{"id":24702,"date":"2021-06-19T18:32:00","date_gmt":"2021-06-19T13:02:00","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=24702"},"modified":"2021-06-21T12:53:03","modified_gmt":"2021-06-21T07:23:03","slug":"ncert-solutions-for-class-6-maths-chapter-14-ex-14-2","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-14-ex-14-2\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2"},"content":{"rendered":"<p>These <a href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths\/\">NCERT Solutions for Class 6 Maths<\/a> Chapter 14 Practical Geometry Ex 14.2 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n<h2>NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Exercise 14.2<\/h2>\n<p>Question 1.<br \/>\nDraw a line segment of length 7.3 cm, using a ruler.<br \/>\nAnswer:<br \/>\nSteps of construction:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-24703\" src=\"https:\/\/i2.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-1.png?resize=349%2C46&#038;ssl=1\" alt=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 1\" width=\"349\" height=\"46\" srcset=\"https:\/\/i2.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-1.png?w=349&amp;ssl=1 349w, https:\/\/i2.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-1.png?resize=300%2C40&amp;ssl=1 300w\" sizes=\"(max-width: 349px) 100vw, 349px\" data-recalc-dims=\"1\" \/><\/p>\n<ul>\n<li>Place the zero mark of the ruler at a point A.<\/li>\n<li>Mark a point B at a distance of 7.3 cm from A.<\/li>\n<li>Join AB.<br \/>\nHence, \\(\\overline{\\mathrm{AB}}\\) is the required line segment of length 7.3 cm.<\/li>\n<\/ul>\n<p>Question 2.<br \/>\nConstruct a line segment of length 5.6 cm using ruler and compasses.<br \/>\nAnswer:<br \/>\nSteps of construction:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-24704\" src=\"https:\/\/i0.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-2.png?resize=353%2C75&#038;ssl=1\" alt=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 2\" width=\"353\" height=\"75\" srcset=\"https:\/\/i0.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-2.png?w=353&amp;ssl=1 353w, https:\/\/i0.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-2.png?resize=300%2C64&amp;ssl=1 300w\" sizes=\"(max-width: 353px) 100vw, 353px\" data-recalc-dims=\"1\" \/><\/p>\n<ul>\n<li>Draw a line \u2019l\u2019. 1 Mark a point A on this line.<\/li>\n<li>Place the compasses pointer on zero mark of the ruler. Open it to place the pencil point up to 5.6 cm mark.<\/li>\n<li>Without changing the opening of the compasses. Place the pointer on A and cut an arc \u2019l\u2019 at B.<br \/>\n\\(\\overline{\\mathrm{AB}}\\) is the required line segment of length 5.6 cm.<\/li>\n<\/ul>\n<p><img loading=\"lazy\" class=\"alignnone\" src=\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/01\/NCERT-Solutions-Guru.png?resize=170%2C17&#038;ssl=1\" alt=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2\" width=\"170\" height=\"17\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 3.<br \/>\nConstruct \\(\\overline{\\mathrm{AB}}\\) of length 7.8 cm. From this, cut off \\(\\overline{\\mathrm{AC}}\\) of length 4.7 cm. Measure \\(\\overline{\\mathrm{BC}}\\).<br \/>\nAnswer:<br \/>\nSteps of construction:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-24705\" src=\"https:\/\/i0.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-3.png?resize=360%2C82&#038;ssl=1\" alt=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 3\" width=\"360\" height=\"82\" srcset=\"https:\/\/i0.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-3.png?w=360&amp;ssl=1 360w, https:\/\/i0.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-3.png?resize=300%2C68&amp;ssl=1 300w\" sizes=\"(max-width: 360px) 100vw, 360px\" data-recalc-dims=\"1\" \/><\/p>\n<ul>\n<li>Place the zero mark of the ruler at A.<\/li>\n<li>Mark a point B at a distance 7.8 cm from A.<\/li>\n<li>Again, mark a point C at a distance 4.7 from A.<br \/>\nHence, by measuring \\(\\overline{\\mathrm{BC}}\\), we find that BC = 3.1 cm.<\/li>\n<\/ul>\n<p>Question 4.<br \/>\nGiven \\(\\overline{\\mathrm{AB}}\\) of length 3.9 cm, construct \\(\\overline{\\mathrm{PQ}}\\) such that the length of \\(\\overline{\\mathrm{PQ}}\\) is twice that of \\(\\overline{\\mathrm{AB}}\\). Verify by measurement.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-24706\" src=\"https:\/\/i2.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-4.png?resize=391%2C71&#038;ssl=1\" alt=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 4\" width=\"391\" height=\"71\" srcset=\"https:\/\/i2.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-4.png?w=391&amp;ssl=1 391w, https:\/\/i2.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-4.png?resize=300%2C54&amp;ssl=1 300w\" sizes=\"(max-width: 391px) 100vw, 391px\" data-recalc-dims=\"1\" \/><br \/>\n(Hint: construct \\(\\overline{\\mathrm{PX}}\\) such that length of \\(\\overline{\\mathrm{PX}}\\) = length of \\(\\overline{\\mathrm{AB}}\\); then cut off \\(\\overline{\\mathrm{XQ}}\\) such that \\(\\overline{\\mathrm{XQ}}\\) also has the length of \\(\\overline{\\mathrm{AB}}\\).)<br \/>\nAnswer:<br \/>\nSteps of construction:<\/p>\n<ul>\n<li>Draw a line \u2019l&#8217;.<\/li>\n<li>Construct \\(\\overline{\\mathrm{PX}}\\) such that length of \\(\\overline{\\mathrm{PX}}\\) = length of \\(\\overline{\\mathrm{AB}}\\)<\/li>\n<li>Then cut of \\(\\overline{\\mathrm{XQ}}\\) such that \\(\\overline{\\mathrm{XQ}}\\) also has the length of \\(\\overline{\\mathrm{AB}}\\).<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-24707\" src=\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-5.png?resize=353%2C82&#038;ssl=1\" alt=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 5\" width=\"353\" height=\"82\" srcset=\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-5.png?w=353&amp;ssl=1 353w, https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-5.png?resize=300%2C70&amp;ssl=1 300w\" sizes=\"(max-width: 353px) 100vw, 353px\" data-recalc-dims=\"1\" \/><\/li>\n<li>Thus the length of \\(\\overline{\\mathrm{PX}}\\) and the length of \\(\\overline{\\mathrm{XQ}}\\) added together make twice the length of \\(\\overline{\\mathrm{AB}}\\)<\/li>\n<\/ul>\n<p>Verification:<br \/>\nHence, by measurement we find that PQ = 7.8 cm = 3.9 cm + 3.9 cm =<br \/>\n\\(\\overline{\\mathrm{AB}}+\\overline{\\mathrm{AB}}\\) 2 \u00d7 \\(\\overline{\\mathrm{AB}}\\)<\/p>\n<p><img loading=\"lazy\" class=\"alignnone\" src=\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/01\/NCERT-Solutions-Guru.png?resize=170%2C17&#038;ssl=1\" alt=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2\" width=\"170\" height=\"17\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 5.<br \/>\nGiven AB of length 7.3 cm and \\(\\overline{\\mathrm{CD}}\\) of length 3.4 cm, construct a line segment \\(\\overline{\\mathrm{XY}}\\) such that the length of \\(\\overline{\\mathrm{XY}}\\) is equal to the difference between the lengths of \\(\\overline{\\mathrm{AB}}\\) and \\(\\overline{\\mathrm{CD}}\\) Verify by measurement.<br \/>\nAnswer:<br \/>\nSteps of construction:<\/p>\n<ul>\n<li>Draw a line &#8216;l&#8217; and take a point X on it.<\/li>\n<li>Construct \\(\\overline{\\mathrm{XZ}}\\) such that length \\(\\overline{\\mathrm{XZ}}\\) = length of \\(\\overline{\\mathrm{AB}}\\) = 7.3 cm<\/li>\n<li>Then cut off \\(\\overline{\\mathrm{ZY}}\\) = length of \\(\\overline{\\mathrm{CD}}\\) = 3.4 cm<\/li>\n<li>Thus the length of \\(\\overline{\\mathrm{XY}}\\) = length of \\(\\overline{\\mathrm{AB}}\\) &#8211; length of \\(\\overline{\\mathrm{CD}}\\)<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-24708\" src=\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-6.png?resize=353%2C104&#038;ssl=1\" alt=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 6\" width=\"353\" height=\"104\" srcset=\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-6.png?w=353&amp;ssl=1 353w, https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-6-Maths-Chapter-14-Practical-Geometry-Ex-14.2-6.png?resize=300%2C88&amp;ssl=1 300w\" sizes=\"(max-width: 353px) 100vw, 353px\" data-recalc-dims=\"1\" \/><br \/>\nVerification:<br \/>\nHence, by measurement we find that length of \\(\\overline{\\mathrm{XY}}\\) = 3.9 cm = 73. cm -3.4 cm = \\(\\overline{\\mathrm{AB}}-\\overline{\\mathrm{CD}}\\)<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>These NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Exercise 14.2 Question 1. Draw a line segment of length 7.3 cm, using a ruler. Answer: Steps of construction: Place the &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-14-ex-14-2\/\"> <span class=\"screen-reader-text\">NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v16.7 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-14-ex-14-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 Questions and Answers are prepared by our highly skilled subject experts. 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NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Exercise 14.2 Question 1. Draw a line segment of length 7.3 cm, using a ruler. 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