{"id":26113,"date":"2021-06-25T10:17:48","date_gmt":"2021-06-25T04:47:48","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=26113"},"modified":"2021-06-25T10:17:48","modified_gmt":"2021-06-25T04:47:48","slug":"ncert-solutions-for-class-6-maths-chapter-7-ex-7-6","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-7-ex-7-6\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6"},"content":{"rendered":"

These\u00a0NCERT Solutions for Class 6 Maths<\/a> Chapter 7 Fractions Ex 7.6 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.6<\/h2>\n

Question 1.
\nSolve
\n\"NCERT
\nAnswer:
\nIn these questions, the denominator is different, so we cannot simply add the numerator. We have to first find the LCM of the denominators and then convert each fraction into that form and then do numerators addition or subtraction.
\n\"NCERT
\n\"NCERT
\n\"NCERT
\n\"NCERT
\n\"NCERT
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nSarita bought \\(\\frac { 2 }{ 5 }\\) metre of ribbon and Lalita \\(\\frac { 3 }{ 4 }\\) metre of ribbon. What is the total length of the ribbon they bought?
\nAnswer:
\nLength of ribbon Saria bought = \\(\\frac { 2 }{ 5 }\\) metre
\nLength of ribbon Lalita bought = \\(\\frac { 3 }{ 4 }\\) metre
\nTotal length of ribbon = \\(\\frac{2}{5}+\\frac{3}{4}\\)
\nThey bought \\(\\frac{23}{20}\\) meters of ribbon together.<\/p>\n

Question 3.
\nNaina was given 1\\(\\frac { 1 }{ 2 }\\) piece of cake and Najma was given 1\\(\\frac { 1 }{ 3 }\\) piece of cake.
\nFind the total amount of cake was given to both of them.
\nAnswer:
\nTotal amount of cake both have
\n= \\(1 \\frac{1}{2}+1 \\frac{1}{3}\\)
\nThis is mixed fraction, converting into improper traction = \\(\\frac{3}{2}+\\frac{4}{3}=\\frac{17}{6}\\)
\nSo, they total have \\(\\frac{17}{6}\\) pieces of cake.<\/p>\n

Question 4.
\nFill in the boxes:
\n\"NCERT
\nAnswer:
\n\"NCERT<\/p>\n

Question 5.
\nComplete the addition-subtraction box.
\nAnswer:
\n\"NCERT<\/p>\n

Question 6.
\nA piece of wire \\(\\frac { 7 }{ 8 }\\) metre long broke into two pieces. One piece was \\(\\frac { 1 }{ 4 }\\) metre long.
\nHow long is the other piece?
\nAnswer:
\nLength of the piece of wire is = \\(\\frac { 7 }{ 8 }\\) meter
\nLength of one broken piece is = \\(\\frac { 1 }{ 4 }\\) meter
\nLength of the other broken piece = total length of the wire – length of one broken piece
\n= \\(\\frac{7}{8}-\\frac{1}{4}=\\frac{5}{8}\\) m
\nLength of the piece of wire is \\(\\frac{5}{8}\\) metre.<\/p>\n

\"NCERT<\/p>\n

Question 7.
\nNandini\u2019s house is \\(\\frac { 9 }{ 10 }\\) km from her school. She walked some distance and
\nthen took a bus for \\(\\frac { 1 }{ 2 }\\) km to reach the school. How far did she walk?
\nAnswer:
\nDistance from Nandini\u2019s house to school = \\(\\frac { 9 }{ 10 }\\) km 10
\nDistance covered by bus = \\(\\frac { 1 }{ 2 }\\) km
\nDistance she walked = distance from house to school – distance she covered by bus.
\n= \\(\\frac{9}{10}-\\frac{1}{2}=\\frac{4}{10}=\\frac{2}{5}\\) km
\n\u2234 Distance walked by Nandhini = \\(\\frac{2}{5}\\) km.<\/p>\n

Question 8.
\nAsha and Samuel have bookshelves of the same size partly filled with books.
\nAsha\u2019s shelf is \\(\\frac{5}{6}\\) th full and Samuel\u2019s shelf is \\(\\frac{2}{5}\\) th full. Whose bookshelf is more full? By what fraction?
\nAnswer:
\nFraction of books in Asha\u2019s shelf = \\(\\frac{5}{6}\\)
\nFraction of books in Samuel\u2019s shelf = \\(\\frac{2}{5}\\)
\nWe compare the fractions to find whose shelf is more full.
\nSince these are unlike fraction, we need to first find the LCM of 5 and 6 which is 30
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 9.
\nJaidev takes 2\\(\\frac{1}{5}\\) minutes to walk across the school ground. Rahul takes \\(\\frac{7}{4}\\) minutes to do the same. Who takes less time and by what fraction?
\nAnswer:
\nTime taken by Jaidev to walk across the ground = \\(\\frac{1}{5}\\) min
\nTime taken by Rahul to walk across the ground = \\(\\frac{7}{4}\\) min
\nWe compare the fractions to find who takes is less time
\nSince these are unlike fraction, we need to first find the LCM of 5 and 4 which is 20 11 44
\n\"NCERT
\nSo, Rahul takes lesser time than Jaidev.
\nDifference = \\(\\frac{11}{5}-\\frac{7}{4}=\\frac{9}{20}\\)
\nSo, Rahul takes lesser time than Jaidev, by \\(\\frac{9}{20}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"

These\u00a0NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.6 Question 1. Solve Answer: In these questions, the denominator is different, so we cannot simply add the numerator. We have to first …<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-6-maths-chapter-7-ex-7-6\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These\u00a0NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6 Questions and Answers are prepared by our highly skilled subject experts. 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