{"id":28522,"date":"2021-07-06T18:00:27","date_gmt":"2021-07-06T12:30:27","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=28522"},"modified":"2021-07-06T18:04:40","modified_gmt":"2021-07-06T12:34:40","slug":"ncert-solutions-for-class-10-maths-chapter-8-ex-8-1","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-8-ex-8-1\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1"},"content":{"rendered":"

These NCERT Solutions for Class 10 Maths<\/a> Chapter 8 Introduction to Trigonometry Ex 8.1 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.1<\/h2>\n

\"NCERT<\/p>\n

Question 1.
\nIn \u2206ABC right angled at B, AB = 24 cm, BC = 7 cm. Determine:
\n(i) sin A, cos A
\n(ii) sin C, cos C
\nSolution:
\nWe have given that,
\n\u2206ABC is a right angle \u2206, right angled at B and AB = 24 cm, BC = 7 cm
\n\u2234 By Pythagoras theorem
\n\"NCERT<\/p>\n

Question 2.
\nIn given figure, find tan P – cot R.
\nSolution:
\nWe have given that \u2206PQR is a right angled A, right angle at Q. and PQ = 12 cm, PR = 13 cm
\n\u2234 By Pythagoras theorem, we know that
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nIf sin A = \\(\\frac { 3 }{ 4 }\\), calculate cos A and tan A.
\nSolution:
\nGiven
\n\"NCERT<\/p>\n

Question 4.
\nGiven 15 cot A = 8, find sin A and sec A.
\nSolution:
\n\"NCERT<\/p>\n

Question 5.
\nGiven sec \u03b8 = \\(\\frac { 13 }{ 12 }\\) , calculate all other trigonometric ratios.
\nSolution:
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 6.
\nIf \u2220A and \u2220B are acute angles such that cos A = cos B, then show that \u2220A = \u2220B.
\nSolution:
\n\"NCERT<\/p>\n

Question 7.
\nIf cot \u03b8 = \\(\\frac { 7 }{ 8 }\\), evaluate:
\n(i) \\(\\frac { \\left( 1+sin\\theta \\right) \\left( 1-sin\\theta \\right) }{ \\left( 1+cos\\theta \\right) \\left( 1-cos\\theta \\right)}\\)
\n(ii) cot\u00b2\u03b8
\nSolution:
\n\"NCERT<\/p>\n

Question 8.
\nIf 3 cot A = 4, check whether \\(\\frac { 1-tan^{ 2 }A }{ 1+tan^{ 2 }A }\\) = cos\u00b2 A – sin\u00b2 A or not.
\nSolution:
\n\"NCERT<\/p>\n

Question 9.
\nIn triangle ABC, right angled at B, if tan A = \\(\\frac { 1 }{ \\surd 3 }\\), find the value of:
\n(i) sin A cos C + cos A sin C
\n(ii) cos A cos C – sin A sin C
\nSolution:
\n\"NCERT<\/p>\n

Question 10.
\nIn \u0394PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.
\nSolution:
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 11.
\nState whether the following statements are true or false. Justify your answer.
\n(i) The value of tan A is always less than 1.
\n(ii) sec A = \\(\\frac { 12 }{ 5 }\\) for some value of angle A.
\n(iii) cos A is the abbreviation used for the cosecant of angle A.
\n(iv) cot A is the product of cot and A.
\n(v) sin \u03b8 = \\(\\frac { 4 }{ 3 }\\) for some angle.
\nSolution:
\n(i) tan 60\u00b0 = \u221a3 , Since \u221a3 > 1. (False)
\n(ii) sec A is always \u2265 1. (True)
\n(iii) cos A is the abbreviation for cosine A. (False)
\n(iv) cot without \u2220A is meaningless. (False)
\n(v) sin \u03b8 can never be greater than 1.
\n\u2234 sin \u03b8 = \\(\\frac { P }{ H }\\), hypotenuse is always greater than other two sides. (False)<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.1 Question 1. In \u2206ABC right angled at B, AB = 24 cm, BC = 7 cm. Determine: …<\/p>\n

NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[2],"tags":[],"yoast_head":"\nNCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-8-ex-8-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 Questions and Answers are prepared by our highly skilled subject experts. 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