{"id":28315,"date":"2021-07-05T11:46:13","date_gmt":"2021-07-05T06:16:13","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=28315"},"modified":"2021-07-05T11:46:13","modified_gmt":"2021-07-05T06:16:13","slug":"ncert-solutions-for-class-8-maths-chapter-12-intext-questions","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-8-maths-chapter-12-intext-questions\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Chapter 12 Exponents and Powers InText Questions"},"content":{"rendered":"

These NCERT Solutions for Class 8 Maths<\/a> Chapter 12 Exponents and Powers InText Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 12 Exponents and Powers InText Questions<\/h2>\n

NCERT Intext Question Page No. 194<\/span><\/p>\n

Question 1.
\nFind the multiplicative inverse of the following:
\n(i) 2-4<\/sup>
\n(ii) 105<\/sup>
\n(iii) 7-2<\/sup>
\n(iv) 5-3<\/sup>
\n(v) 10-100<\/sup>
\nAnswer:
\n(i) The multiplicative inverse of 2-4<\/sup> = 24<\/sup>
\n(ii) The multiplicative inverse of 10-5<\/sup> = 105<\/sup>
\n(iii) The multiplicative inverse of 7-2<\/sup> = 72<\/sup>
\n(iv) The multiplicative inverse of 5-3<\/sup> = 53<\/sup>
\n(v) The multiplicative inverse of 10-100<\/sup> = 10100<\/sup><\/p>\n

\"NCERT<\/p>\n

Question 2.
\nExpand the following numbers using exponents.
\n(i) 1025.63
\n(ii) 1256.249
\nAnswer:<\/p>\n\n\n\n\n\n
Number<\/td>\nExpanded form<\/td>\n<\/tr>\n
(i) 1025.63<\/td>\n1 x 1000 + 0 x 100 + 2 x 10 + 5\u00a0 x 1 \\(\\frac{6}{10}+\\frac{3}{100}\\) or
\n1 x 103<\/sup> + 2 x 101<\/sup> + 5 x 10\u00b0 + 6 x 10-1<\/sup> + 3 x 10-2<\/sup><\/td>\n<\/tr>\n
(ii) 1025.249<\/td>\n1 x 1000 +2 x 100 +5 x 10 + 6 x 1 + \\(\\frac{2}{10}+\\frac{4}{100}+\\frac{9}{1000}\\)
\nor
\n1 x 103<\/sup> + 2 x 102<\/sup> + 5 x 101<\/sup> + 6 x 10\u00b0 + 2 x 10-1<\/sup> + 9 x 10-3<\/sup><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

NCERT Intext Question Page No. 195<\/span><\/p>\n

Question 1.
\nSimplify and write in exponential form.
\n(i) (-2)-3<\/sup> x (-2)-4<\/sup>
\n(ii) p3<\/sup> x p-10<\/sup>
\n(iii) 32<\/sup> x 3-5<\/sup> x 36<\/sup>
\nAnswer:
\n(i) (-2)-3<\/sup> x (-2)-4<\/sup> = (-2)3-4<\/sup>
\n[am<\/sup> x an<\/sup> = am+n<\/sup>]
\n= (-2)-7<\/sup> = \\(\\frac{1}{(-2)^{7}}\\)<\/p>\n

(ii) p3<\/sup> x p-10<\/sup> = p3 + (-10)<\/sup> = p3 – 10 <\/sup>= p7<\/sup> or \\(\\frac{1}{\\mathrm{p}^{7}}\\)<\/p>\n

\"NCERT<\/p>\n

(iii) 32<\/sup> x 3-5<\/sup> x 36<\/sup> = 32 + (- 5) + 6<\/sup> = 32 – 5 + 6<\/sup> = 38-5<\/sup> = 33<\/sup><\/p>\n

NCERT Intext Question Page No. 199<\/span><\/p>\n

Question 1.
\nWrite the following numbers in standard form.
\n(i) 0.000000564
\n(ii) 0.0000021
\n(iii) 15240000
\nAnswer:
\n(i) 0.000000564 = \\(\\frac{564}{1000000000}=\\frac{564}{10^{9}}\\)
\n= \\(\\frac{5.64 \\times 10^{2}}{10^{9}}\\) = 5.64 x 10-7<\/sup><\/p>\n

(ii) 0.0000021 = \\(\\frac{21}{10000000}=\\frac{21}{10^{7}}\\)
\n= \\(\\frac{2.1 \\times 10}{10^{7}}\\) = 2.1 x 101-7<\/sup> = 2.1 x 10-6<\/sup><\/p>\n

(iii) 15240000 = 1524 x 10000
\n= 1.524 x 1000 x 10000 = 1.524 x 107<\/sup>
\n\u2234 15240000 = 1.524 x 107<\/sup><\/p>\n

\"NCERT<\/p>\n

Question 2.
\nWrite all the facts give in the standard form.
\nAnswer:
\nA number is said to be in the standard form when it is written as k x 10n<\/sup>, Where 1 \u2264 k < 10 and ‘n’ is an integer. A number expressed as the product of a number between 1 and 10 and an integral power of 10.
\nExample: Compare the size of a red blood cell which is 0.000007m to that of a plant cell which is 0.0000129m.
\nSize of red blood cell = 0.000007 m
\n= \\(\\frac{7}{1000000}\\) x 10-6<\/sup> m
\nSize of the plant cell = \\(\\frac{7}{10000000} \\mathrm{~m}=\\frac{1.29 \\times 10^{2}}{10000000} \\mathrm{~m}\\)
\n= 1.29 x 10-5<\/sup> m
\nNow = \\(\\frac{7 \\times 10^{-6}}{1.29 \\times 10^{-5}}=\\frac{7 \\times 10^{-1}}{1.29}\\)
\n= \\(\\frac{7 \\times 10^{-1}}{1.3}=\\frac{0.7}{1.3}=\\frac{1}{2}\\) (approx)
\nThus, the size of a red blood cell is half of the plant cell size.<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 8 Maths Chapter 12 Exponents and Powers InText Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 12 Exponents and Powers InText Questions NCERT Intext Question Page No. 194 Question 1. Find the multiplicative inverse of the following: (i) 2-4 (ii) …<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 12 Exponents and Powers InText Questions<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 12 Exponents and Powers InText Questions - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-8-maths-chapter-12-intext-questions\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 8 Maths Chapter 12 Exponents and Powers InText Questions - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 8 Maths Chapter 12 Exponents and Powers InText Questions and Answers are prepared by our highly skilled subject experts. 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