{"id":30079,"date":"2023-11-01T17:41:19","date_gmt":"2023-11-01T12:11:19","guid":{"rendered":"https:\/\/ncertsolutions.guru\/?p=30079"},"modified":"2023-11-02T14:41:42","modified_gmt":"2023-11-02T09:11:42","slug":"ncert-solutions-for-class-12-maths-chapter-5-ex-5-6","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-6\/","title":{"rendered":"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.6"},"content":{"rendered":"

These NCERT Solutions for Class 12 Maths<\/a> Chapter 5 Continuity and Differentiability Ex 5.6 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.6<\/h2>\n

\"NCERT<\/p>\n

Question 1.
\nx = 2at\u00b2, y = at4<\/sup>
\nSolution:
\n\"NCERT<\/p>\n

Question 2.
\nx = a cos \u03b8, y = b cos \u03b8
\nSolution:
\n\"NCERT<\/p>\n

Question 3.
\nx = sin t, y = cos 2t
\nSolution:
\n\"NCERT<\/p>\n

Question 4.
\n\\(x=4t,y=\\frac { 4 }{ t } \\)
\nSolution:
\n\"NCERT<\/p>\n

Question 5.
\nx = cos \u03b8 – cos 2\u03b8, y = sin \u03b8 – sin 2\u03b8
\nSolution:
\n\"NCERT<\/p>\n

Question 6.
\nx = a(\u03b8 – sin\u03b8), y = a(1 + cos\u03b8)
\nSolution:
\n\"NCERT<\/p>\n

Question 7.
\n\\(x=\\frac { { sin }^{ 3 }t }{ \\sqrt { cos2t } } \\& y=\\frac { { cos }^{ 3 }t }{ \\sqrt { cos2t } } \\)
\nSolution:
\n\"NCERT<\/p>\n

Question 8.
\n\\(x=a\\left( cost+log\\quad tan\\frac { t }{ 2 } \\right) ,y=a\\quad sint \\)
\nSolution:
\n\"NCERT<\/p>\n

Question 9.
\nx = a sec \u03b8, y = b tan \u03b8
\nSolution:
\n\"NCERT<\/p>\n

Question 10.
\nx = a(cos\u03b8 + \u03b8sin\u03b8), y = a(sin\u03b8 – \u03b8cos\u03b8)
\nSolution:
\n\"NCERT<\/p>\n

Question 11.
\nIf \\(x=\\sqrt { { a }^{ { sin }^{ -1 }t } } ,y=\\sqrt { { a }^{ { cos }^{ -1 }t } } \\) show that \\(\\frac { dy }{ dx } =-\\frac { y }{ x } \\)
\nSolution:
\nGiven that
\n\"NCERT<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.6 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.6 Question 1. x = 2at\u00b2, y = at4 Solution: Question 2. x = a cos \u03b8, y …<\/p>\n

NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.6<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[3],"tags":[],"yoast_head":"\nNCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.6 - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-6\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.6 - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.6 Questions and Answers are prepared by our highly skilled subject experts. 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