{"id":25888,"date":"2021-06-24T13:31:13","date_gmt":"2021-06-24T08:01:13","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=25888"},"modified":"2021-06-24T13:32:32","modified_gmt":"2021-06-24T08:02:32","slug":"ncert-solutions-for-class-6-maths-chapter-8-ex-8-2","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-8-ex-8-2\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2"},"content":{"rendered":"

These\u00a0NCERT Solutions for Class 6 Maths<\/a> Chapter 8 Decimals Ex 8.2 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2<\/h2>\n

Question 1.
\nComplete the table with the help of these boxes and use decimals to write the number.
\n\"NCERT
\nAnswer:
\nExplanation:
\n(a) In this figure,
\nIf small block out of 100 are shaded
\n\u2234 Decimal representation = 0.26
\n(b) 100 small blocks + 38 small blocks are shaded
\n\u2234 \\(\\frac{100}{100}+\\frac{38}{100}=1+\\frac{38}{100}\\) = 1.28
\n1.38 is represented by the shaded portion.
\n(c) 100 parts + 28 parts are shaded
\n1.28 is represented by the shaded portion. Therefore, the table is compiled as :
\n\"\"<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nWrite the numbers given in the following place value table in decimal form.
\n\"NCERT
\nAnswer:
\n(a) 0 x 100 + 0 x 10 + 3 x 1 + 2 x \\(\\frac { 1 }{ 10 }\\) + 5 x 100 + 0 x \\(\\frac { 1 }{ 1000 }\\)
\n= 0 + 0 + 3 +0.2 + 0.05 + 0 = 3.25<\/p>\n

(b) 1 x 100 + 0 x 10 + 2 x 1 + 6 x \\(\\frac { 1 }{ 10 }\\) + 3 x \\(\\frac { 1 }{ 100 }\\) + 0 x \\(\\frac { 1 }{ 1000 }\\)
\n= 1 + 0 + 2 + 0.6 + 0.03 + 0 = 102.63<\/p>\n

(c) 0 x 100 + 3 x 10 + 0 x 1 + 0 x \\(\\frac { 1 }{ 10 }\\) + 2 x \\(\\frac { 1 }{ 100 }\\) + 5 x \\(\\frac { 1 }{ 1000 }\\)
\n= 0 + 30 + 0 + 0 + 0.02 + 0.005
\n= 30.025<\/p>\n

(d) 2 x 100 + 1 x 10 + 1 x 1 + 9 x \\(\\frac { 1 }{ 10 }\\) + O x \\(\\frac { 1 }{ 100 }\\) + 2 x \\(\\frac { 1 }{ 1000 }\\)
\n= 200 + 10 + 1 + 0.9 + 0 + 0.002
\n= 211.902<\/p>\n

(e) 0 x 100 + 1 x 10 + 2 x 1 + 2 x \\(\\frac { 1 }{ 10 }\\) + 4 x \\(\\frac { 1 }{ 100 }\\) + 1 x \\(\\frac { 1 }{ 1000 }\\)
\n= 0 + 10 + 2 + 0.2 + 0.04 + 0.001
\n= 12.241<\/p>\n

Question 3.
\nWrite the following decimals in the place value table:
\n(a) 0.29
\n(b) 2.08
\n(c) 19.60
\n(d) 148.32
\n(e) 200.812
\nAnswer:
\n\"NCERT<\/p>\n

Question 4.
\nWrite each of the following as decimals:
\n(a) 20 + 9 + \\(\\frac{4}{10}+\\frac{1}{100}\\)
\n(b) 137 + \\(\\frac{5}{100}\\)
\n(c) \\(\\frac{7}{10}+\\frac{6}{100}+\\frac{4}{1000}\\)
\n(d) 23 + \\(\\frac{2}{10}+\\frac{6}{1000}\\)
\n(e) 700 + 20 + 5 + \\(\\frac{9}{100}\\)
\nAnswer:
\n(a) 20 + 9 + 0.4 + 0.01 = 29.41
\n(b) 137 + 0.05 = 137.05
\n(c) 0.7 + 0.06 + 0.004 = 0.764
\n(d) 23 + 0.2 + 0.006 = 23.206
\n(e) 700 + 20 + 5 + 0.09 = 725.09<\/p>\n

\"NCERT<\/p>\n

Question 5.
\nWrite each of the following decimals in words:
\n(a) 0.03
\n(b) 1.20
\n(c) 108.56
\n(d) 10.07
\n(e) 0.032
\n(f) 5.008
\nAnswer:
\n(a) Zero point zero three
\n(b) One point two zero
\n(c) One hundred and eight point five six
\n(d) Ten point zero seven
\n(e) Zero point zero three two
\n(f) Five point zero zero eight<\/p>\n

Question 6.
\nBetween which two numbers in tenths place on the number line does each of the given number lie?
\n(a) 0.06
\n(b) 0.45
\n(c) 0.19
\n(d) 0.66
\n(e) 0.92
\n(f) 0.57
\nAnswer:
\nAll the numbers lie between 0 and 1
\n(a) 0.06 is nearer to 0.1.
\n(b) 0.45 is nearer to 0.5.
\n(c) 0.19 is nearer to 0.2.
\n(d) 0.66 is nearer to 0.7.
\n(e) 0.92 is nearer to 0.9.
\n(f) 0.57 is nearer to 0.6.<\/p>\n

\"NCERT<\/p>\n

Question 7.
\nWrite as fractions in lowest terms:
\n(a) 0.60
\n(b) 0.05
\n(c) 0.75
\n(d) 0.18
\n(e) 0.25
\n(f) o .125
\n(g) 0.066
\nAnswer:
\n(a) 0.60 = \\(\\frac{60}{100}=\\frac{3}{5}\\)
\n(b) 0.05 = \\(\\frac{5}{100}=\\frac{1}{20}\\)
\n(c) 0.75 = \\(\\frac{75}{100}=\\frac{3}{4}\\)
\n(d) 0.18 = \\(\\frac{18}{100}=\\frac{9}{50}\\)
\n(e) 0.25 = \\(\\frac{25}{100}=\\frac{1}{4}\\)
\n(f) o .125 = \\(\\frac{125}{1000}=\\frac{1}{8}\\)
\n(g) 0.066 = \\(\\frac{66}{1000}=\\frac{33}{500}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"

These\u00a0NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2 Question 1. Complete the table with the help of these boxes and use decimals to write the number. Answer: Explanation: (a) In …<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-8-ex-8-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These\u00a0NCERT Solutions for Class 6 Maths Chapter 8 Decimals Ex 8.2 Questions and Answers are prepared by our highly skilled subject experts. 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