{"id":25941,"date":"2021-06-24T15:05:58","date_gmt":"2021-06-24T09:35:58","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=25941"},"modified":"2021-06-24T15:05:58","modified_gmt":"2021-06-24T09:35:58","slug":"ncert-solutions-for-class-9-maths-chapter-11-ex-11-2","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-9-maths-chapter-11-ex-11-2\/","title":{"rendered":"NCERT Solutions for Class 9 Maths Chapter 11 Constructions Ex 11.2"},"content":{"rendered":"

These NCERT Solutions for Class 9 Maths<\/a> Chapter 11 Constructions Ex 11.2 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 9 Maths Chapter 11 Constructions Exercise 11.2<\/h2>\n

Question 1.
\nConstruct a triangle ABC in which BC = 7 cm, \u2220B = 75\u00b0 and AB + AC = 13 cm.
\nSolution:
\n\"NCERT
\nSteps of construction:
\nStep-I: Draw the base BC = 7 cm and at point B make an angle say \u2220XBC = 75\u00b0.
\nStep-II: Cut the line segment BD = AB + AC = 13 cm from die ray BX.
\nStep-III: Join DC and draw perpendicular bisector of DC. Which intersect DB at A.
\nStep-IV: Join AC.
\nStep-V: Triangle ABC is the required triangle.<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nConstruct a triangle ABC in which BC = 8 cm, \u2220B = 45\u00b0 and AB – AC = 3.5 cm.
\nSolution:
\n\"NCERT
\nSteps of Construction:
\nStep-I: Draw the base BC = 8 cm and make \u2220XBC = 45\u00b0.
\nStep-II: Cut the Sine segment BD = AB – AC = 3.5 cm from ray BX.
\nStep-III: Join DC and draw the perpendicular bisector of DC.
\nStep-IV: Let the perpendicular bisector of DC intersect XB at A.
\nStep-V: Join AC.
\nStep-VI: Triangle ABC is the required triangle.<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nConstruct a triangle PQR in which QR = 6 m, \u2220Q = 60\u00b0 and PR – PQ = 2 cm.
\nSolution:
\n\"NCERT
\nSteps of Construction:
\nStep-I: Draw the base QR = 6 cm and at point Q make an angle \u2220XQR = 60\u00b0.
\nStep-II: Cutline segment QM = PR – PQ = 2 cm from the line XQ extended on the opposite side of line segment QR.
\nStep-III: Join MC and draw the perpendicular bisector of MR which intersect XQ at P.
\nStep-IV: Join PR.
\nStep-V: Triangle PQR is the required triangle.<\/p>\n

\"NCERT<\/p>\n

Question 4.
\nConstruct a triangle XYZ in which \u2220Y = 30\u00b0, \u2220Z = 90\u00b0 and XY + YZ + ZX = 11 cm.
\nSolution:
\n\"NCERT
\nSteps of Construction:
\nStep-I: Draw the line segment PQ = 11 cm. (= XY + YZ + ZX)
\nStep-II: At P construct an angle of 30\u00b0 and at Q, an angle of 90\u00b0.
\nStep-III: Bisect these angles. Let the bisector of these angles intersect at a point X.
\nStep-IV: Draw perpendicular bisectors of XP and XQ which intersect PQ at Y and Z respectively.
\nStep-V: Join XY and XZ.
\nStep-VI: Triangle XYZ is the required triangle.<\/p>\n

\"NCERT<\/p>\n

Question 5.
\nConstruct a right triangle whose base is 12 cm and the sum of its hypotenuse and other side is 18 cm.
\nSolution:
\n\"NCERT
\nSteps of Construction:
\nStep-I: Draw the base BC = 12 cm and at a point B makes an angle say \u2220XBC = 90\u00b0.
\nStep-II: Cut the line segment BD = 18 cm (= AB + AC).
\nStep-III: Join DC and make a \u2220DCY = \u2220BDC.
\nStep-IV: CY intersect BX at A.
\nStep-V: Join AC.
\nStep-VI: Triangle ABC is the required triangle.<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 9 Maths Chapter 11 Constructions Ex 11.2 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 9 Maths Chapter 11 Constructions Exercise 11.2 Question 1. Construct a triangle ABC in which BC = 7 cm, \u2220B = 75\u00b0 and AB + AC = 13 …<\/p>\n

NCERT Solutions for Class 9 Maths Chapter 11 Constructions Ex 11.2<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6],"tags":[],"yoast_head":"\nNCERT Solutions for Class 9 Maths Chapter 11 Constructions Ex 11.2 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-9-maths-chapter-11-ex-11-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 9 Maths Chapter 11 Constructions Ex 11.2 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 9 Maths Chapter 11 Constructions Ex 11.2 Questions and Answers are prepared by our highly skilled subject experts. 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