{"id":26378,"date":"2021-06-25T17:38:51","date_gmt":"2021-06-25T12:08:51","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=26378"},"modified":"2021-06-25T17:38:51","modified_gmt":"2021-06-25T12:08:51","slug":"ncert-solutions-for-class-7-maths-chapter-2-ex-2-1","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-7-maths-chapter-2-ex-2-1\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 2 Fractions and Decimals Ex 2.1 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.1<\/h2>\n

Question 1.
\n\"NCERT
\nAnswer:
\n\"NCERT
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 2.
\n(i) \\(\\frac{2}{9}, \\frac{2}{3}, \\frac{8}{21}\\)
\n(ii) \\(\\frac{1}{5}, \\frac{3}{7}, \\frac{7}{10}\\)
\nAnswer:
\n(i) \\(\\frac{2}{9}, \\frac{2}{3}, \\frac{8}{21}\\)
\nL.C.M of 9, 3 and 21 = 63
\n\"NCERT
\n\u2234 The descending order is \\(\\frac{2}{3}, \\frac{8}{21}, \\frac{2}{9}\\)<\/p>\n

(ii) \\(\\frac{1}{5}, \\frac{3}{7}, \\frac{7}{10}\\)
\nL.C.M of 5, 7 and 10 = 70
\n\"NCERT
\n\u2234 The descending order is \\(\\frac{7}{10}, \\frac{3}{7}, \\frac{1}{5}\\)<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nIn a \u2018magic square the sum of the numbers in each row, in each column
\nand along the diagonals is the same. Is this a magic square?<\/p>\n\n\n\n\n\n
\\(\\frac{4}{11}\\)<\/td>\n\\(\\frac{9}{11}\\)<\/td>\n\\(\\frac{2}{11}\\)<\/td>\n<\/tr>\n
\\(\\frac{3}{11}\\)<\/td>\n\\(\\frac{5}{11}\\)<\/td>\n\\(\\frac{7}{11}\\)<\/td>\n<\/tr>\n
\\(\\frac{8}{11}\\)<\/td>\n\\(\\frac{1}{11}\\)<\/td>\n\\(\\frac{6}{11}\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

(Along the first row \\(\\frac{4}{11}+\\frac{9}{11}+\\frac{2}{11}=\\frac{15}{11}\\))
\nAnswer:
\nSum of numbers along the
\n1st<\/sup>row = \\(\\frac{4}{11}+\\frac{9}{11}+\\frac{2}{11}\\) = \\(\\frac{4+9+2}{11}\\)
\n\\(\\frac{15}{11}\\)
\n\"NCERT
\nSince, the sum of numbers in each case is the same therefore, it is a magic square.<\/p>\n

\"NCERT<\/p>\n

Question 4.
\nA rectangular sheet of paper is 12\\(\\frac{1}{2}\\) cm long and 10\\(\\frac{2}{3}\\) cm wide. Find its perimeter.
\nAnswer:
\nLength of a rectangle = 12\\(\\frac{1}{2}\\) cm = \\(\\frac{25}{2}\\) cm
\nWidth of a rectangle = 10\\(\\frac{2}{3}\\)cm = \\(\\frac{32}{3}\\) cm
\nPerimeter of a rectangle = 2 (length + breadth)
\n\"NCERT<\/p>\n

Question 5.
\nFind the perimeters of (i) \u0394ABE (ii) the rectangle BCDE in this figure. Whose perimeter is greater?
\n\"NCERT
\nAnswer:
\n(i) Perimeter of \u0394ABE = AB + BE + AE
\n\"NCERT<\/p>\n

(ii) Perimeter of rectangle BCDE
\n= 2 [length + breadth]
\n= 2 [CD + DE]
\n\"NCERT
\n\"NCERT
\nThus, the perimeter of \u0394ABE is greater.<\/p>\n

\"NCERT<\/p>\n

Question 6.
\nSalil wants to put a picture in a frame. The picture is 7\\(\\frac { 3 }{ 5 }\\) cm wide. To fit in the frame the picture cannot be more than 7\\(\\frac { 3 }{ 10 }\\) cm wide. How much should the picture be trimmed?
\nAnswer:
\nWidth of the picture = 7\\(\\frac { 3 }{ 5 }\\)cm
\n\\(\\frac { 38 }{ 5 }\\)cm
\nRequired width of the picture
\n= 7\\(\\frac { 3 }{ 10 }\\) cm = \\(\\frac { 73 }{ 10 }\\) cm
\nThe picture should be trimmed by
\n\"NCERT
\nThe picture should be trimmed by \\(\\frac { 3 }{ 10 }\\) cm.<\/p>\n

Question 7.
\nRitu ate \\(\\frac { 3 }{ 5 }\\) part of an apple and the remaining apple was eaten by her brother Somu. How much part of the apple did Somu eat? Who had the larger share? By how much?
\nAnswer:
\nRitu ate \\(\\frac { 3 }{ 5 }\\) part of an apple, therefore part of the apple ate by Somu = 1 – \\(\\frac { 3 }{ 5 }\\)
\n= \\(\\frac{5-3}{5}=\\frac{2}{5}\\)
\n\\(\\frac{3}{5}>\\frac{2}{5}\\)
\n\u2234 Ritu had the larger share by = \\(\\frac{3}{5}-\\frac{2}{5}\\)
\n= \\(\\frac{3-2}{5}=\\frac{1}{5}\\)
\nThus, Ritu had the larger share by \\(\\frac{1}{5}\\) part of an apple.<\/p>\n

\"NCERT<\/p>\n

Question 8.
\nMichael finished colouring a picture in \\(\\frac{7}{12}\\) hour. Vaibhav finished colouring the
\nsame picture in \\(\\frac{3}{4}\\) hour. Who worked longer? By what fraction was it longer?
\nAnswer:
\nTime taken by Michael = \\(\\frac{7}{12}\\) hour
\nTime taken by Vaibhav = \\(\\frac{3}{4}\\) hour.
\n\"NCERT
\nThus, Vaibhav worked longer by \\(\\frac{1}{6}\\) hour.<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.1 Question 1. Answer: Question 2. (i) (ii) Answer: (i) L.C.M of 9, 3 and 21 = 63 …<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-7-maths-chapter-2-ex-2-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 Questions and Answers are prepared by our highly skilled subject experts. 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