{"id":26289,"date":"2021-06-25T15:11:07","date_gmt":"2021-06-25T09:41:07","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=26289"},"modified":"2021-06-25T15:11:07","modified_gmt":"2021-06-25T09:41:07","slug":"ncert-solutions-for-class-7-maths-chapter-1-intext-questions","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-7-maths-chapter-1-intext-questions\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 1 Integers InText Questions"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 1 Integers InText Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 1 Integers InText Questions<\/h2>\n

NCERT In-text Question Page No. 2<\/span>
\nQuestion 1.
\nA number line representing integers is given below:
\n\"NCERT
\n-3 and -2 are marked by E and F respectively. Which integers are marked by B, D, H, J, M and O?
\nAnswer:
\nLet us complete the given number line such that integers marked by various alphabets are shown
\n\"NCERT
\nThe integer marked by B = -6
\nThe integer marked by D = -4
\nThe integer marked by H = 0
\nThe integer marked by J = 2
\nThe integer marked by M = 5
\nThe integer marked by O = 7<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nArrange 7, -5, 4, 0 and -4 in ascending order and then mark them on a number line to check your answer.
\nAnswer:
\n(i) Since every positive integer is greater than 0.
\n(ii) every negative integer is less than 0
\n-5 < (-4) < 0 < 4 < 7
\nascending order is : -5, -4, 0, 4, 7
\n\"NCERT<\/p>\n

NCERT In-text Question Page No. 3<\/span>
\nQuestion 1.
\nWe have have done various patterns with numbers in our previous class. Can you find a pattern for each of the following? If yes, complete them.
\n(a) 7, 3, -1, -5, -9<\/span>, -13<\/span>, -17<\/span>
\n(b) -2, -4, -6, -8, -10<\/span>, -12<\/span>, -14<\/span>
\n(c) 15, 10, 5, 0, -5, -10,<\/span> -15<\/span>
\n(d) -11,-8, -5, -2, 1<\/span>, 4<\/span>, 7<\/span><\/p>\n

NCERT In-text Question Page No. 8<\/span>
\nQuestion 1.
\nWrite a pair of integers whose sum gives
\n(a) a negative integer
\n(b) zero
\n(c) an integer smaller than both the integer.
\n(d) an integer smaller than only one of the integers.
\n(e) an integer greater than both the integers.
\nAnswer:
\n(a) -7 and 2
\nsum = -7 + 2 = -5 (negative integer)<\/p>\n

(b) -13 and 13
\nsum = -13 + 13 = 0<\/p>\n

(c) – 13 and (- 7)
\nsum = – 13 + (-7) = – 13 – 7 = -20
\n(- 20 is smaller than – 13 and (-7))<\/p>\n

(d) 7 and -5
\nsum = 7 + (-5) = 7 – 5 = 2
\n(2 is smaller than 7 only)<\/p>\n

(e) 19 and 21
\nsum = 19 + 21 = 40
\n(40 is greater than both 19 and 21)<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nWrite a pair of integers whose difference gives
\n(a) a negative integer.
\n(b) zero
\n(c) an integer smaller than both the integers.
\n(d) an integer greater than only one of the integers.
\n(e) an integer greater than both the integers.
\nAnswer:
\n(a) 7 and -12
\nDifference = – 12 – (7) = -12 -7
\n= -19 (is a negative integer)<\/p>\n

(b) (-3) and (-3)
\nDifference = -3 – (-3) = – 3 + 3 = 0<\/p>\n

(c) 5 and 9 Difference = 9 – 5
\n= 4 (4 is smaller than 9 as well as 5)<\/p>\n

(d) 16 and 5 Difference =16 – 5
\n= 11 (11 is greater than 5)<\/p>\n

(e) 15 and-6
\nDifference = 15 – (-6) = 15 + 6
\n= 21 (21 is greater than 15 as well as -6)<\/p>\n

NCERT Index Question Page No. 10<\/span>
\nQuestion 1.
\nUsing number line, find:
\n(i) 4 \u00d7 (-8)
\n(ii) 8 (-2)
\n(iii) 3 \u00d7 (-7)
\n(iv) 10 \u00d7 (-1)
\nAnswer:
\n(i) 4 \u00d7 (-8)
\n\"NCERT
\nFrom the number line, we have:
\n(- 8) + (-8) + (-8) + (-8) = -32
\n\u2234 4 \u00d7 (-8) = -32<\/p>\n

(ii) 8 \u00d7 (-2)
\n\"NCERT
\nFrom the number line, we have:
\n(-2) + (-2) + (-2) + (-2) + (-2) + (-2) + (-2) + (-2) = -16
\n\u2234 8 \u00d7 (-2) = -16<\/p>\n

(iii) 3 \u00d7 (-7)
\n\"NCERT
\nFrom the number line, we have:
\n(-7) + (-7) + (-7) = -21
\n3 \u00d7 (-7) = -21<\/p>\n

(iv) 10 \u00d7 (-1)
\n\"NCERT
\nFrom the number line, we have:
\n(-1) + (-1) + (-1) + (-1) + ( -1) + ( -1) + (-1) + ( -1) + (-1) + (-1) = -10
\n\u2234 10 \u00d7 (-1) =-10<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 10<\/span>
\nQuestion 1.
\nFind:
\n(i) 6 \u00d7 (-19)
\n(ii) 12 \u00d7 (-32)
\n(iii) 7 \u00d7 (-22)
\nAnswer:
\n(i) 6 \u00d7 (-19)= – (6 \u00d7 19)
\n= -(114) = -114<\/p>\n

(ii) 12 \u00d7 (-32) = – (12 \u00d7 32)
\n= -(384) = -384<\/p>\n

(iii) 7 \u00d7 (-22) = – (7 \u00d7 22)
\n= -(154) = – 154<\/p>\n

NCERT In-text Question Page No. 11<\/span>
\nQuestion 1.
\nFind:
\n(a) 15 \u00d7 (-16)
\n(b) 21 \u00d7 (- 32)
\n(c) (-42) \u00d7 12
\n(d) (-55) \u00d7 15
\nAnswer:
\n(a) 15 \u00d7 (-16) = -(15 \u00d7 16) = -[240] = -240
\n(b) 21 \u00d7 (-32) = -(21 \u00d7 32) = -[672] = -672
\n(c) (-42) \u00d7 12 = -(42 \u00d7 12) = -[504] = -504
\n(d) (-55) \u00d7 15 = -(55 \u00d7 15) = -[825] = -825<\/p>\n

Question 2.
\nCheck if
\n(a) 25 \u00d7 (-21) = (-25) \u00d7 21.
\n(b) (-23) \u00d7 20 = 23 \u00d7 (-20).
\nWrite five more such examples.
\nAnswer:
\n(a) L.H.S.= 25 \u00d7 (-21) – (25 \u00d7 21)
\n= – [525] = -525
\nR.H.S.= (-25) \u00d7 21 = – [25 \u00d7 21]
\n= – [525] = -525
\n\u2235 L.H.S.= R.H.S.
\n\u2234 25 \u00d7 (-21)= (-25) \u00d7 21<\/p>\n

(b) L.H.S.= (-23) \u00d7 20 = – [23 \u00d7 20]
\n= – [460] = -460
\nR.H.S.= 23 \u00d7 (-20) = – [23 \u00d7 20]
\n= – [460] = – 460
\n\u2235 L.H.S.= R.H.S.
\n\u2234 (-23) \u00d7 20= 23 \u00d7 (-20)<\/p>\n

Other examples:
\n(i) (-9) \u00d7 18 = 9 \u00d7 (-18)
\n(ii) 51 \u00d7 (-40)= (-51) \u00d7 40
\n(iii) (-12) = (-51) \u00d7 40
\n(iv) (-20) \u00d7 25= 20 \u00d7 (-25)
\n(v) 16 \u00d7 (-15) = (-16) \u00d7 15<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 12<\/span>
\nQuestion 1.
\n(i) Starting from (-5) \u00d7 4, find (-5) \u00d7 (-6)
\n(ii) Starting from (-6) \u00d7 3, find (-6) \u00d7 (-7)
\nAnswer:
\n(i) Look at the following pattern:
\n(-5) \u00d7 4 = – [5 \u00d7 4] = -20
\n(-5) \u00d7 3 = – [5 \u00d7 3] = -15 = -20 + 5
\n(-5) \u00d7 2 = – [5 \u00d7 2] = -10 = -15 + 5
\n(-5) \u00d7 1 = – [5 \u00d7 1] = -5 = -10 + 5
\n(-5) \u00d7 0 = – [5 \u00d7 0] = 0 = -5 + 5<\/p>\n

From this pattern, we have:
\n(-5) \u00d7 (-l) = 0 + 5 = 5
\n(-5) \u00d7 (-2) = 5 + 5 = 10
\n(-5) \u00d7 (-3) = 10 + 5 = 15
\n(-5) \u00d7 (-4) = 15 + 5 = 20
\n(-5) \u00d7 (-5) = 20 + 5 = 25
\n(-5) \u00d7 (-6) = 25 + 5 = 30
\nThus, (-5) \u00d7 (-6) = 30<\/p>\n

(ii) Look at the following pattern:
\n-6 \u00d7 3 = – [6 \u00d7 3] = – 18
\n-6 \u00d7 2 = – 12 = – 18 + 6
\n-6 \u00d7 1 = -6 = – 12 + 6
\n-6 \u00d7 0 = 0 = -6 + 6
\nFrom this pattern, we have:
\n-6 \u00d7 (-1) = 0 + 6 = 5
\n-6 \u00d7 (-2) = 6 + 6= 12
\n-6 \u00d7 (-3) = 12 + 6= 18
\n-6 \u00d7 (-4) = 18 + 6 = 24
\n-6 \u00d7 (-5) = 24 + 6 = 30
\n-6 \u00d7 (-6) = 30 + 6 = 36
\n-6 \u00d7 (-7) = 36 + 6 = 42
\nThus, (-6) \u00d7 (-7) = 42<\/p>\n

NCERT In-text Question Page No. 12<\/span>
\nQuestion 1.
\n(i) Find: (-31) \u00d7 (-100), (-25) \u00d7 (-72), (-83) \u00d7 (-28)
\nAnswer:
\nWe multiply the two negative integers as whole numbers and put the positive sign (+) before the product.
\n(-31) \u00d7 (-100) = + [31 \u00d7 100] = + [3100] = 3100
\n(-25) \u00d7 (-72) = + [25 \u00d7 72] = + [1800] = 1800
\n(-83) \u00d7 (-28) = + [83 \u00d7 28] = + [2324] = 2324<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 14<\/span>
\nQuestion 1.
\n(i) The product (-9) \u00d7 (-5) \u00d7 (-6) \u00d7 (-3) is positive whereas the product (-9) \u00d7 (-5) \u00d7 6 \u00d7 (-3) is negative. Why?
\n(ii) What will be the sign of the product if we multiply together:
\n(a) 8 negative integers and 3 positive integers?
\n(b) 5 negative integers and 4 positive integers?
\n(c) (-1), twelve timers?
\n(d) (-1), 2m times, m is a natural number?
\nAnswer:
\nWe know that, if the number of negative integers in a product is even, then the product is a positive integer; if the number of negative integers in a product is odd, then the product is a negative integer.<\/p>\n

\u2234 (i) The product (-9) \u00d7 (-5) \u00d7 (-6) \u00d7 (-3) is positive because an even number of negative integers are multiplied.
\nThe product (-9) \u00d7 (-5) \u00d7 6 \u00d7 (-3) is negative because an odd number of negative integers are multiplied.<\/p>\n

(ii) (a) Positive [ \u2235 Product of 8 negative integers is positive]
\n(b) Negative [ \u2235 Product of 5 negative integers is positive]
\n(c) Positive [ \u2235 12 even and product of even number of negative]
\n(d) Positive [ \u2235 2m is an even number]<\/p>\n

NCERT In-text Question Page No. 18<\/span>
\nQuestion 1.
\n(i) Is 10 \u00d7 [(6 + (-2)] = 10 \u00d7 6 + 10 \u00d7 (-2)?
\n(ii) Is (-15) \u00d7 [(-7 + (-1)] = (-15) \u00d7 (-7) + (-15) \u00d7 (-1)?
\nAnswer:
\n(i) Yes, [ \u2235 a \u00d7 (b + c) = a \u00d7 b + a \u00d7 c]
\n10 \u00d7 [6 + (-2) = 10 \u00d7 [6 – 2]
\n= 10 \u00d7 4 = 40
\nAnd, 10 \u00d7 6 + 10 \u00d7 (-2) = 60 – 20 = 40.
\nThus, 10 \u00d7 [6 + (-2) = 10 \u00d7 6 + 10 \u00d7 (-2)<\/p>\n

(ii) Yes, [ v a \u00d7 (b + c) = a \u00d7 b + a \u00d7 c]
\n(-15) \u00d7 [(-7 + (-1)] = (-15) \u00d7 [-7 -1]
\n= (-15) \u00d7 (-8)
\n= (+) (15 \u00d7 8)
\n= 120.
\nAnd, (-15) \u00d7 (-7) + (-15) \u00d7 (-1)
\n= (+) (15 \u00d7 7) + (+) (15 \u00d7 1)
\n= 105 + 15 = 120.
\nThus, (-15) \u00d7 [(-7) + (-1)]<\/p>\n

\"NCERT<\/p>\n

Question 2.
\n(i) Is 10 \u00d7 [6 – (-2)] = 10 \u00d7 6 – 10 \u00d7 (-2)?
\n(ii) Is (- 15) \u00d7 [(-7) – (- 1)]
\n= (-15) \u00d7 (-7) – (-15) \u00d7 (-1)?
\nAnswer:
\n(i) L.H.S = 10 \u00d7 [6 – (-2)]
\n= 10 \u00d7 [6 + 2] = 10 \u00d7 8 = 80
\nR.H.S = 10 \u00d7 6 – 10 \u00d7 (- 2)
\n= 60 – (-20) = 60 + 20 = 80
\n\u2234 L.H.S = R.H.S<\/p>\n

(ii) L.H.S = (-15) \u00d7 [(-7) – (- 1)]
\n= (-15) \u00d7 [-7 + 1]
\n= (-15) \u00d7 (- 6) = 90
\nR.H.S = (-15) \u00d7 (-7) – (-15) \u00d7 (- 1)
\n= 105 – (15) = 105 – 15 = 90
\n\u2234 L.H.S = R.H.S<\/p>\n

NCERT In-text Question Page No. 19<\/span>
\nQuestion 1.
\nBy using distributive property, find: (-49) \u00d7 18; (-25) \u00d7 (-31); 70 \u00d7 (-19) + (-1) \u00d7 70.
\nAnswer:
\n(i) (-49) \u00d7 18
\n\u2235 18 = 10 + 8
\n\u2234 (-49) \u00d7 18
\n= (-49) \u00d7 [10 + 8]
\n= (-49) \u00d7 10 + [-49) \u00d7 8
\n[using distributivity]
\n= -490 + (-49) [10 – 2] [\u2235 8 = 10 – 2]
\n= -490 + (-49) \u00d7 10 – (-49) \u00d7 2
\n= -490 +(-490)+ 98
\n= -980 + 98 = -882<\/p>\n

(ii) (-25) \u00d7 (-31)
\nv -31 = (-30) + (-1)
\n.-. (-25) \u00d7 (-31)
\n= (-25) \u00d7 (-30) + (-1)]
\n= (- 5) \u00d7 (-30) + (-25) \u00d7 (-1)
\n[using distributivity] = + (25 \u00d7 30) + ((25 \u00d7 1)]
\n= 750 + 25 = 775<\/p>\n

(iii) 70 \u00d7 (-19) + (-1) \u00d7 70:
\nY a \u00d7 b + a \u00d7 c = a \u00d7 [b + c]
\n70 \u00d7 (-19) + (-1) \u00d7 70
\n70 \u00d7 [(-19) + (-1)] = 70 \u00d7 [-20]
\n-[70 \u00d7 20] = -1400<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 22<\/span>
\nQuestion 1.
\nFind:
\n(a) (-100)+ 5
\n(b) (-81) + 9
\n(c) (-75) + 5
\n(d) (-32) + 2
\nAnswer:
\n(a) (-100) + 5 = -(100 + 5) = -(20) = -20
\n(b) (-81) + 9 = -(81 + 9) = -(9) = -9
\n(c) (-75) + 5 = -(75 + 5) = -(15) = -15
\n(d) (-32) + 2 = -(32 + 2) = -(16) = -16<\/p>\n

NCERT In-text Question Page No. 23<\/span>
\nQuestion 1.
\nFind:
\n(a) 125 \u00f7 (-25)
\n(b) 80 \u00f7 (-5)
\n(c) 64 \u00f7 + (-16)
\nAnswer:
\nWe know that to divide a positive integer by a negative integer, we first divide them as whole numbers and them put a minus sign (-) before the quotient.
\n(a) \u2235 125 \u00f7 25 = 5<\/p>\n

(b) \u2235 80 \u00f7 5 = 16
\n\u2234 125 \u00f7 (-25) = -5
\n\u2234 80 \u00f7 (-5) = -16<\/p>\n

(c) \u2235 64 \u00f7 16 = 4
\n\u2234 64 \u00f7 (-16) = -4<\/p>\n

NCERT In-text Question Page No. 23<\/span>
\nQuestion 1.
\nFind:
\n(a) (-36) \u00f7 (-4)
\n(b) (-201) \u00f7 (-3)
\n(c) (-325) \u00f7 (-13)
\nAnswer:
\nTo divide a negative integer by a negative integer, we first divide them as whole numbers and them put a positive sign (+) before the quotient.
\n(a) \u2235 36 \u00f7 4 = 9
\n\u2234 (-36) \u00f7 (-4) = 9<\/p>\n

(b) \u2235 201 \u00f7 3 = 67
\n\u2234 (-201) \u00f7 (-3) = 67<\/p>\n

(c) \u2235 325 \u00f7 13 = 25
\n\u2234 (-325) \u00f7 (-13) = 25<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 24<\/span>
\nQuestion 1.
\nIs (i) 1 \u00f7 a = 1 and (ii) a \u00f7 (-1) = -a for any integer a? Take different values of a and check.
\nAnswer:
\n(i) Let us take a = -1, 1, 2, 3,…
\nFor a = -1,
\nL.H.S. = 1 \u00f7 (-1) =-l [ \u2235 1 \u00f7 1 = 1]
\nR.H.S. = 1
\ni. e. L.H.S. \u2260 R.H.S.
\nFor a = 2,
\nL.H.S. = 1 \u00f7 a = 1 \u00f7 2 = \\(\\frac { 1 }{ 2 }\\) \u2260 R.H.S.
\nFor a = 3,
\nL.H.S. = 1 \u00f7 a = 1 \u00f7 3 = \\(\\frac { 1 }{ 3 }\\) \u2260 R.H.S.
\nThus, 1 \u00f7 a = 1 is true only for a = 1<\/p>\n

(ii) Let us take a = 1,2,3,…
\nFor a = 1,
\nL.H.S. = a \u00f7 (-1) = 1 \u00f7 (-1) = -2
\nR.H.S. = -a = -1
\ni.e. L.H.S. = R.H.S.
\nFor a = 2,
\nL.H.S. = a \u00f7 (-1) = 2 \u00f7 (-1) = -2
\nR.H.S. = a = -2
\ni.e. L.H.S. = R.H.S.
\nFor a = 7,
\nL.H.S. = a \u00f7 (-1) = 3 \u00f7 (-1) = -3
\nR.H.S. = -a = -3
\ni.e. L.H.S. = R.H.S.
\nFor a = 7,
\nL.H.S. = a \u00f7 (-1) = 7 + (-1) = -7
\nR.H.S. = -a = -7
\ni.e. L.H.S. = R.H.S.
\ni..e. For every integer, we have a \u00f7 (-1) = -a<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 1 Integers InText Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 1 Integers InText Questions NCERT In-text Question Page No. 2 Question 1. A number line representing integers is given below: -3 and -2 are marked by …<\/p>\n

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