{"id":28121,"date":"2021-07-03T13:04:24","date_gmt":"2021-07-03T07:34:24","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=28121"},"modified":"2021-07-03T13:04:47","modified_gmt":"2021-07-03T07:34:47","slug":"ncert-solutions-for-class-8-maths-chapter-14-ex-14-4","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-8-maths-chapter-14-ex-14-4\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.4"},"content":{"rendered":"

These NCERT Solutions for Class 8 Maths<\/a> Chapter 14 Factorization Ex 14.4 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 14 Factorization Exercise 14.4<\/h2>\n

Question 1.
\nFind and correct the errors in the following mathematical statements.
\nAnswer:
\n(1) 4(x – 5) = 4x – 5
\nThe given statement is incorrect.
\nThe correct statement is
\n4(x – 5) = 4x – 20<\/p>\n

\"NCERT<\/p>\n

(2) x (3x + 2) = 3x2<\/sup> + 2
\nThe given statement is incorrect.
\nThe correct statement is x (3x + 2) = 3x2<\/sup> + 2x<\/p>\n

(3) 2x + 3y = 5xy
\nThis is an incorrect statement.
\nThe correct statement is 2x + 3y = 2x + 3y<\/p>\n

(4) x + 2x + 3x = 5x
\nThis is an incorrect statement.
\nThe correct statement is x + 2x + 3x = 6x<\/p>\n

(5) 5y + 2y + y – 7y = 0
\nThis is an incorrect statement.
\nThe correct statement is
\n5y + 2y + y – 7y = y<\/p>\n

(6) 3x + 2x = 5x2<\/sup>
\nThis is an incorrect statement.
\nThe correct statement is 3x + 2x = 5x<\/p>\n

(7) (2x)2<\/sup> + 4(2x) + 7 = 2x2<\/sup> + 8x + 7
\nThis given statement is incorrect.
\nThe correct statement is
\n(2x)2<\/sup> + 4 (2x) + 7 = 4x2<\/sup> + 8x + 7<\/p>\n

(8) (2x)2<\/sup> + 5x = 4x + 5x = 9x2<\/sup>
\nThe given statement is incorrect.
\nThe correct statement is (2x)2<\/sup> + 5x = 4x2<\/sup> + 5x<\/p>\n

(9) (3x + 2)2<\/sup> = 3x2<\/sup> + 6x + 4
\nThe given statement is incorrect.
\nThe correct statement is
\n(3x + 2)2<\/sup> = (3x)2<\/sup> + 2 \u00d7 3x \u00d7 2 + (2)2<\/sup>
\n(3x + 2)2<\/sup> = 9x2<\/sup> + 12x + 4<\/p>\n

(10) Substituting x = – 3 in
\n(a) x2<\/sup> + 5x + 4
\n= (- 3)2<\/sup> + 5 (-3) + 4
\n= 9 + 2 + 4
\n= 15
\nThe given statement is incorrect.
\nThe correct statement is x2<\/sup> + 5x + 4
\n= (-3)2<\/sup> + 5 (- 3) + 4
\n= 9 – 15 + 4
\n= 13 – 15 = – 2
\n\u2234 x2<\/sup> + 5x + 4 = -2 at x = – 3<\/p>\n

\"NCERT<\/p>\n

(b) x2<\/sup> – 5x + 4
\n= (-3)2<\/sup> – 5 (-3) + 4
\n= 9 – 15 + 4 = -2
\nThe given statement is incorrect.
\nThe correct statement is
\nx2<\/sup> – 5x + 4
\n= (-3)2<\/sup> – 5 (-3) + 4
\n= 9 + 15 +4 = 28<\/p>\n

(c) x2<\/sup> + 5x = (-3)2<\/sup> + 5 (-3)
\n= – 9 – 15 = – 24
\nThe given statement is incorrect.
\nThe correct statement is
\nx2<\/sup> + 5x
\n= (-3)2<\/sup> + 5(\u20143)
\n= 9 – 15 = -6<\/p>\n

(11) (y – 3)2<\/sup> = y2<\/sup> – 9
\nThe given statement is incorrect. (y-3)2<\/sup>
\n= y2<\/sup> – 2 (y) (3) + 32<\/sup>
\n= y2<\/sup> – 6y + 9
\nThe correct statement is (y – 3)2<\/sup> = y2<\/sup> – 6y + 9<\/p>\n

(12) (z + 5)2<\/sup> = z2<\/sup> + 25
\nThe given statement is incorrect.
\n(z + 5)2<\/sup> = z2<\/sup> + 2 \u00d7 z \u00d7 5 + 52<\/sup>
\n= z2<\/sup> + 10z + 25
\nThe correct statement is (z + 5)2<\/sup> = z2<\/sup> + 10z + 25<\/p>\n

(13) (2a + 3b) (a – b) = 2a2<\/sup> – 3b2<\/sup>
\nThe given statement is incorrect.
\n(2a + 3b) (a – b)
\n= 2a (a – b) + 3b (a – b)
\n= 2a2<\/sup> – 2ab + 3ab – 3b2<\/sup>
\n= 2a2<\/sup> + ab – 3b2<\/sup>
\nThe correct statement is
\n(2a + 3b) (a – b) = 2a2<\/sup> + ab – 3b2<\/sup>
\n(14) (a + 4) (a + 2) = a2<\/sup> + 8
\nThe given statement is incorrect.
\n(a + 4) (a + 2)
\n= a (a + 2) + 4 (a + 2)
\n= a2<\/sup> + 2a + 4a + 8
\n= a2<\/sup> + 6a + 8
\nThe correct statement is (a + 4) (a + 2) = a2<\/sup> + 6a + 8<\/p>\n

\"NCERT<\/p>\n

(15) (a – 4) (a – 2) = a2<\/sup> – 8
\nThe given statement is incorrect, (a – 4) (a – 2)
\n= a(a – 2) – 4(a – 2)
\n= a2<\/sup> – 2a – 4a + 8
\n= a2<\/sup> – 6a + 8
\nThe correct statement is (a – 4) (a – 2) = a2<\/sup> – 6a + 8<\/p>\n

(16) \\(\\frac{3 x^{2}}{3 x^{2}}\\) = 0
\nThe given statement is incorrect.
\nThe correct statement is
\n\\(\\frac{3 x^{2}}{3 x^{2}}\\) = 1<\/p>\n

(17) \\(\\frac{3 x^{2}+1}{3 x^{2}}\\) = 1 + 1 = 2
\n\\(\\frac{3 x^{2}+1}{3 x^{2}}=\\frac{3 x^{2}}{3 x^{2}}+\\frac{1}{3 x^{2}}=1+\\frac{1}{3 x^{2}}\\)
\nThe given statement is incorrect.
\nThe correct statement is
\n\\(\\frac{3 x^{2}+1}{3 x^{2}}=1+\\frac{1}{3 x^{2}}\\)<\/p>\n

(18) \\(\\frac{3 x}{3 x+2}=\\frac{1}{2}\\)
\nThe given statement is incorrect.
\nThe correct statement is
\n\\(\\frac{3 x}{3 x+2}=\\frac{3 x}{3 x+2}\\)<\/p>\n

(19) \\(\\frac{3}{4 x+3}=\\frac{1}{4 x}\\)
\nThe given statement is incorrect.
\nThe correct statement is \\(\\frac{3}{4 x+3}=\\frac{3}{4 x+3}\\)<\/p>\n

(20) \\(\\frac{4 x+5}{4 x}\\) = 5
\nThe given statement is incorrect.
\n\\(\\frac{4 x+5}{4 x}=\\frac{4 x}{4 x}+\\frac{5}{4 x}=1+\\frac{5}{4 x}\\)
\nThe correct statement is
\n\\(\\frac{4 x+5}{4 x}=1+\\frac{5}{4 x}\\)<\/p>\n

\"NCERT<\/p>\n

(21) = 7x
\nThe given statement is incorrect.
\n\\(\\frac{7 \\mathrm{x}+5}{5}=\\frac{7 \\mathrm{x}}{5}+\\frac{5}{5}=\\frac{7 \\mathrm{x}}{5}+1\\)
\nThe correct statement is
\n\\(\\frac{7 x+5}{5}=\\frac{7 x}{5}+1\\)<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 14 Factorization Exercise 14.4 Question 1. Find and correct the errors in the following mathematical statements. Answer: (1) 4(x – 5) = 4x – 5 …<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.4<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.4 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-8-maths-chapter-14-ex-14-4\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.4 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.4 Questions and Answers are prepared by our highly skilled subject experts. 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