{"id":25764,"date":"2021-06-24T09:55:00","date_gmt":"2021-06-24T04:25:00","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=25764"},"modified":"2021-06-24T09:55:00","modified_gmt":"2021-06-24T04:25:00","slug":"ncert-solutions-for-class-9-maths-chapter-10-ex-10-3","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-9-maths-chapter-10-ex-10-3\/","title":{"rendered":"NCERT Solutions for Class 9 Maths Chapter 10 Circles Ex 10.3"},"content":{"rendered":"

These NCERT Solutions for Class 9 Maths<\/a> Chapter 10 Circles Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.3<\/h2>\n

Question 1.
\nDraw different pairs of circles. How many points does each pair have in common? What is the maximum number of common points?
\nSolution:
\nThere are three different pairs of circle.
\n\"NCERT
\nIt is clear that in Fig. I, there is no any common point in pair of circle O and O’.
\nIn Fig. II, there is only one point A is common point in pair of circle P and P’.
\nIn Fig. III, there are two points X and Y are common points in pair of circle Q and Q’.
\nThe maximum number of common points are two.<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nSuppose you are give a circle. Give a construction to find its centre.
\nSolution:
\nTo find the centre of the circle we take following steps:
\n\"NCERT
\nStep (i) – Take three points A, B and Con die circle.
\nStep (ii) – Join AB and AC.
\nStep (iii) – Draw perpendicular bisector of AB and BC.
\nStep (iv) – Both perpendicular bisector intersect each other at point O.
\nStep (v) – Point O is centre of the required circle.
\nRemark: We know that centre lie on perpendicular bisector of chord. Therefore centre must be lie on perpendicular bisector of AB. Again centre also must be lie on perpendicular bisector of BC. Both cases are possible only when centc lie on their point of intersection.<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nIf two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord.
\nSolution:
\nGiven: Two circles O and O’ intersect each other at A and B. AB is a common chord for both circles.
\n\"NCERT
\nTo prove that: OO’ is perpendicular bisector of AB.
\nConstruction: Draw line segments OA, OB, O’A and O’B.
\nProof: In \u2206OAO’ and \u2206OBO’ we have
\nOA = OB (Radii of same circle)
\nO’A = O’B (Radii of same circle)
\nand OO’ = OO’ (Common)
\nSo, by S-S-S congruency condition
\n\u2206OAO’ \u2245 \u2206OBO’
\n\u2234 \u2220AOO’ = \u2220BOO’ (By C.P.C.T)
\nor \u2220AOM = \u2220BOM …..(i)
\nNow, In \u2206AOM and \u2206BOM
\nOA = OB (Radii of samecircle)
\n\u2234 \u2220AOM = \u2220BOM (From (i))
\nOM = OM (Common)
\nSo, by S-A-S congruency condition
\n\u2206AOM \u2245 \u2206BOM
\n\u2234 AM = BM (By CPCT)
\nand \u2220AMO = \u2220BMO (By CPCT)
\nBut, \u2220AMO + \u2220BMO = 180\u00b0 (Liner pair)
\n2\u2220AMO = 180\u00b0 (\u2235 \u2220AMO = \u2220BMO prove above)
\nor, \u2220AMO = 90\u00b0
\nHence, OO’ lie on the perpendicular bisector of AB.<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 9 Maths Chapter 10 Circles Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.3 Question 1. Draw different pairs of circles. How many points does each pair have in common? What is the maximum number …<\/p>\n

NCERT Solutions for Class 9 Maths Chapter 10 Circles Ex 10.3<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6],"tags":[],"yoast_head":"\nNCERT Solutions for Class 9 Maths Chapter 10 Circles Ex 10.3 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-9-maths-chapter-10-ex-10-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 9 Maths Chapter 10 Circles Ex 10.3 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 9 Maths Chapter 10 Circles Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts. 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