f(x) = \(\frac { 1 }{\sqrt{|x|-x}}\)
f(x) is defined if |x| – x > 0
if |x| > x
if x < 0.
Hence, Df = (-∞, 0).


Question 15.
If a ∈ R and the equation
-3(x – [x] )2 + 2 (x – [x]) + a² = 0,
where [x] denotes the greatest integer (≤ x) has no integral solution, then all possible values of a lie in the interval:
(a) (1, 2)
(b) (-2, -1)
(c) (-∞, -2) ∪(2, ∞)
(d) (-1, 0) ∪ (0, 1).

Answer

Answer: (d) (-1, 0) ∪ (0, 1).
Hint:
Put x – [x] = t.
Then – 3t² + 2t + a² = 0
⇒ a² = 3t² – 2t.
For non-integral solutions, 0 < a² < 1.
Hence, as (- 1, 0) ∪ (0, 1).


Fill in the Blanks

Question 1.
Let A = {1, 2, 3}. Then the number of equivalence relations containing (1, 2) is ………………

Answer

Answer: 2.


Question 2.
If A = {0, 1, 3}, then the number of relations on A is ………………..

Answer

Answer: 9.


Question 3.
A bijective function is both ……………….. and ………………

Answer

Answer: one-one, onto.


Question 4.
Let R be a relation defined on A = { 1, 2, 3) by R = {(1, 3), (3, 1), (2, 2)}, R is ………………..

Answer

Answer: symmetric.


Question 5.
If f be the greatest integer function defined as f(x) = [x] and g be the modulus function defined as g(x) = |x|, then the value of gof (\(\frac { -5 }{4}\)) is ………………..

Answer

Answer: 2.
Hint:
gof (\(\frac { -5 }{4}\)) = g (f(\(\frac { -5 }{4}\)))
= g(-2) = |-2| = 2.


Question 6.
If f : R → R is defined by 3x + 4, then f(f(x)) is …………….

Answer

Answer: 9x + 16.
Hint:
f(f (x)) = f(3x + 4)
= 3f(x) + 4
= 3 (3x + 4) + 4
= 9x + 16.


Question 7.
If f(x) = ex and g(x) = log x, then gof is ……………….

Answer

Answer: x.
Hint:
gof (x) = g(f(x) = g (ex)
= log ex = x log e = x(1) = x.


Question 8.
The domain of the function f (x) = \(\frac { x }{|x|}\) is ………………..

Answer

Answer: R – {0}.
Hint:
f is defined for all x ∈ R except at x = 0.


Question 9.
Let f: R – {-\(\frac { 4 }{3}\)} → R be a function defined as: f(x) = \(\frac { 4x }{3x+4}\), x ≠ –\(\frac { 4 }{3}\)
Then inverse of f is map g : Range f → R – {-\(\frac { 4 }{3}\)} given by …………………

Answer

Answer: g(y) = \(\frac { 4x }{3x+4}\)
Hint:
Let y = f(x)= \(\frac { 4x }{3x+4}\)
⇒ 3xy + 4y = 4x
⇒ (4 – 3y)x = 4y
⇒ x = \(\frac { 4y }{4-3y}\)


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