{"id":29495,"date":"2024-01-18T18:00:44","date_gmt":"2024-01-18T12:30:44","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=29495"},"modified":"2024-01-19T17:58:27","modified_gmt":"2024-01-19T12:28:27","slug":"ncert-solutions-for-class-12-maths-chapter-3-ex-3-4","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-12-maths-chapter-3-ex-3-4\/","title":{"rendered":"NCERT Solutions for Class 12 Maths Chapter 3 Matrices Ex 3.4"},"content":{"rendered":"

These NCERT Solutions for Class 12 Maths<\/a> Chapter 3 Matrices Ex 3.4 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 12 Maths Chapter 3 Matrices Exercise 3.4<\/h2>\n

\"NCERT<\/p>\n

Question 1.
\n\\(\\begin{bmatrix} 1 & -1 \\\\ 2 & 3 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 1 & -1 \\\\ 2 & 3 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

Question 2.
\n\\(\\begin{bmatrix} 2 & 1 \\\\ 1 & 1 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 2 & 1 \\\\ 1 & 1 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

Question 3.
\n\\(\\begin{bmatrix} 1 & 3 \\\\ 2 & 7 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 1 & 3 \\\\ 2 & 7 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 4.
\n\\(\\begin{bmatrix} 2 & 3 \\\\ 5 & 7 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 2 & 3 \\\\ 5 & 7 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

Question 5.
\n\\(\\begin{bmatrix} 2 & 1 \\\\ 7 & 4 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 2 & 1 \\\\ 7 & 4 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

Question 6.
\n\\(\\begin{bmatrix} 2 & 5 \\\\ 1 & 3 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 2 & 5 \\\\ 1 & 3 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 7.
\n\\(\\begin{bmatrix} 3 & 1 \\\\ 5 & 2 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 3 & 1 \\\\ 5 & 2 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

Question 8.
\n\\(\\begin{bmatrix} 4 & 5 \\\\ 3 & 4 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 4 & 5 \\\\ 3 & 4 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

Question 9.
\n\\(\\begin{bmatrix} 3 & 10 \\\\ 2 & 7 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 3 & 10 \\\\ 2 & 7 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 10.
\n\\(\\begin{bmatrix} 3 & -1 \\\\ -4 & 2 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 3 & -1 \\\\ -4 & 2 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

Question 11.
\n\\(\\begin{bmatrix} 2 & -6 \\\\ 1 & -2 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 2 & -6 \\\\ 1 & -2 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 12.
\n\\(\\begin{bmatrix} 6 & -3 \\\\ -2 & 1 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 6 & -3 \\\\ -2 & 1 \\end{bmatrix}\\)
\nTo use column transformation write A = AI
\n\\(\\begin{bmatrix} 6 & -3 \\\\ -2 & 1 \\end{bmatrix}\\) = A\\(\\left[\\begin{array}{ll} 1 & 0 \\\\ 0 & 1 \\end{array}\\right]\\)
\nApplying C1<\/sub> \u2192 C1<\/sub> + 2C2<\/sub>
\n\\(\\left[\\begin{array}{ll} 0 & -3 \\\\ 0 & 1 \\end{array}\\right]\\) = A\\(\\left[\\begin{array}{ll} 1 & 0 \\\\ 2 & 1 \\end{array}\\right]\\)<\/p>\n

Question 13.
\n\\(\\begin{bmatrix} 2 & -3 \\\\ -1 & 2 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 2 & -3 \\\\ -1 & 2 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

Question 14.
\n\\(\\begin{bmatrix} 2 & 1 \\\\ 4 & 2 \\end{bmatrix}\\)
\nSolution:
\nLet \\(A=\\begin{bmatrix} 2 & 1 \\\\ 4 & 2 \\end{bmatrix}\\)
\nWrite
\nA = IA
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 15.
\n\\(\\left[ \\begin{matrix} 2 & -3 & 3 \\\\ 2 & 2 & 3 \\\\ 3 & -2 & 2 \\end{matrix} \\right] \\)
\nSolution:
\n\"NCERT<\/p>\n

Question 16.
\n\\(\\left[ \\begin{matrix} 1 & 3 & -2 \\\\ -3 & 0 & -5 \\\\ 2 & 5 & 2 \\end{matrix} \\right] \\)
\nSolution:
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 17.
\n\\(\\left[ \\begin{matrix} 2 & 0 & -1 \\\\ 5 & 1 & 0 \\\\ 0 & 1 & 3 \\end{matrix} \\right] \\)
\nSolution:
\nRow transformation
\nLet \\(A=\\left[ \\begin{matrix} 2 & 0 & -1 \\\\ 5 & 1 & 0 \\\\ 0 & 1 & 3 \\end{matrix} \\right] \\)
\n\"NCERT<\/p>\n

Question 18.
\nChoose the correct answer in the following question:
\nMatrices A and B will be inverse of each other only if
\n(a) AB = BA
\n(b) AB = BA = 0
\n(c) AB = 0, BA = 1
\n(d) AB = BA = I
\nSolution:
\nChoice (d) is correct
\ni.e., AB = BA = I<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 12 Maths Chapter 3 Matrices Ex 3.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 12 Maths Chapter 3 Matrices Exercise 3.4 Question 1. Solution: Let Write A = IA Question 2. Solution: Let Write A = IA Question 3. Solution: Let Write …<\/p>\n

NCERT Solutions for Class 12 Maths Chapter 3 Matrices Ex 3.4<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[3],"tags":[],"yoast_head":"\nNCERT Solutions for Class 12 Maths Chapter 3 Matrices Ex 3.4 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-12-maths-chapter-3-ex-3-4\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 12 Maths Chapter 3 Matrices Ex 3.4 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 12 Maths Chapter 3 Matrices Ex 3.4 Questions and Answers are prepared by our highly skilled subject experts. 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