{"id":25727,"date":"2021-06-23T18:39:27","date_gmt":"2021-06-23T13:09:27","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=25727"},"modified":"2021-06-25T15:25:10","modified_gmt":"2021-06-25T09:55:10","slug":"ncert-solutions-for-class-6-maths-chapter-10-ex-10-3","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-10-ex-10-3\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3"},"content":{"rendered":"

These NCERT Solutions for Class 6 Maths<\/a> Chapter 10 Mensuration Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.3<\/h2>\n

Question 1.
\nFind the areas of the rectangles whose sides are:
\n(a) 3 cm and 4 cm
\n(b) 12 m and 21 m
\n(c) 2 km and 3 km
\n(d) 2 m and 70 cm
\nAnswer:
\n(a) Area of rectangle
\n= length \u00d7 breadth
\n= 3 cm \u00d7 4 cm = 12 cm2<\/sup><\/p>\n

(b) Area of rectangle
\n= length \u00d7 breadth
\n= 12 m \u00d7 21 m = 252 m2<\/sup><\/p>\n

(c) Area of rectangle
\n= length \u00d7 breadth
\n= 2 km \u00d7 3 km = 6 km2<\/sup><\/p>\n

(d) Area of rectangle
\n= lenght \u00d7 breadth
\n= 2m ( lm = 100cm)
\n= 200 cm \u00d7 70 cm = 14000sq.cm<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nFind the areas of the squares whose sides are:
\n(a) 10 cm
\n(b) 14 cm
\n(c) 5 m
\nAnswer:
\n(a) Area of square = side \u00d7 side
\n= 10 cm \u00d7 10 cm = 100 cm2<\/sup><\/p>\n

(b) Area of square = side \u00d7 side
\n= 14 cm \u00d7 14 cm = 196 cm2<\/sup><\/p>\n

(c) Area of square = side \u00d7 side
\n= 5 m \u00d7 5 m = 25 m2<\/sup><\/p>\n

Question 3.
\nThe length and breadth of three rectangles are as given below:
\n(a) 9 m and 6 m
\n(b) 17 m and 3 m
\n(c) 4 m and 14 m
\nWhich one has the largest area and which one has the smallest?
\nAnswer:
\n(a) Area of rectangle
\n= length \u00d7 breadth
\n= 9 m \u00d7 6 m = 54 m2<\/sup><\/p>\n

(b) Area of rectangle
\n= length \u00d7 breadth
\n= 3 m \u00d7 17 m = 51 m2<\/sup><\/p>\n

(c) Area of rectangle
\n= length \u00d7 breadth
\n= 4 m \u00d7 14 m = 56 m2<\/sup>
\nThus, the rectangle (c) has largest area, and rectangle (b) has smallest area.<\/p>\n

\"NCERT<\/p>\n

Question 4.
\nThe area of a rectangular garden 50 m long is 300 sq m. Find the width of the garden.
\nAnswer:
\nLength of rectangle
\n= 50 m and Area of rectangle = 300 m2 <\/sup>Since, Area of rectangle
\n= length \u00d7 breadth
\nTherefore, breadth
\n\\(\\frac{\\text { Area of rectangle }}{\\text { Length }}\\) = \\(\\frac{300}{50}\\) = 6m
\nThus, the breadth of the garden is 6 m.<\/p>\n

Question 5.
\nWhat is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of \u20b9 8 per hundred sq m?
\nAnswer:
\nLength of land
\n= 500 m and Breadth of land = 200 m
\nArea of land = length \u00d7 breadth
\n= 500 m \u00d7 200 m = 1,00,000 m2<\/sup>
\nCost of tilling 100 sq. m of land = 8
\n\u2234 Cost of tilling 1,00,000 sq. m of land
\n\\(\\frac{8 \\times 100000}{100}\\) = 8000<\/p>\n

Question 6.
\nA table-top measures 2 m by 1 m 50 cm. What is its area in square metres?
\nAnswer:
\nLength of table = 2 m
\nBreadth of table = 1 m 50 cm = 1.50 m
\nArea of table = length \u00d7 breadth
\n= 2 m \u00d7 1.50 m = 3 m2<\/sup><\/p>\n

\"NCERT<\/p>\n

Question 7.
\nA room is 4 m long and 3 m 50 cm wide. How many square metres of carpet is needed to cover the floor of the room?
\nAnswer:
\nLength of room = 4 m
\nBreadth of room = 3 m 50 cm = 3.50 m
\nArea of carpet = length \u00d7 breadth
\n= 4 \u00d7 3.50= 14 m2<\/sup><\/p>\n

Question 8.
\nA floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.
\nAnswer:
\nLength of floor
\n= 5 m and breadth of floor = 4 m
\nArea of floor = length \u00d7 breadth
\n= 5m \u00d7 4m = 20m2<\/sup>
\nNow, Side of square carpet = 3 m
\nArea of square carpet = side \u00d7 side
\n= 3 \u00d7 3 = 9 m2<\/sup>
\nArea of floor that is not carpeted = 20m2<\/sup> – 9m2<\/sup> = 11m2<\/sup><\/p>\n

Question 9.
\nFive square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?
\nAnswer:
\nSide of square bed = 1 m
\nArea of square bed = side \u00d7 side
\n= 1m \u00d7 1m = 1m2<\/sup>
\n\u2234 Area of 5 square beds = 1 \u00d7 5 = 5 m2<\/sup>
\nNow, Length of land = 5 m
\nBreadth of land = 4 m
\n\u2234 Area of land = length \u00d7 breadth
\n= 5 m \u00d7 4 m = 20 m2<\/sup>
\nArea of remaining part
\n= Area of land – Area of 5 flower beds = 20 m2<\/sup> – 5 m2<\/sup> = 15 m2<\/sup><\/p>\n

\"NCERT<\/p>\n

Question 10.
\nBy splitting the following figures into rectangles, find their areas (The measures are given in centimetres).
\n\"NCERT
\nAnswer:
\n\"NCERT
\nArea of HKLM = 3 \u00d7 3 = 9 cm2<\/sup>
\nArea of IJGH = 1 \u00d7 2 = 2 cm2<\/sup>
\nArea of FEDG = 3 \u00d7 3 = 9 cm2<\/sup>
\nArea of ABCD = 2 \u00d7 4 = 8 cm2<\/sup>
\nTotal area of the figure
\n= 9 + 2 +9 + 8
\n= 28 cm2<\/sup><\/p>\n

\"NCERT
\nArea of ABCD = 3 \u00d7 1 = 3 cm2<\/sup>
\nArea of BDEF = 3 \u00d7 1 = 3 cm2<\/sup>
\nArea of FGHI = 3 \u00d7 1 = 3 cm2<\/sup>
\nTotal area of the figure = 3 + 3 + 3 = 9 cm2<\/sup><\/p>\n

\"NCERT<\/p>\n

Question 11.
\nSplit the following shapes into rectangles and find their areas. (The measures are given in centimetres)
\n\"NCERT
\nAnswer:
\n(a) Area of rectangle ABCD
\n= 2 \u00d7 10 = 20 cm2<\/sup>
\nArea of rectangle DEFG
\n= 10 \u00d7 2 = 20 cm2<\/sup>
\nTotal area of the figure
\n= 20 + 20 = 40 cm2<\/sup>
\n\"NCERT<\/p>\n

(b) There are 5 squares each of side 7 cm.
\nArea of one square
\n= 7 \u00d7 7 = 49 cm2<\/sup>
\nArea of 5 square
\n= 49 \u00d7 5 = 245 cm2
\n\"NCERT<\/p>\n

(c) Area of rectangle ABCD
\n= 5 \u00d7 1 = 5 cm2<\/sup>
\nArea of rectangle EFGH
\n= 4 \u00d7 1 = 4 cm2<\/sup>
\nTotal area of the figure
\n= 5 + 4 cm2<\/sup>
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 12.
\nHow many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:
\n(a) 100 cm and 144 cm
\n(b) 70 cm and 36 cm
\nAnswer:
\n(a) Area of region
\n= 100 cm \u00d7 144 cm = 14400 cm2<\/sup>
\nArea of one tile
\n= 5 cm \u00d7 12 cm = 60 cm2<\/sup>
\nNumber of tiles = \\(\\frac{\\text { Area of region }}{\\text { Area of one tile }}\\) = \\(\\frac{14400}{60}\\) = 240
\nThus, 240 tiles are required.<\/p>\n

(b) Area of region
\n= 70 cm \u00d7 36 cm = 2520 cm2<\/sup>
\nArea of one tile
\n= 5 cm \u00d7 12 cm = 60 cm2<\/sup>
\nNumber of tiles
\n= \\(\\frac{\\text { Area of region }}{\\text { Area of one tile }}\\) = \\(\\frac{2520}{60}\\) = 42
\nThus, 42 tiles are required.<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.3 Question 1. Find the areas of the rectangles whose sides are: (a) 3 cm and 4 cm (b) 12 m and …<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-10-ex-10-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts. 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NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.3 Question 1. 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