{"id":26648,"date":"2021-06-26T14:24:01","date_gmt":"2021-06-26T08:54:01","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=26648"},"modified":"2021-06-26T14:24:01","modified_gmt":"2021-06-26T08:54:01","slug":"ncert-solutions-for-class-7-maths-chapter-2-ex-2-5","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-7-maths-chapter-2-ex-2-5\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 2 Fractions and Decimals Ex 2.5 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.5<\/h2>\n

Question 1.
\nWhich is greater?
\n(i) 0.5 or 0.05
\n(ii) 0.7 or 0.5
\n(iii) 7 or 0.7
\n(iv) 1.37 or 1.49
\n(v) 2.03 or 2.30
\n(vi) 0.8 or 0.88
\nAnswer:
\n(i) Comparing the digits at tenths place, we have
\n5 > 0
\n\u2234 0.5 >0.05
\nSo, 0.5 is greater.<\/p>\n

(ii) Comparing the digits at tenths places, we have
\n7 > 5
\n\u2234 0.7 > 0.5
\nSo, 0.7 is greater.<\/p>\n

(iii) Comparing the digits at ones place, we have
\n7 > 0
\n\u2234 7 > 0.7
\nSo, 7 is greater.<\/p>\n

(iv) Since the digits at ones place are same, comparing the digits at tenths place, we have
\n3 < 4
\n\u2234 1.37 <1.49
\nSo, 1.49 is greater.<\/p>\n

(v) Since the digits at ones place are same, comparing the digits at tenths place, we have
\n0 < 3
\n\u2234 2. 03 < 2.30
\nSo, 2.30 is greater.<\/p>\n

(vi) 0.8 can be written as 0.80. Now, digits at tenths place are same, comparing the digits at hundredths place, we have
\n0 < 8
\n\u2234 0.80 <0.88
\nSo, 0.88 is greater.<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nExpress as rupees using decimals:
\n(i) 7 paise
\n(ii) 7 rupees 7 paise
\n(iii) 77 rupees 77 paise
\n(iv) 50 paise
\n(v) 235 paise.
\nAnswer:
\n(i) 7 paise = \u20b9 = 7 \u00d7 \\(\\frac{1}{100}=\\frac{7}{100}\\) = \u20b9 0.07<\/p>\n

(ii) rupees 7 paise = \u20b9 = 7 + 7 \u00d7 \\(\\frac{1}{100}\\)
\n= \u20b9 7 + \u20b9 0.07 = \u20b9 7.07<\/p>\n

(iii) 77 rupees 77 paise = \u20b9 77 + \u20b9 77 \u00d7 \\(\\frac{1}{100}\\) = \u20b9 77 + \u20b9 0.77 = \u20b9 77.77<\/p>\n

(iv) 50 paise = \u20b9 50 \u00d7 \\(\\frac{1}{100}\\) = \u20b9 0.50<\/p>\n

(v) 235 paise= 200 paise + 35 paise
\n= \u20b9 2 + \u20b9 35 \u00d7 \\(\\frac{1}{100}\\) = \u20b9 2 + \u20b9 0.35
\n= \u20b9 2.35<\/p>\n

Question 3.
\n(i) Express 5 cm in metre and kilometre
\n(ii) Express 35 mm in cm, m, and km
\nAnswer:
\nWe know that 100 cm = 1 m,
\n1000 m = 1 km
\n(i) 5cm = \\(\\frac{5}{100}\\) m = 0.05 m
\n5 cm = \\(\\frac{5}{100 \\times 100}\\) km
\n= 0.00005 km.<\/p>\n

(ii) We know that 1 cm =10 mm
\n35 mm = \\(\\frac{35}{10 \\times 100}\\) m = \\(\\frac{35}{1000}\\)
\n35mm = \\(\\frac{35}{10 \\times 100}\\) m = \\(\\frac{35}{1000}\\)
\n= 0.035 m
\n35 mm \\(\\frac{35}{10 \\times 100 \\times 1000}\\) km
\n= \\(\\frac{35}{1000000}\\) = 0.000035 km<\/p>\n

\"NCERT<\/p>\n

Question 4.
\nExpress in kg:
\n(i) 200 g
\n(ii) 3470 g
\n(iii) 4 kg 8 g
\nAnswer:
\nWe know that 1000 g = 1 kg
\n(i) 200 g = \\(\\frac{200}{1000}\\) kg = \\(\\frac{2}{10}\\) kg = 0.2 kg
\n(ii) 3470 g = \\(\\frac{3470}{1000}\\) kg = \\(\\frac{347}{100}\\) kg = 3.47 kg
\n(iii) 4 kg 8 g = 4 kg + \\(\\frac{8}{1000}\\) kg
\n= 4 kg + 0.008 kg = 4.008 kg<\/p>\n

Question 5.
\nWrite the following decimal numbers in the expanded form:
\n(i) 20.03
\n(ii) 2.03
\n(iii) 200.03
\n(iv) 2.034
\nAnswer:
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 6.
\nWrite the place value of 2 in the following decimal numbers:
\n(i) 2.56
\n(ii) 21.37
\n(iii) 10.25
\n(iv) 9.42
\n(v) 63.352.
\nAnswer:
\n(i) In 2.56, the digit 2 is at the ones place
\n\u2234 place value of 2 is 2 \u00d7 1 = 2.<\/p>\n

(ii) In 21.37, the digit 2 is at the tens place
\n\u2234 place value of 2 is 2 \u00d7 10 = 20.<\/p>\n

(iii) In 10.25, the digit 2 is at the tenths place
\n\u2234 place value of 2 is 2 \u00d7 \\(\\frac{1}{10}=\\frac{2}{10}\\)<\/p>\n

(iv) In 9.42, the digit 2 is at the hundredths place
\n\u2234 The place value of 2 is 2 \u00d7 \\(\\frac{1}{100}=\\frac{2}{100}\\)<\/p>\n

(v) In 63.352, the digit 2 is at the thousandths place
\n\u2234 The place value of 2 is 2 \u00d7 \\(\\frac{1}{1000}=\\frac{2}{100}\\)<\/p>\n

Question 7.
\nDinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?
\nAnswer:
\nDistance from A to B = 7.5 km
\nDistance from B to C = 12.7 km
\nDistance from A to C through
\nB = (7.5 + 12.7) km
\n= 20.2 km
\n\u2234 Distance travelled by Dinesh = 20.2 km
\n\"NCERT
\nAgain
\nDistance from A to D = 9.3 km
\nDistance from D to C = 11.8 km
\nDistance from A to C through D
\n= (9.3 + 11.8) km
\n= 21.1 km
\n\u2234 Distance travelled by Ayub = 21.1 km 21. 1 > 20.2
\n\u2234 Ayub travelled more distance.
\nDifference = 21.1 km – 20.2 km
\n= 0.90 km (or) 900 m
\n\u2234 Ayub travelled more distance by 900 m<\/p>\n

\"NCERT<\/p>\n

Question 8.
\nShyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?
\nAnswer:
\nSince, Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes
\nTotal fruits bought by Shyama = 5 kg
\n300 g + 3 kg 250 g = 8 kg 550 g
\nSince, Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas
\nTotal fruits bought by Sarala
\n= 4 kg 800 g + 4 kg 150 g = 8 kg 950 g
\n8.950 > 8.550
\nSo, Sarala bought more fruits
\nDifference in weight = 8 kg 950 g – 8 kg 550 g = 0 kg 400 g
\n= 400 g or \\(\\frac{400}{1000}\\)kg = 0.4 kg<\/p>\n

Question 9.
\nHow much less is 28 km than 42.6 km?
\nAnswer:
\nDifference = 42.6 km – 28 km = 14.6 km 28 km is less than 42.6 km by 14.6 km<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.5 Question 1. Which is greater? (i) 0.5 or 0.05 (ii) 0.7 or 0.5 (iii) 7 or 0.7 …<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-7-maths-chapter-2-ex-2-5\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 Questions and Answers are prepared by our highly skilled subject experts. 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