{"id":25479,"date":"2021-06-23T10:32:42","date_gmt":"2021-06-23T05:02:42","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=25479"},"modified":"2021-06-25T15:35:26","modified_gmt":"2021-06-25T10:05:26","slug":"ncert-solutions-for-class-6-maths-chapter-11-ex-11-2","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-11-ex-11-2\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2"},"content":{"rendered":"

These NCERT Solutions for Class 6 Maths<\/a> Chapter 11 Algebra Ex 11.2 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 11 Algebra Exercise 11.2<\/h2>\n

Question 1.
\nThe side of an equilateral triangle is shown by l. Express the perimeter of the equilateral triangle using l.
\nAnswer:
\nSide of equilateral triangle = l
\nTherefore, Perimeter of equilateral triangle = 3 \u00d7 side = 3l<\/p>\n

Question 2.
\nThe Side of a regular hexagon (see the given figure) is denoted by l. Express the perimeter of the hexagon using l.
\n(Hint: A regular hexagon has all its six sides equal in length.)
\n\"NCERT
\nAnswer:
\nSide of hexagon = l
\nTherefore,
\nPerimeter of Hexagon = 6 \u00d7 side = 6l<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nA cube is a three-dimensional figure as shown in the given figure. It has six faces and all of them are identical squares. The length of an edge of the cube is given by l. Find the formula for the total length of the edges of a cube.
\n\"NCERT
\nAnswer:
\nLength of one edge of cube = l
\nNumber of edges in a cube = 12
\nTherefore, total length = 12 \u00d7 1 = 12l<\/p>\n

Question 4.
\nThe diameter of a circle is a line which joins two points on the circle and also passed through the centre of the circle. (In the adjoining figure AB is a diameter of the circle; C is its centre.) Express the diameter of the circle (d) in terms of its radius(r).
\n\"NCERT
\nAnswer:
\nSince, length of diameter is double the length of radius.
\nTherefore, d = 2r<\/p>\n

\"NCERT<\/p>\n

Question 5.
\nTo find sum of three numbers 14,27 and 13, we can have two ways:
\n(a) We may first add 14 and 27 to get 41 and then add 13 to it to get the total sum 54 or
\n(b) We may add 27 and 13 to get 40 and then add 14 to get the sum 54. Thus, (14 + 27) + 13 = 14 + (27 + 13)
\nThis can be done for any three numbers. This property is known as the associativity of addition of numbers. Express this property which we have already studied in the chapter on whole numbers, in a general way, by using variables a, b and c.
\nAnswer:
\n(a + b) + c = a + (b + c )<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 11 Algebra Exercise 11.2 Question 1. The side of an equilateral triangle is shown by l. Express the perimeter of the equilateral triangle using l. …<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-11-ex-11-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2 Questions and Answers are prepared by our highly skilled subject experts. 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