These NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.7 Questions and Answers are prepared by our highly skilled subject experts.
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.7
Question 1.
Find:
(i) 0.4 ÷ 2
(ii) 0.35 ÷ 5
(iii) 2.48 ÷ 4
(iv) 65.4 ÷ 6
(v) 651.2 ÷ 4
(vi) 14.49 ÷ 7
(vii) 3.96 ÷ 4
(viii) 0.80 ÷ 5
Question 2.
Find:
(1) 4.8 ÷ 10
(ii) 52.5 ÷ 10
(iii) 0.7 ÷ 10
(iv) 33.1 ÷ 10
(V) 272.23 ÷ 10
(vi) 0.56 ÷ 10
(vii) 3.97 ÷ 10
Answer:
Question 3.
Find:
(i) 2.7 ÷ 100
(ii) 0.3 ÷ 100
(iii) 0.78 ÷ 100
(iv) 432.6 ÷ 100
(v) 23.6 ÷ 100
(vi) 98.53 ÷ 100
Answer:
(i) 2.7 ÷ 100 \(\frac{2.7}{100}\)
There are two zeros in 100
∴ The decimal point in the quotient is shifted to the left by two places
∴ \(\frac{2.7}{100}\) = 0.027
(ii) 0.3 ÷ 100
There are two zeros in 100
∴ The decimal point in the quotient is shifted to the left by two places
∴ 0.3 ÷ 100 = \(\frac{0.3}{100}\) = 0.003
(iii) 0.78 ÷ 100
There are two zeros in 100
∴ The decimal point in the quotient is shifted to the left by two places
∴ 0.78 ÷ 100 = \(\frac{0.78}{100}\) = 0.0078
(iv) 432.6 ÷ 100
There are two zeros in 100
∴ The decimal point in the quotient is shifted to the left by two places
∴ 432.6 ÷ 100 = \(\frac{432.6}{100}\) = 4.326
(v) 23.6 ÷ 100
There are two zeros in 100
The decimal point in the quotient is shifted to the left by two places
∴ 23.6 ÷ 100 = \(\frac{23.6}{100}\) = 0.236
(vi) 98.53 ÷ 100
There are two zeros in 100
∴ The decimal point in the quotient is shifted to the left by two places
∵ 98.53 ÷ 100 = \(\frac{98.53}{100}\) = 0.9853
Question 4.
(i) 7.9 ÷ 1000
(ii) 26.3 ÷ 1000
(iii) 38.53 ÷ 1000
(iv) 128.9 ÷ 1000
(v) 0.5 ÷ 1000
Answer:
(i) 7.9 ÷ 1000 = \(\frac{7.9}{1000}\) = 0.0079
(ii) 26.3 ÷ 1000 = \(\frac{26.3}{1000}\) = 0.0263
(iii) 38.53 ÷ 1000 = \(\frac{38.53}{1000}\) = 0.03853
(iv) 128.9 ÷ 1000 = \(\frac{128.9}{1000}\) = 0.1289
(v) 0.5 ÷ 1000 = \(\frac{0.5}{1000}\) = 0.0005
Question 5.
(i) 7 ÷ 3.5
(ii) 36 ÷ 0.2
(iii) 3.25 ÷ 0.5
(iv) 30.94 ÷ 0.7
(v) 0.5 ÷ 0.25
(vi) 7.75 ÷ 0.25
(vii) 76.5 ÷ 0.15
(viii) 37.8 ÷ 1.4
(ix) 2.73 ÷ 1.3
Answer:
Question 6.
A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance
will it cover in one litre of petrol?
Answer:
Total distance covered 43.2 km
Quantity of petrol used = 2.4 litres
∴ Distance covered in one litre petrol
= \(\frac{\text { Total distance covered }}{\text { Total quantity of petrol }}\)
= \(\frac{43.2}{2.4}\) km
= \(\frac{432 \times 10}{24 \times 10}=\frac{432}{24}\) = l8km
Distance covered in one litre of petrol = 18km