{"id":25297,"date":"2021-06-22T15:13:35","date_gmt":"2021-06-22T09:43:35","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=25297"},"modified":"2021-06-30T18:06:04","modified_gmt":"2021-06-30T12:36:04","slug":"ncert-solutions-for-class-6-maths-chapter-12-ex-12-2","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-12-ex-12-2\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.2"},"content":{"rendered":"

These NCERT Solutions for Class 6 Maths<\/a> Chapter 12 Ratio and Proportion Ex 12.2 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Exercise 12.2<\/h2>\n

Question 1.
\nDetermine if the following are in proportion.
\n(a) 15, 45 ; 40, 120
\n(b) 33, 121; 9, 96
\n(c) 24, 28, 36, 48
\n(d) 32,48 :70,210
\n(e) 4, 6 ; 8, 12
\n(f) 33, 44 ; 75, 100
\nAnswer:
\n(a) 15 : 45 = \\(\\frac{15}{45}=\\frac{1}{3}\\) = 1 : 3
\n40 : 120 = \\(\\frac{40}{120}=\\frac{1}{3}\\) = 1 : 3
\nSince, 15 : 45 = 40 : 120
\nTherefore, 15,45,40,120 are in proportion.<\/p>\n

(b) 33 : 121= \\(\\frac{33}{121}=\\frac{3}{11}\\) = 3 : 11
\n9 : 96 = \\(\\frac{9}{96}=\\frac{3}{32}\\) = 3 : 32
\nSince, 33 : 121 \u2260 9 : 96
\nTherefore, 33,121,9,96 are not in proportion.<\/p>\n

(c) 24 : 28 = \\(\\frac{24}{28}=\\frac{6}{7}\\) = 6 : 7
\n36 : 48 = \\(\\frac{36}{48}=\\frac{3}{4}\\) = 3 : 4
\nSince, 24 : 28 \u2260 36 : 48
\nTherefore, 24, 28,36, 48 are not in proportion.<\/p>\n

(d) 32 : 48 = \\(\\frac{32}{48}=\\frac{2}{3}\\) = 2 : 3
\n70 : 210= \\(\\frac{70}{210}=\\frac{1}{3}\\) = 1 : 3
\nSince, 32 : 48 \u2260 70 : 210
\nTherefore, 32,48, 70, 210 are not in proportion.
\n(e) 4 : 6 = \\(\\frac{4}{6}=\\frac{2}{3}\\) = 2 : 3
\n8 : 12 = \\(\\frac{8}{12}=\\frac{2}{3}\\) = 2 : 3
\nSince, 4 : 6 = 8 : 12
\nTherefore, 4,6,8,12 are in proportion.<\/p>\n

(f) 33 : 44 = \\(\\frac{33}{44}=\\frac{3}{4}\\) = 3 : 4
\n75 : 100 = \\(\\frac{75}{100}=\\frac{3}{4}\\) = 3 : 4
\nSince, 33 : 44 = 75 : 100
\nTherefore, 33, 44, 75,100 are in ratio.<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nWrite True (T) or False (F) against each of the following statements:
\n(a) 16 : 24 :: 20 : 30
\n(b) 21: 6:: 35 : 10
\n(c) 12: 18:: 28:12
\n(d) 8:9:: 24: 27
\n(e) 5.2 : 3.9 :: 3 :4
\n(f) 0.9 : 0.36 :: 10 : 4
\nAnswer:
\n(a) 16 : 24 :: 20 : 30
\n\u21d2 \\(\\frac{16}{24}=\\frac{20}{30}\\) \u21d2 \\(\\frac{2}{3}=\\frac{2}{3}\\)
\nHence, it is true.<\/p>\n

(b) 21 : 6 :: 35 : 10
\n\u21d2 \\(\\frac{21}{6}=\\frac{35}{10}\\) \u21d2 \\(\\frac{7}{2}=\\frac{7}{2}\\)
\nHence, it is true.<\/p>\n

(c) 12 : 18 :: 28 : 12
\n\u21d2 \\(\\frac{12}{18}=\\frac{28}{12}\\) \u21d2 \\(\\frac{2}{3} \\neq \\frac{7}{3}\\)
\nHence, it is false.<\/p>\n

(d) 8 : 9 :: 24 : 27
\n\u21d2 \\(\\frac{8}{9}=\\frac{24}{27}\\) \u21d2 \\(\\frac{8}{9}=\\frac{8}{9}\\)
\nHence, it is true.<\/p>\n

(e) 5.2 : 3.9 :: 3 : 4
\n\u21d2 \\(\\frac{5.2}{3.9}=\\frac{3}{4}\\) \u21d2 \\(\\frac{4}{3} \\neq \\frac{3}{4}\\)
\nHence, it is false.<\/p>\n

(f) 0.9 : 0.36 :: 10 : 4
\n\u21d2 \\(\\frac{0.9}{0.36}=\\frac{10}{4}\\) \u21d2 \\(\\frac{5}{2}=\\frac{5}{2}\\)
\nHence, it is true.<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nAre the following statements true?
\n(a) 40 persons : 200 persons = \u20b9 15: \u20b9 75
\n(b) 7.5 litres : 15 litres = 5 kg : 10 kg
\n(c) 99 kg : 45 kg = \u20b9 44 : \u20b9 20
\n(d) 32 m : 64 m = 6 sec : 12 sec
\n(e) 45 km : 60 km = 12 hours : 15 hours
\nAnswer:
\n(a) 40 persons : 200 persons
\n= \\(\\frac{40}{200}=\\frac{1}{5}\\) = 1 : 5
\n\u20b9 15 : \u20b9 75 = \\(\\frac{15}{75}=\\frac{1}{5}\\) = 1 : 5
\nSince, 40 persons : 200 persons = \u20b9 15 : \u20b9 75
\nHence, the statement is true.<\/p>\n

(b) 7.5 litres : 15 litres
\n= \\(\\frac{7.5}{15}=\\frac{75}{150}=\\frac{1}{2}\\) = 1 : 2
\n5 kg : 10 kg = \\(\\frac{5}{10}=\\frac{1}{2}\\) = 1 : 2
\nSince, 7.5 litres : 15 litres = 5 kg: 10 kg
\nHence, the statement is true.<\/p>\n

(c) 99 kg : 45 kg = \\(\\frac{99}{45}=\\frac{11}{5}\\) = 11 : 5
\n\u20b9 44 : \u20b9 20= \\(\\frac{44}{20}=\\frac{11}{5}\\) = 11 : 5
\nSince, 99 kg: 45 kg = \u20b9 44 : \u20b9 20 Hence, the statement is true.<\/p>\n

(d) 32 m : 64 m = \\(\\frac{32}{64}=\\frac{1}{2}\\) = 1 : 2
\n6 sec : 12 sec = \\(\\frac{6}{12}=\\frac{1}{2}\\) = 1 : 2
\nSince, 32 m : 64 m = 6 sec : 12 sec Hence, the statement is true.<\/p>\n

(e) 45 km : 60 km = \\(\\frac{45}{60}=\\frac{3}{4}\\) = 3 : 4
\n12 hours : 15 hours
\n= \\(\\frac{12}{15}=\\frac{4}{5}\\) = 4 : 5
\nSince, 45 km : 60 km \u2260 12 hours : 15 hours
\nHence, the statement is not true.<\/p>\n

\"NCERT<\/p>\n

Question 4.
\nDetermine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion.
\n(a) 25 cm : 1 m and \u20b9 40: \u20b9 160
\n(b) 39 litres : 65 litres and 6 bottles : 10 bottles
\n(c) 2 kg: 80 kg and 25 g : 625 g
\n(d) 200 mL : 2.5 litre and \u20b9 4 : \u20b9 50
\nAnswer:
\n(a) 25 cm : 1 m = 25 cm : (1 \u00d7 100) cm
\n= 25 cm : 100 cm
\n= \\(\\frac{25}{100}=\\frac{1}{4}\\) = 1 : 4
\n\u20b9 40 : \u20b9 160 = \\(\\frac{40}{160}=\\frac{1}{4}\\) = 1 : 4
\nSince, the ratios are equal, therefore these are in proportion.
\nMiddle terms = 1 m, \u20b9 40 and
\nExtreme terms = 25 cm, \u20b9 160<\/p>\n

(b) 39 litres : 65 litres
\n= \\(\\frac{39}{65}=\\frac{3}{5}\\) = 3 : 5
\n6 bottles : 10 bottles
\n= \\(\\frac{6}{10}=\\frac{3}{5}\\) = 3 : 5
\nSince, the ratios are equal, therefore these are in proportion.
\nMiddle terms = 65 litres, 6 bottles and Extreme terms = 39 litres, 10 bottles<\/p>\n

(c) 2 kg : 80 kg = \\(\\frac{2}{80}=\\frac{1}{40}\\) = 1 : 40
\n25 g : 625 g = \\(\\frac{25}{625}=\\frac{1}{25}\\) = 1 : 25
\nSince, the ratios are not equal, therefore these are not in proportion,<\/p>\n

(d) 200 ml : 2.5 litres = 200 ml: (25000) litres = 200 ml : 2500 ml = \\(\\frac{200}{2500}=\\frac{2}{25}\\) = 2 : 25
\n\u20b9 4: \u20b9 50 = \\(\\frac{4}{50}=\\frac{2}{25}\\) = 2 : 25
\nSince, the ratios are equal, therefore these are in proportion.
\nMiddle terms = 2.5 litres, \u20b9 4 and Extreme terms = 200 ml, \u20b9 50<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.2 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Exercise 12.2 Question 1. Determine if the following are in proportion. (a) 15, 45 ; 40, 120 (b) 33, …<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.2<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.2 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-12-ex-12-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.2 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.2 Questions and Answers are prepared by our highly skilled subject experts. 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NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Exercise 12.2 Question 1. Determine if the following are in proportion. 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