{"id":27698,"date":"2021-07-01T16:05:44","date_gmt":"2021-07-01T10:35:44","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=27698"},"modified":"2021-07-02T10:19:07","modified_gmt":"2021-07-02T04:49:07","slug":"ncert-solutions-for-class-7-maths-chapter-8-ex-8-2","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-7-maths-chapter-8-ex-8-2\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 8 Comparing Quantities Ex 8.2 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.2<\/h2>\n

Question 1.
\nConvert the given fractional numbers to per cents
\n(i) \\(\\frac{1}{9}\\)
\n(b) \\(\\frac{5}{4}\\)
\n(c) \\(\\frac{3}{40}\\)
\n(d) \\(\\frac{2}{7}\\)
\nAnswer:
\n\"NCERT<\/p>\n

Question 2.
\nConvert the given decimal fractions to per cents.
\n(a) 0.65
\n(b) 2.1
\n(c) 0.02
\n(d) 12.35
\nAnswer:
\n(a) 0.65 : \\(\\frac{64}{100}=\\frac{65}{100}\\) \u00d7 100% = 65%
\n(b) 2.1 = \\(\\frac{21}{10}=\\frac{21}{10}\\) \u00d7 100% = 210%
\n(c) 0.02 = \\(\\frac{2}{100}=\\frac{2}{100}\\) \u00d7 100% =2 %
\n(d) 12.35 = \\(\\frac{1235}{100}=\\frac{1235}{100}\\) \u00d7 100% = 1235<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nEstimate what part of the figures is shaded and hence find the per cent which is shaded.
\n\"NCERT
\nAnswer:
\n(i) \\(\\frac{1}{4}\\) part is shaded.
\n\\(\\frac{1}{4}=\\frac{1}{4}\\) \u00d7 100% = % = 25 %
\nThis coloured part is 25%.<\/p>\n

(ii) 3 parts out of 5 parts are shaded so,
\n\\(\\frac{3}{5}\\) part is shaded
\n\\(\\frac{3}{5}=\\frac{3}{5}\\) \u00d7 100% = 3 \u00d7 20% = 60%
\nThis coloured part is 60%.<\/p>\n

(iii) Here 3 parts out of 8 parts are shaded 3
\nso, \\(\\frac{3}{8}\\) part is shaded.
\n\\(\\frac{3}{8}=\\frac{3}{8}\\) \u00d7 100% = \\(\\frac{3}{2}\\) x 25%
\n= 37\\(\\frac { 1 }{ 2 }\\)% or 37.5%
\nThis 37\\(\\frac { 1 }{ 2 }\\) part is shaded.<\/p>\n

Question 4.
\nFind:
\n(a) 15% of 250
\n(b) 1% of 1 hour
\n(c) 20% of \u20b9 2500
\n(d) 75% of 1 kg
\nAnswer:
\n(a) 15% of 250 = \\(\\frac{15}{100}\\) of 250
\n= \\(\\frac{15}{100} \\times 250=\\frac{15 \\times 250}{100}=\\frac{75}{2}\\)
\n= 37\\(\\frac{1}{2}\\) or 37.5
\n\u2234 15% of 250 = 37 \\(\\frac{1}{2}\\) or 37.5 2<\/p>\n

(b) 1% of 1 hour = \\(\\frac{1}{100}\\) \u00d7 60 minutes
\n= \\(\\frac{1 \\times 60}{100}=\\frac{3}{5}\\) minutes
\n= \\(\\frac { 3 }{ 5 }\\) \u00d7 60 seconds = 36 seconds
\n\u2234 1% of 1 hour = 36 seconds<\/p>\n

\"NCERT<\/p>\n

(c) 20% of \u20b9 2500 = \\(\\frac { 20 }{ 100 }\\) of
\n2500 = \\(\\frac { 20 }{ 100 }\\) x 2500
\n= \u20b9 \\(\\frac{20 \\times 2500}{100}\\) = \u20b9 500
\n\u2234 20% of \u20b9 2500 = \u20b9 500<\/p>\n

(d) 75% of 1 kg = 75% of 1000 g
\n= \\(\\frac{75}{100} \\times 100 \\mathrm{~g}=\\frac{75 \\times 1000}{100}\\) = 750 g
\n\u2234 75% of 1 kg = 750g<\/p>\n

Question 5.
\nFind the whole quantity if
\n(a) 5% of it is 600.
\n(b) 12% of it is \u20b9 1080.
\n(c) 40% of it is 500 km.
\n(d) 70% of it is 14 minutes.
\n(e) 8% of it is 40 litres.
\nAnswer:
\n(a) 5% of a quantity is 600.
\nLet the quantity be x
\n5% of x = 600
\n\\(\\frac { 5 }{ 100 }\\) \u00d7 x = 600
\nx = \\(\\frac{600 \\times 100}{5}\\)
\n= 120 \u00d7 100
\n= 12000
\nThus the required quantity is 12000.<\/p>\n

(b) 12% of it is \u20b9 1080
\nLet the required amount be x
\n12% of x = 1080
\n\\(\\frac { 12 }{ 100 }\\) \u00d7 x = 1080
\nx = \\(\\frac{1080 \\times 100}{12}\\)
\n= \\(\\frac{1080 \\times 25}{3}\\)
\nThe required amount = \u20b9 9000
\n= 360 \u00d7 25 = \u20b9 9000<\/p>\n

\"NCERT<\/p>\n

(c) 40% of it is 500 km
\nLet the total quantity be x
\n40% of x = 500
\n\\(\\frac { 4 }{ 100 }\\) \u00d7 x = 500
\nx = \\(\\frac{500 \\times 100}{40}\\) km
\n= 50 \u00d7 25 km
\n= 1250 km
\nThe required quantity is 1250 km.<\/p>\n

(d) 70% of it is 14 minutes
\nLet the required time be x
\n70% of x = 14 minutes
\n\\(\\frac{70}{100}\\) \u00d7 x = 14
\nx = \\(\\frac{14 \\times 100}{70}\\)
\n= 20 minutes
\nThus, the required quantity is 20 minutes.<\/p>\n

(e) 8% of a quantity is 40 litres
\nLet the quantity be x
\n8% of x =40 litres
\n\\(\\frac { 8 }{ 100 }\\) \u00d7 x = 40
\nx = \\(\\frac{40 \\times 100}{8}\\) = 500litres
\nThe required quantity is 500 litres.<\/p>\n

Question 6.
\nConvert given per cents to decimal fractions and also to fractions in simplest forms:
\n(a) 25%
\n(b) 150%
\n(c) 20%
\n(d) 5%
\nAnswer:
\n(a) 25% = \\(\\frac{25}{100}=\\frac{1}{4}\\)
\nThus, 20% = \\(\\frac{1}{4}\\) = 0.25<\/p>\n

\"NCERT<\/p>\n

(b) 150% = \\(\\frac{150}{100}=\\frac{3}{2}\\)
\nThus 150% = \\(\\frac{3}{2}\\) (or) 1\\(\\frac{1}{2}\\) = 1.5<\/p>\n

(c) 20% = \\(\\frac{20}{100}=\\frac{1}{5}\\) = 0.2
\nThus 20% = \\(\\frac{1}{5}\\) = 0.2<\/p>\n

(d) 5% = \\(\\frac{5}{100}=\\frac{1}{20}\\)
\nThus 5% = \\(\\frac{1}{20}\\) = 0.05<\/p>\n

Question 7.
\nIn a city, 30% are females, 40% are males and remaining are children. What per cent are children?
\nAnswer:
\nFemales are 30% and males are 40%
\nNumber of children = 100% – (30% + 40%)
\n= 100% – 70% = 30%
\nThus, children are 30% of the population.<\/p>\n

Question 8.
\nOut of 15,000 voters in a constituency, 60% voted. Find the percentage of voters who did not vote. Can you now find how many actually did not vote?
\nAnswer:
\nTotal number of voters = 15,000
\nPart of voters who voted = 60%
\nPart of voters who did not vote = 100% – 60% = 40%
\n40% of 15000 = \\(\\frac{40}{100}\\) \u00d7 15000
\n= 40 \u00d7 150 = 6000
\nThus, 6000 voters did not vote.<\/p>\n

\"NCERT<\/p>\n

Question 9.
\nMeeta saves \u20b9 4000 from her salary. If this is 10% of her salary. What is her salary?
\nAnswer:
\nMeeta saving = \u20b9 4000
\nLet the salary be \u20b9 x
\nSaving = 10% of x
\n10% of x =4000
\n\\(\\frac{10}{100}\\) \u00d7 x = 4000
\nx = \\(\\frac{4000 \\times 100}{10}\\)
\n= \u20b9 40,000
\nMeeta salary = \u20b9 40,000\/-<\/p>\n

Question 10.
\nA local cricket team played 20 matches in one season. It won 25% of them. How many matches did they win?
\nAnswer:
\nTotal number of matches played = 20
\nPart of matches won = 25%
\n25% of 20 = \\(\\frac{25}{100}\\) \u00d7 20 = \\(\\frac{25 \\times 20}{100}\\) = 5
\nThe team won 5 matches.<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.2 Question 1. Convert the given fractional numbers to per cents (i) (b) (c) (d) Answer: Question 2. Convert the …<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-7-maths-chapter-8-ex-8-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 Questions and Answers are prepared by our highly skilled subject experts. 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NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.2 Question 1. Convert the given fractional numbers to per cents (i) (b) (c) (d) Answer: Question 2. 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