{"id":17556,"date":"2021-02-01T10:43:21","date_gmt":"2021-02-01T05:13:21","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=17556"},"modified":"2021-02-03T14:11:35","modified_gmt":"2021-02-03T08:41:35","slug":"mcq-questions-for-class-11-physics-chapter-13","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/mcq-questions-for-class-11-physics-chapter-13\/","title":{"rendered":"MCQ Questions for Class 11 Physics Chapter 13 Kinetic Theory with Answers"},"content":{"rendered":"

Students are advised to practice the\u00a0NCERT MCQ Questions for Class 11 Physics Chapter 13 Kinetic Theory with Answers Pdf free download is available here. MCQ Questions for Class 11 Physics with Answers<\/a> are prepared as per the Latest Exam Pattern. Students can solve these Kinetic Theory Class 11 MCQs Questions with Answers and assess their preparation level.<\/p>\n

Kinetic Theory Class 11 MCQs Questions with Answers<\/h2>\n

Solving the Kinetic Theory Multiple Choice Questions of Class 11 Physics Chapter 13 MCQ can be of extreme help as you will be aware of all the concepts. These MCQ Questions on Kinetic Theory Class 11 with answers pave for a quick revision of the Chapter thereby helping you to enhance subject knowledge. Have a glance at the MCQ of Chapter 13 Physics Class 11 and cross-check your answers during preparation.<\/p>\n

Question 1.
\nA room temperature the r.m.s. velocity of the molecules of a certain diatomic gas is found to be 1930 m\/sec. the gas is
\n(a) H\u00b2
\n(b) F\u00b2
\n(c) O\u00b2
\n(d) Cl\u00b2<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) H\u00b2<\/p>\n<\/details>\n

\n

Question 2.
\nEnergy supplied to convert unit mass of substance from solid to liquid state at its melting point is called
\n(a) Latent heat of fusion
\n(b) Evaporation
\n(c) Solidification
\n(d) Latent heat of fission<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) Latent heat of fusion<\/p>\n<\/details>\n

\n

Question 3.
\nOne any planet, the presence of atmosphere implies [nrms = root mean square velocity of molecules and ne = escape velocity]
\n(a) nrms << ne
\n(b) nrms > ne
\n<\/span>(c) nrms = ne
\n<\/span>(d) nrms = 0<\/span><\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) nrms << ne<\/p>\n<\/details>\n

\n

Question 4.
\nCalculate the RMS velocity of molecules of a gas of which the ratio of two specific heats is 1.42 and velocity of sound in the gas is 500 m\/s
\n(a) 727 m\/s
\n(b) 527 m\/s
\n(c) 927 m\/s
\n(d) 750 m\/s<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) 727 m\/s<\/p>\n<\/details>\n

\n

Question 5.
\nThe r.m.s. speed of the molecules of a gas in a vessel is 200 m\/s. if 25% of the gas leaks out of the vessel, at constant temperature, then the r.m.s. speed of the remaining molecules will be
\n(a) 400 m\/s
\n(b) 150 m\/s
\n(c) 100 m\/s
\n(d) 200 m\/s<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) 200 m\/s<\/p>\n<\/details>\n

\n

Question 6.
\nA gas is taken in a sealed container at 300 K. it is heated at constant volume to a temperature 600 K. the mean K.E. of its molecules is
\n(a) Halved
\n(b) Doubled
\n(c) Tripled
\n(d) Quadrupled<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) Doubled<\/p>\n<\/details>\n

\n

Question 7.
\nMoon has no atmosphere because
\n(a) It is far away form the surface of the earth
\n(b) Its surface temperature is 10\u00b0C
\n(c) The r.m.s. velocity of all the gas molecules is more then the escape velocity of the moons surface
\n(d) The escape velocity of the moons surface is more than the r.m.s velocity of all molecules<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) The r.m.s. velocity of all the gas molecules is more then the escape velocity of the moons surface<\/p>\n<\/details>\n

\n

Question 8.
\nA unit mass of solid converted to liquid at its melting point. Heat is required for this process is
\n(a) Specific heat
\n(b) Latent heat of vaporization
\n(c) Latent heat of fusion
\n(d) External latent heat<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) Latent heat of fusion<\/p>\n<\/details>\n

\n

Question 9.
\nOne mole of ideal gas required 207 J heat to rise the temperature by 10\u00b0K when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by the same 10\u00b0K the heat required is (R = 8\/3 J\/mole \u00b0K)
\n(a) 1987 J
\n(b) 29 J
\n(c) 215.3 J
\n(d) 124 J<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) 124 J<\/p>\n<\/details>\n

\n

Question 10.
\nThe r.m.s velocity of the molecules of an ideal gas is C at a temperature of 100K. at what temperature is r.m.s. velocity will be doubted?
\n(a) 200 K
\n(b) 400 K
\n(c) 300 K
\n(d) 50 K<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) 400 K<\/p>\n<\/details>\n

\n

Question 11.
\nOne mole of an ideal gas requires 207 J heat to raise the temperature by 10 K, when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by 10K, then heat required is
\n(a) 96.6 J
\n(b) 124 J
\n(c) 198.8 J
\n(d) 215.4 J<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) 124 J<\/p>\n<\/details>\n

\n

Question 12.
\n5 gm of air is heated from 273\u00b0K to 275\u00b0K. the change in internal energy of air will be (CV = 172 cal\/kg \u00b0K and 4.2 J\/cal)
\n(a) 7.22 J
\n(b) 5.22 J
\n(c) 8.16 J
\n(d) 3.5 J<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) 7.22 J<\/p>\n<\/details>\n

\n

Question 13.
\nThe specific heat of a gas in isothermal process is
\n(a) Zero
\n(b) Negative
\n(c) Remains constant
\n(d) Infinite<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) Infinite<\/p>\n<\/details>\n

\n

Question 14.
\nThe internal energy of one mole of an ideal gas depend upon
\n(a) Volume of gas
\n(b) Temperature of gas
\n(c) Nature of gas
\n(d) Density of gas<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) Temperature of gas<\/p>\n<\/details>\n

\n

Question 15.
\nWhich of the following is the unit of specific
\n(a) J kg\/\u00b0c
\n(b) J\/kg\u00b0c
\n(c) kg \u00b0c\/J
\n(d) J kg\/\u00b0c\u00b2<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) J\/kg\u00b0c<\/p>\n<\/details>\n

\n

Question 16.
\nFor a gas, the r.m.s. speed at 800K is
\n(a) Half the value at 200 K
\n(b) Double the value at 200 K
\n(c) Same as at 200 K
\n(d) Four times the value at 200 K<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) Double the value at 200 K<\/p>\n<\/details>\n

\n

Question 17.
\nPV\/3 = RT, V represents volume of
\n(a) Any amount of gas
\n(b) 2 moles of gas
\n(c) 3 moles of gas
\n(d) 4 moles of gas<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) 3 moles of gas<\/p>\n<\/details>\n

\n

Question 18.
\nThe average kinetic energy of the molecules of a gas at 27\u00b0C is 9 10-20 J. what is its average K.E. at 227\u00b0C?
\n(a) 5 10-20 J
\n(b) 10 10-20 J
\n(c) 15 10-20 J
\n(d) 20 10-20 J<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) 15 10-20 J<\/p>\n<\/details>\n

\n

Question 19.
\nAt constant volume temperature is increased then
\n(a) Collision on walls will be less
\n(b) Collision frequency will be increases
\n(c) Collision will be in straight line
\n(d) Collision will not change<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) Collision frequency will be increases<\/p>\n<\/details>\n

\n

Question 20.
\nFollowing gases are kept at the same temperature. Which gas possesses maximum r.m.s. speed?
\n(a) Oxygen
\n(b) Nitrogen
\n(c) Hydrogen
\n(d) Carbon dioxide<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) Hydrogen<\/p>\n<\/details>\n

\n

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Students are advised to practice the\u00a0NCERT MCQ Questions for Class 11 Physics Chapter 13 Kinetic Theory with Answers Pdf free download is available here. MCQ Questions for Class 11 Physics with Answers are prepared as per the Latest Exam Pattern. Students can solve these Kinetic Theory Class 11 MCQs Questions with Answers and assess their …<\/p>\n

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