{"id":57,"date":"2021-07-23T06:16:05","date_gmt":"2021-07-23T00:46:05","guid":{"rendered":"http:\/\/ncertsolutions.guru\/?p=57"},"modified":"2021-07-23T18:36:34","modified_gmt":"2021-07-23T13:06:34","slug":"ncert-solutions-for-class-10-maths-chapter-4-hindi","status":"publish","type":"post","link":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)"},"content":{"rendered":"

NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)<\/h2>\n

These Solutions are part of NCERT Solutions for Class 10 Maths in Hindi Medium<\/a>. Here we have given NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations\u00a0.<\/p>\n

Chapter 4. \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923<\/strong><\/p>\n

\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0935\u0932\u0940 4.1<\/strong><\/span><\/p>\n

Ex 4.1 Class 10 \u0917\u0923\u093f\u0924 Q1. \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f \u0915\u094d\u092f\u093e \u0928\u093f\u092e\u094d\u0928 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948:\u00a0<\/strong><\/p>\n

(i) (x + 1)2<\/sup>\u00a0= 2(x – 3)<\/strong><\/p>\n

\u0939\u0932 :<\/strong><\/p>\n

(x + 1)2<\/sup>\u00a0= 2(x – 3)<\/p>\n

\u21d2 x2<\/sup>\u00a0+ 2x + 1 = 2x – 6<\/p>\n

\u21d2 x2<\/sup>\u00a0+ 2x – 2x + 1 + 6 = 0<\/p>\n

\u21d2 x2<\/sup>\u00a0+ 7 = 0<\/p>\n

ax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\n

a = 1, b = 0 \u0914\u0930 c = 7 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n

\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n

(ii) x2<\/sup>\u00a0– 2x = (-2) (3 – x)<\/strong><\/p>\n

\u0939\u0932 :<\/strong><\/p>\n

x2<\/sup>\u00a0– 2x = – 6 + 2x<\/p>\n

\u21d2 x2<\/sup>\u00a0– 2x – 2x + 6 = 0<\/p>\n

\u21d2 x2<\/sup>\u00a0– 4x + 6 = 0<\/p>\n

ax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\n

a = 1, b = – 4\u00a0\u0914\u0930 c = 6\u00a0\u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n

\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n

(iii) (x – 2) (x + 1) = ( x – 1) (x + 3)<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u00a0(x – 2) (x + 1) = ( x – 1) (x + 3)<\/p>\n

\u21d2\u00a0x2<\/sup>\u00a0+ x – 2x -2\u00a0 =\u00a0x2<\/sup>\u00a0+ 3x – x – 3<\/p>\n

\u200b\u21d2\u00a0x2<\/sup>\u00a0–\u00a0x2<\/sup>+ x + x – 2x + 3x -2 + 3\u00a0= 0<\/p>\n

\u200b\u21d2\u00a02x – x – 1 \u00a0= 0<\/p>\n

ax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e\u00a0 \u0939\u0948 |<\/p>\n

..<\/sup>.\u00a0\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u0939\u0940\u0902\u00a0\u0939\u0948 |<\/p>\n

(iv) (x – 3) (2x +1) = x( x + 5)<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0(x – 3) (2x +1) = x( x + 5)<\/p>\n

\u21d2 2x2\u00a0<\/sup>+ x – 6x – 3= x2\u00a0<\/sup>+\u00a05x<\/p>\n

\u21d2 2x2\u00a0<\/sup>– 5x – 3= x2\u00a0<\/sup>+\u00a05x<\/p>\n

\u21d2\u00a0\u00a02x2\u00a0<\/sup>–\u00a0x2\u00a0<\/sup>– 5x\u00a0– 5x – 3 \u00a0=\u00a0\u00a0<\/sup>0<\/p>\n

\u21d2\u00a0\u00a0x2\u00a0<\/sup>–\u00a010x – 3 \u00a0=\u00a0\u00a0<\/sup>0<\/p>\n

ax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\n

a = 1, b = – 10 \u0914\u0930 c = – 3 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n

\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n

(v) (2x – 1) 2(x – 3 ) = (x + 5) (x – 1)<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u00a0(2x – 1) 2(x – 3 ) = (x + 5) (x – 1)<\/p>\n

\u21d2\u00a0(2x – 1) (2x – 6 ) = (x + 5) (x – 1)<\/p>\n

\u21d2 4x2\u00a0<\/sup>– 12x – 2x + 6 = x2\u00a0<\/sup>+ 4x – 5<\/p>\n

\u21d2 4x2\u00a0<\/sup>– 14x + 6 =\u00a0x2<\/sup>\u00a0– x\u00a0+ 4x – 5<\/p>\n

\u21d2 4x2\u00a0<\/sup>–\u00a0x2\u00a0<\/sup>–\u00a014x\u00a0– 4x + 6 + 5 =\u00a00<\/p>\n

\u21d2 \u00a03x2\u00a0<\/sup>–\u00a018x + 11\u00a0 =\u00a0\u00a0<\/sup>0<\/p>\n

ax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\n

a = 3, b = – 18 \u0914\u0930 c = 11 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n

\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n

(vi) x2<\/sup>\u00a0+ 3x + 1 = (x – 2)2\u00a0<\/sup><\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>x2<\/sup>\u00a0+ 3x + 1 = (x – 2)2<\/sup><\/p>\n

\u21d2\u00a0\u00a0<\/strong>x2<\/sup>\u00a0+ 3x + 1\u00a0= x2\u00a0<\/sup>– 2x +4<\/p>\n

\u21d2x2\u00a0<\/sup>–\u00a0x2\u00a0<\/sup>+ 4x + 3x + 1 –\u00a04 =\u00a00<\/p>\n

\u21d2 7x – 3\u00a0=\u00a0\u00a0<\/sup>0<\/p>\n

ax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e\u00a0 \u0939\u0948 |<\/p>\n

..<\/sup>.\u00a0\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u0939\u0940\u0902\u00a0\u0939\u0948 |<\/p>\n

(vii) (x + 2)3<\/sup>\u00a0= 2x(x2<\/sup>\u00a0– 1)\u00a0<\/strong><\/p>\n

\u0939\u0932 :<\/strong>(x + 2)3<\/sup>\u00a0= 2x(\u00a0x2\u00a0<\/sup>– 1)<\/p>\n

\u21d2 x3\u00a0<\/sup>+ 8 + 6\u00a0<\/sup>+ 12x = 2x3\u00a0<\/sup>– 2x<\/p>\n

\u21d2 2x3\u00a0<\/sup>–\u00a0x3<\/sup>\u00a0– 6-12x + 2x \u00a0– 8 = 0<\/p>\n

\u21d2 \u00a0x3<\/sup>\u00a0– 6x2\u00a0<\/sup>-10x – 8 =0<\/p>\n

ax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e\u00a0 \u0939\u0948 |<\/p>\n

..<\/sup>.\u00a0\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u0939\u0940\u0902\u00a0\u0939\u0948 |<\/p>\n

(viii) x3<\/sup>\u00a0– 4x2<\/sup>\u00a0– x + 1 = (x – 2 )3<\/sup>\u00a0\u00a0<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>x3<\/sup>\u00a0– 4x2<\/sup>\u00a0<\/sup>– x + 1 = (x – 2 )3<\/sup><\/p>\n

\u21d2x3<\/sup>\u00a0– 4x2<\/sup>\u00a0<\/sup>– x + 1 \u00a0= x3\u00a0<\/sup>–\u00a08 + 6x2\u00a0<\/sup>+ 12x<\/p>\n

\u21d2 x3\u00a0<\/sup>–\u00a0x3<\/sup>\u00a0–\u00a0\u00a0<\/sup>4x2<\/sup>\u00a0<\/sup>+\u00a06x2\u00a0<\/sup>-12x + 1 =\u00a00<\/p>\n

\u21d2 \u00a02x2\u00a0<\/sup>-13x\u00a0+ 1\u00a0= 0<\/p>\n

ax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\n

a = 2, b = – 13 \u0914\u0930 c = 1 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n

\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n

Ex 4.1 Class 10 \u0917\u0923\u093f\u0924\u00a0Q2. \u0928\u093f\u092e\u094d\u0928 \u0938\u094d\u0925\u093f\u0924\u093f\u092f\u094b\u0902 \u0915\u094b \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0928\u093f\u0930\u0941\u092a\u093f\u0924 \u0915\u0940\u091c\u093f\u090f :<\/strong><\/p>\n

(i) \u090f\u0915 \u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 528 m2\u00a0<\/sup>\u0939\u0948 | \u0915\u094d\u0937\u0947\u0924\u094d\u0930 \u0915\u0940 \u0932\u0902\u092c\u093e\u0908 (\u092e\u0940\u091f\u0930\u094b\u0902 \u092e\u0947\u0902) \u091a\u094c\u095c\u093e\u0908 \u0915\u0947 \u0926\u0941\u0917\u0941\u0928\u0947 \u0938\u0947\u00a0\u090f\u0915 \u0905\u0927\u093f\u0915 \u0939\u0948 | \u0939\u092e\u0947\u0902 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u0932\u0902\u092c\u093e\u0908 \u0914\u0930 \u091a\u094c\u095c\u093e\u0908\u00a0\u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0928\u0940\u00a0\u0939\u0948 |<\/strong><\/p>\n

\u0939\u0932 : \u00a0\u00a0<\/strong>\u090f\u0915\u00a0\u00a0<\/sup>\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u093e\u00a0\u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932\u00a0=\u00a0528 m2<\/sup><\/p>\n

\u092e\u093e\u0928\u093e\u00a0\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u091a\u094c\u095c\u093e\u0908 = x\u00a0m<\/p>\n

\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u0932\u0902\u092c\u093e\u0908\u00a0\u00a0=\u00a02x + 1\u00a0m\u00a0<\/sup><\/p>\n

\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u093e\u00a0\u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932\u00a0=\u00a0528 m2<\/sup><\/p>\n

\u0932\u0902\u092c\u093e\u0908 x \u091a\u094c\u095c\u093e\u0908 =\u00a0528<\/p>\n

(2x + 1)x =\u00a0528<\/p>\n

2x2<\/sup>\u00a0+ x\u00a0=\u00a0528<\/p>\n

2x2<\/sup>\u00a0+ x –\u00a0528\u00a0= 0<\/p>\n

2x2<\/sup>\u00a0+ 33x – 32x –\u00a0528\u00a0= 0<\/p>\n

x(2x + 33) – 16(2x + 33\u00a0) = 0<\/p>\n

(2x + 33) (x\u00a0– 16) = 0<\/p>\n

2x + 33\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x\u00a0– 16\u00a0= 0<\/p>\n

2x\u00a0= –\u00a033\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a016<\/div>\n
x\u00a0= –\u00a033\/2\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a016<\/div>\n
<\/div>\n
\u091a\u0942\u0901\u0915\u093f<\/div>\n
\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u091a\u094c\u095c\u093e\u0908 =\u00a0X\u00a0m<\/div>\n
\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 =\u00a016\u00a0m<\/p>\n

\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u0932\u0902\u092c\u093e\u0908\u00a0\u00a0=\u00a02X+ 1\u00a0m<\/p>\n

=\u00a02\u00a0x\u00a016 + 1\u00a0m<\/p>\n

= 32\u00a0+ 1\u00a0m<\/p>\n

= 33m<\/p>\n<\/div>\n

(ii) \u0926\u094b\u00a0\u0915\u094d\u0930\u092e\u093e\u0917\u0924 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u094b\u0902 \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 306 \u0939\u0948 | \u0939\u092e\u0947\u0902 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u094b\u0902 \u0915\u094b \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0928\u093e \u0939\u0948 |<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u0926\u094b\u00a0\u0915\u094d\u0930\u092e\u093e\u0917\u0924 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u094b\u0902 \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 \u00a0= 306<\/p>\n

\u092e\u093e\u0928\u093e \u092a\u0939\u0932\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0\u00a0= x<\/p>\n

\u0926\u0942\u0938\u0930\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0 =\u00a0x + 1\u00a0\u00a0<\/sup><\/p>\n

\u0926\u094b\u00a0\u0915\u094d\u0930\u092e\u093e\u0917\u0924 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u094b\u0902 \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 = 306<\/p>\n

\u092a\u0939\u0932\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915 x\u00a0\u0926\u0942\u0938\u0930\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915 = 306<\/p>\n

(x + 1)x \u00a0 \u00a0= 306<\/p>\n

x2<\/sup>\u00a0+ x\u00a0= 306<\/p>\n

x2<\/sup>\u00a0+ x – 306\u00a0= 0<\/p>\n

2x2<\/sup>\u00a0+ 18x – 17x – 306\u00a0= 0<\/p>\n

x(x +\u00a0) – 17(x + 18\u00a0) = 0<\/p>\n

(x +\u00a018) (x\u00a0– 17) = 0<\/p>\n

x + 18\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x\u00a0– 17\u00a0= 0<\/p>\n

x\u00a0= – 18\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a017<\/div>\n
<\/div>\n
\u091a\u0942\u0901\u0915\u093f<\/div>\n
\u092a\u0939\u0932\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0= x<\/div>\n
\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0= 17<\/p>\n

\u0926\u0942\u0938\u0930\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0\u00a0=\u00a0x + 1<\/p>\n

= 17\u00a0+ 1<\/p>\n<\/div>\n

= 18<\/p>\n

(iii) \u0930\u094b\u0939\u0928 \u0915\u0940 \u092e\u093e\u0901 \u0909\u0938\u0938\u0947 26 \u0935\u0930\u094d\u0937 \u092c\u095c\u0940 \u0939\u0948 |\u0909\u0928\u0915\u0940 \u0906\u092f\u0941 (\u0935\u0930\u094d\u0937\u094b\u0902 \u092e\u0947\u0902) \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 \u0905\u092c \u0938\u0947 \u0924\u0940\u0928 \u0935\u0930\u094d\u0937 \u092a\u0936\u094d\u091a\u093e\u0924\u094d 360 \u0939\u094b \u091c\u093e\u090f\u0917\u0940| \u0939\u092e\u0947\u0902 \u0930\u094b\u0939\u0928 \u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0906\u092f\u0941 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0923\u0940 \u0939\u0948 |<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u092e\u093e\u0928\u093e\u00a0\u0930\u094b\u0939\u0928\u00a0\u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928\u00a0\u0906\u092f\u0941\u00a0\u00a0= x<\/p>\n

\u0930\u094b\u0939\u0928 \u0915\u0940 \u092e\u093e\u0901 \u0915\u0940 \u0906\u092f\u0941 \u00a0=\u00a0x + 26<\/p>\n

\u0924\u0940\u0928 \u0935\u0930\u094d\u0937 \u092a\u0936\u094d\u091a\u093e\u0924\u00a0\u0930\u094b\u0939\u0928 \u0915\u0940 \u0906\u092f\u0941\u00a0\u00a0= x + 3<\/p>\n

\u0924\u0940\u0928 \u0935\u0930\u094d\u0937 \u092a\u0936\u094d\u091a\u093e\u0924\u00a0\u0930\u094b\u0939\u0928 \u0915\u0940 \u092e\u093e\u0901 \u0915\u0940 \u0906\u092f\u0941\u00a0\u00a0\u00a0=\u00a0x + 26\u00a0+ 3<\/p>\n

\u00a0<\/sup>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0=\u00a0x + 29<\/p>\n

\u0926\u094b\u0928\u094b \u0915\u0940 \u0906\u092f\u0941\u00a0\u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 = 306<\/p>\n

(x + 29)(x + 3)\u00a0= 306<\/p>\n

x2<\/sup>\u00a0+ 29x\u00a0+ 3x\u00a0+ 87\u00a0= 306<\/p>\n

x2<\/sup>\u00a0+ 32x + 87\u00a0= 306<\/p>\n

x2<\/sup>\u00a0+ 32x\u00a0= 273<\/p>\n

x2<\/sup>\u00a0+ 32x –\u00a0273\u00a0= 0<\/p>\n

x2\u00a0<\/sup>+ 39x – 7x –\u00a0273\u00a0= 0<\/p>\n

x2\u00a0<\/sup>+ 39x – 7x –\u00a0273\u00a0=0<\/p>\n

x(x + 39) – 7(x + 39) = 0<\/p>\n

(x + 39) (x\u00a0– 7) = 0<\/p>\n

x + 39\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x\u00a0– 7\u00a0= 0<\/p>\n

x\u00a0= – 39\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a07<\/div>\n
<\/div>\n
\u091a\u0942\u0901\u0915\u093f<\/div>\n
\u0930\u094b\u0939\u0928\u00a0\u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928\u00a0\u0906\u092f\u0941\u00a0\u00a0= 7 \u0935\u0930\u094d\u0937<\/div>\n
\u0930\u094b\u0939\u0928 \u0915\u0940 \u092e\u093e\u0901 \u0915\u0940 \u0906\u092f\u0941 \u00a0=\u00a0\u00a0x + 26<\/div>\n
\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0\u00a0=\u00a0\u00a07\u00a0+ 26<\/p>\n

= 33 \u0935\u0930\u094d\u0937<\/p>\n<\/div>\n

(iv) \u090f\u0915 \u0930\u0947\u0932\u0917\u093e\u095c\u0940\u00a0480 km \u0915\u0940 \u0926\u0941\u0930\u0940 \u0938\u092e\u093e\u0928 \u091a\u093e\u0932 \u0938\u0947 \u0924\u092f \u0915\u0930\u0924\u0940 \u0939\u0948 | \u092f\u0926\u093f \u0907\u0938\u0915\u0940 \u091a\u093e\u0932 8 km\/h \u0915\u092e \u0939\u094b\u0924\u0940, \u0924\u094b \u0935\u0939 \u0909\u0938\u0940 \u0926\u0942\u0930\u0940 \u0915\u094b \u0924\u092f \u0915\u0930\u0928\u0947 \u092e\u0947\u0902 3 \u0918\u0902\u091f\u0947 \u0905\u0927\u093f\u0915 \u0932\u0947\u0924\u0940 | \u0939\u092e\u0947\u0902 \u0930\u0947\u0932\u0917\u093e\u095c\u0940 \u0915\u0940 \u091a\u093e\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0928\u0940\u00a0\u0939\u0948|<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong><\/p>\n

\u092e\u093e\u0928\u093e \u0930\u0947\u0932\u0917\u093e\u095c\u0940 \u0915\u0940 \u0938\u092e\u093e\u0928\u094d\u092f \u091a\u093e\u0932 x km\/h \u0939\u0948 |<\/p>\n

\u0926\u0941\u0930\u0940 = 480 km<\/p>\n

<\/a>\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0935\u0932\u0940 4.2\u00a0<\/strong><\/span><\/p>\n

Ex 4.2 Class 10 \u0917\u0923\u093f\u0924 Q1. \u0917\u0941\u0923\u0928\u0916\u0902\u0921 \u0935\u093f\u0927\u093f \u0938\u0947 \u0928\u093f\u092e\u094d\u0928 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u0947 \u092e\u0942\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f :\u00a0\u00a0<\/strong><\/p>\n

(i) x2\u00a0<\/sup>– 3x – 10 = 0<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>x2\u00a0<\/sup>– 3x – 10 = 0<\/p>\n

x2\u00a0<\/sup>– 5x + 3x\u00a0– 10 = 0<\/p>\n

x(x – 5) + 2(x –\u00a05) = 0<\/p>\n

(x – 5)(x +\u00a02) \u00a0= 0<\/p>\n

x – 5 = 0\u00a0\u0924\u0925\u093e\u00a0x + 2\u00a0= 0<\/p>\n

x\u00a0= 5\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a0– 2<\/div>\n

(ii) 2x2\u00a0<\/sup>\u200b+ x – 6 = 0<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u00a02x2\u00a0<\/sup>\u200b+ x – 6 = 0<\/p>\n

2x2<\/sup>\u00a0+ 4x – 3x – 6\u00a0= 0<\/p>\n

x(x + 2\u00a0) – 3(x + 2) = 0<\/p>\n

(x +\u00a02) (x\u00a0– 3) = 0<\/p>\n

x + 2= 0\u00a0\u0924\u0925\u093e\u00a0x\u00a0– 3\u00a0= 0<\/p>\n

x\u00a0= – 2\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a03<\/div>\n

(iii)\u221a2x2<\/sup>\u00a0+ 7x +\u00a05\u221a2 = 0<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u221a2x2<\/sup>\u00a0+ 7x +\u00a05\u221a2 = 0<\/p>\n

\u221a2x2<\/sup>\u00a0+ 5x + 2x\u00a0+\u00a05\u221a2 = 0<\/p>\n

x(\u221a2x\u00a0+ \u00a05) –\u00a0\u221a2(\u221a2x + 5) = 0<\/p>\n

(\u221a2x\u00a0+ \u00a05) (x\u00a0– \u221a2) = 0<\/p>\n

\u221a2 x\u00a0+ \u00a05 = 0\u00a0\u0924\u0925\u093e x – \u221a2 = 0<\/p>\n

\u221a2x\u00a0= – 5 \u0924\u0925\u093e\u00a0x\u00a0= \u221a2<\/p>\n

x\u00a0= – 5 \/\u221a2 \u0924\u0925\u093e\u00a0x\u00a0= \u221a2<\/p>\n

(iv) 2x2\u00a0<\/sup>– x +\u00a01\/8 = 0\u00a0<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u00a02x2\u00a0<\/sup>\u200b- x + 1\/8 = 0<\/p>\n

2x2\u00a0<\/sup>\u200b- x + 1\/8 = 0<\/p>\n

(v) 100x2\u00a0<\/sup>–\u00a020x + 1 = 0\u00a0<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u00a0 100x2\u00a0<\/sup>–\u00a020x + 1 = \u00a00<\/p>\n

100x2\u00a0<\/sup>–\u00a010x –\u00a010x + 1 = \u00a00<\/p>\n

x(10x – 1) -1(10x – 1) = 0<\/p>\n

(x – 1)(10x –\u00a01) = 0<\/p>\n

10x – 1 = 0\u00a0\u0924\u0925\u093e 10x – 1 = 0<\/p>\n

10x\u00a0= 1 \u0924\u0925\u093e 10x\u00a0=\u00a01<\/div>\n

x\u00a0= 1\/10\u0924\u0925\u093e x\u00a0=\u00a01\/10<\/p>\n

Ex 4.2 Class 10 \u0917\u0923\u093f\u0924\u00a0Q2. \u0909\u0926\u093e\u0939\u0930\u0923 1 \u092e\u0947\u0902 \u0926\u0940 \u0917\u0908 \u0938\u092e\u0938\u094d\u092f\u093e\u0913\u0902 \u0915\u094b \u0939\u0932 \u0915\u0940\u091c\u093f\u090f|<\/strong><\/p>\n

1. \u091c\u0949\u0928 \u0914\u0930 \u091c\u0940\u0935\u0902\u0924\u0940 \u0926\u094b\u0928\u094b\u0902 \u0915\u0947 \u092a\u093e\u0938 \u0915\u0941\u0932 \u092e\u093f\u0932\u093e\u0915\u0930 45 \u0915\u0902\u091a\u0947\u00a0\u0939\u0948\u0902\u0964 \u0926\u094b\u0928\u094b\u0902 \u092a\u093e\u0901\u091a-\u092a\u093e\u0901\u091a \u0915\u0902\u091a\u0947\u00a0\u0916\u094b \u0926\u0947\u0924\u0947 \u0939\u0948\u0902 \u0914\u0930 \u0905\u092c \u0909\u0928\u0915\u0947\u00a0\u092a\u093e\u0938 \u0915\u0902\u091a\u094b\u0902\u00a0\u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u093e \u0917\u0941\u0923\u0928\u092a\u092b\u0932 124 \u0939\u0948\u0964 \u0939\u092e \u091c\u093e\u0928\u0928\u093e \u091a\u093e\u0939\u0947\u0902\u0917\u0947 \u0915\u093f \u0906\u0930\u0902\u092d\u00a0\u092e\u0947\u0902 \u0909\u0928\u0915\u0947 \u092a\u093e\u0938 \u0915\u093f\u0924\u0928\u0947 \u0915\u0902\u091a\u0947 \u0925\u0947\u0964<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u00a0\u091c\u0949\u0928 \u0914\u0930 \u091c\u0940\u0935\u0902\u0924\u0940 \u0926\u094b\u0928\u094b\u0902 \u0915\u0947 \u092a\u093e\u0938 \u0915\u0941\u0932 \u0915\u0902\u091a\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e\u00a0\u0939\u0948\u0902 = 45<\/p>\n

\u092e\u093e\u0928\u093e\u00a0\u091c\u0949\u0928 \u0915\u0947 \u092a\u093e\u0938 \u0915\u0941\u0932 \u0915\u0902\u091a\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e\u00a0\u0939\u0948\u0902 = x<\/p>\n

\u091c\u0940\u0935\u0902\u0924\u0940 \u0915\u0947 \u092a\u093e\u0938 \u0915\u0941\u0932 \u0915\u0902\u091a\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e\u00a0\u0939\u0948\u0902 = 45 – x<\/p>\n

\u0915\u0941\u0932 \u0915\u0902\u091a\u094b\u0902\u00a0\u092a\u093e\u0901\u091a-\u092a\u093e\u0901\u091a \u0915\u0902\u091a\u0947\u00a0\u0916\u094b \u091c\u093e\u0928\u0947 \u0915\u0947 \u092c\u093e\u0926 :-<\/p>\n

\u091c\u0949\u0928 \u0915\u0947 \u092a\u093e\u0938 \u0915\u0941\u0932 \u0915\u0902\u091a\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e\u00a0\u0939\u0948\u0902 = x – 5<\/p>\n

\u091c\u0940\u0935\u0902\u0924\u0940 \u0915\u0947 \u092a\u093e\u0938 \u0915\u0941\u0932 \u0915\u0902\u091a\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e\u00a0\u0939\u0948\u0902 = 45 – x – 5<\/p>\n

= 40 – x<\/p>\n

\u0936\u0947\u0937\u00a0\u0915\u0902\u091a\u094b\u0902\u00a0\u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u093e \u0917\u0941\u0923\u0928\u092a\u092b\u0932 \u0939\u0948 =\u00a0124<\/p>\n

(x – 5)(40 – x) = 306\u00a0124<\/p>\n

40x –\u00a0x2\u00a0<\/sup>–\u00a0200 + 5x\u00a0=\u00a0124<\/p>\n

–\u00a0x2\u00a0<\/sup>\u200b+\u00a040x + 5x\u00a0<\/sup>–\u00a0200 –\u00a0124 = 0<\/p>\n

– x2\u00a0<\/sup>\u200b+\u00a045x\u00a0<\/sup>– 324\u00a0= 0<\/p>\n

x2\u00a0<\/sup>\u200b-\u00a045x\u00a0<\/sup>+ 324\u00a0= 0<\/p>\n

x2\u00a0<\/sup>\u200b- 36x – 9x\u00a0<\/sup>+ 324\u00a0= 0<\/p>\n

x(x – 36\u00a0) –\u00a09(x\u00a0– 36) = 0<\/p>\n

(x – 36)(x –\u00a09) = 0<\/p>\n

x – 36\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x –\u00a09\u00a0= 0<\/p>\n

x\u00a0= 36\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a09<\/p>\n

\u091a\u0942\u0901\u0915\u093f x \u0915\u0947 \u0926\u094b \u092e\u093e\u0928 \u0939\u0948 \u0907\u0938\u0932\u093f\u090f<\/div>\n
<\/div>\n
2. \u090f\u0915 \u0915\u0941\u091f\u0940\u0930 \u0909\u0926\u094d\u092f\u094b\u0917 \u090f\u0915 \u0926\u093f\u0928 \u092e\u0947\u0902 \u0915\u0941\u091b \u0916\u093f\u0932\u094c\u0928\u0947 \u0928\u093f\u0916\u092e\u0924 \u0915\u0930\u0924\u093e \u0939\u0948\u0964 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0916\u093f\u0932\u094c\u0928\u0947 \u0915\u093e \u092e\u0942\u0932\u094d\u092f (\u00a0\u0930\u0941\u092a\u092f\u094b\u0902 \u092e\u0947\u0902 )\u00a055 \u092e\u0947\u0902 \u0938\u0947 \u090f\u0915 \u0926\u093f\u0928 \u092e\u0947\u0902 \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0915\u093f\u090f \u0917\u090f \u0916\u093f\u0932\u094c\u0928\u0947 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u094b \u0918\u091f\u093e\u0928\u0947 \u0938\u0947\u00a0\u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u0947 \u092c\u0930\u093e\u092c\u0930 \u0939\u0948\u0964 \u0915\u093f\u0938\u0940 \u090f\u0915 \u0926\u093f\u0928, \u0915\u0941\u0932 \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0932\u093e\u0917\u0924 750 \u0930\u0941 \u0925\u0940\u0964 \u0939\u092e \u0909\u0938\u00a0\u0926\u093f\u0928 \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0915\u093f\u090f \u0917\u090f \u0916\u093f\u0932\u094c\u0928\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0928\u093e \u091a\u093e\u0939\u0947\u0902\u0917\u0947\u0964<\/strong><\/div>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u0909\u0938 \u0926\u093f\u0928 \u0928\u093f\u0930\u094d\u092e\u093f\u0924\u00a0\u0916\u093f\u0932\u094c\u0928\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e = x<\/p>\n

\u0909\u0938 \u0926\u093f\u0928 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0928\u093f\u0930\u094d\u092e\u093f\u0924\u00a0\u0916\u093f\u0932\u094c\u0928\u094b\u0902 \u0915\u093e \u0932\u093e\u0917\u0924 = \u00a055 – x \u0930\u0941\u092a\u092f<\/p>\n

\u0909\u0938 \u0926\u093f\u0928 \u0915\u0941\u0932 \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0932\u093e\u0917\u0924 = 750<\/p>\n

x(55 – x) = 750<\/p>\n

55x –\u00a0x2<\/sup>\u00a0=\u00a0750<\/p>\n

–\u00a0x2\u00a0<\/sup>\u200b+ 55x – 750\u00a0= 0<\/p>\n

x2\u00a0<\/sup>\u200b-\u00a055x\u00a0<\/sup>+ 750 = 0<\/p>\n

x2\u00a0<\/sup>\u200b- 30x – 25x\u00a0<\/sup>+ 750 = 0<\/p>\n

x(x – 30\u00a0) –\u00a025(x\u00a0– 30) = 0<\/p>\n

(x – 30)(x – 25) = 0<\/p>\n

x – 30\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x – 25 = 0<\/p>\n

x\u00a0= 30\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a025<\/p>\n

\u092e\u093e\u0928\u093e \u0909\u0938 \u0926\u093f\u0928 \u0928\u093f\u0930\u094d\u092e\u093f\u0924\u00a0\u0916\u093f\u0932\u094c\u0928\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e = x<\/div>\n
\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 = 25<\/div>\n

\u0909\u0938 \u0926\u093f\u0928 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0928\u093f\u0930\u094d\u092e\u093f\u0924\u00a0\u0916\u093f\u0932\u094c\u0928\u094b\u0902 \u0915\u093e \u0932\u093e\u0917\u0924 = 55 – x<\/p>\n

= \u00a055 – 25<\/p>\n

= 30 \u0930\u0942\u092a\u092f<\/p>\n

Ex 4.2 Class 10 \u0917\u0923\u093f\u0924\u00a0Q3. \u0910\u0938\u0940 \u0926\u094b \u0938\u0902\u0916\u094d\u092f\u093e\u090f\u0901 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f, \u091c\u093f\u0928\u0915\u093e \u092f\u094b\u0917 27 \u0939\u094b \u0914\u0930 \u0917\u0941\u0923\u0928\u092b\u0932 182 \u0939\u094b |<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u0938\u0902\u0916\u094d\u092f\u093e\u0913\u0902 \u0915\u093e\u00a0\u092f\u094b\u0917 =\u00a027<\/p>\n

\u0938\u0902\u0916\u094d\u092f\u093e\u0913\u0902 \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 =\u00a0182<\/p>\n

\u092e\u093e\u0928\u093e \u092a\u0939\u0932\u0940\u00a0\u0938\u0902\u0916\u094d\u092f\u093e = x<\/p>\n

\u0926\u0942\u0938\u0930\u0940 \u0938\u0902\u0916\u094d\u092f\u093e = x + 1<\/p>\n

\u0926\u094b\u0928\u094b\u0902 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 = 182<\/p>\n

x(27 – x) = 182<\/p>\n

27x –\u00a0x2<\/sup>\u00a0=\u00a0182<\/p>\n

–\u00a0x2\u00a0<\/sup>\u200b+ 27x – 182= 0<\/p>\n

x2\u00a0<\/sup>\u200b-\u00a027x\u00a0<\/sup>+ 182 = 0<\/p>\n

x2\u00a0<\/sup>\u200b- 14x – 13x\u00a0<\/sup>+ 182 = 0<\/p>\n

x(x – 14 ) –\u00a013(x\u00a0– 14) = 0<\/p>\n

(x – 14)(x – 13) = 0<\/p>\n

x – 14 = 0\u00a0\u0924\u0925\u093e\u00a0x – 13 = 0<\/p>\n

x\u00a0= 14 \u0924\u0925\u093e\u00a0x\u00a0=13<\/div>\n

\u092a\u0939\u0932\u0940\u00a0\u0938\u0902\u0916\u094d\u092f\u093e = x<\/p>\n

= 13<\/p>\n

\u0926\u0942\u0938\u0930\u0940 \u0938\u0902\u0916\u094d\u092f\u093e = x\u00a0+ 1<\/p>\n

= 13 + 1<\/p>\n

= 14<\/p>\n

Ex 4.2 Class 10 \u0917\u0923\u093f\u0924\u00a0Q4. \u0926\u094b \u0915\u094d\u0930\u092e\u093e\u0917\u0924 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0902\u0915 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f \u091c\u093f\u0928\u0915\u0947 \u0935\u0930\u094d\u0917\u094b\u0902 \u0915\u093e \u092f\u094b\u0917 365 \u0939\u094b |<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u0926\u094b\u00a0\u0915\u094d\u0930\u092e\u093e\u0917\u0924 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u094b\u0902 \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 \u00a0= 306<\/p>\n

\u092e\u093e\u0928\u093e \u092a\u0939\u0932\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0\u00a0= x<\/p>\n

\u0926\u0942\u0938\u0930\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0 =\u00a0x + 1\u00a0\u00a0<\/sup><\/p>\n

\u0926\u094b\u0928\u094b\u0902 \u0915\u094d\u0930\u092e\u093e\u0917\u0924 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u0947\u00a0\u0935\u0930\u094d\u0917\u094b\u0902 \u0915\u093e \u092f\u094b\u0917 \u00a0=\u00a0\u00a0365<\/p>\n

(x)2<\/sup>\u00a0+\u00a0(x + 1)2<\/sup>\u00a0\u00a0 \u00a0= 365<\/p>\n

x2<\/sup>\u00a0+ x2\u00a0<\/sup>+ 2x\u00a0+ 1\u00a0= 365<\/p>\n

2x2<\/sup>\u00a0\u00a0<\/sup>+ 2x\u00a0+ 1\u00a0=\u00a0365<\/p>\n

2x2<\/sup>\u00a0<\/sup>+ 2x + 1 – 365\u00a0= 0<\/p>\n

2x2<\/sup>\u00a0<\/sup>+ 2x + 1 – 365\u00a0= 0<\/p>\n

2x2<\/sup>\u00a0<\/sup>+ 2x\u00a0– 364\u00a0= 0<\/p>\n

2(x2<\/sup>\u00a0<\/sup>+ x\u00a0– 182)\u00a0= 0<\/p>\n

x2<\/sup>\u00a0<\/sup>+ x\u00a0– 182 = 0\/2<\/p>\n

x2<\/sup>\u00a0<\/sup>+ x\u00a0– 182 = 0<\/p>\n

x2<\/sup>\u00a0<\/sup>+ 14x – 13x – 182 = 0<\/p>\n

x(x + 14) – 13(x +\u00a0<\/sup>14) = 0<\/p>\n

(x +\u00a014) (x\u00a0– 13)\u00a0= 0<\/p>\n

x + 14\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x\u00a0– 13\u00a0= 0<\/p>\n

x\u00a0= – 14\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a013<\/div>\n
<\/div>\n
\u091a\u0942\u0901\u0915\u093f<\/div>\n
\u092a\u0939\u0932\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0= x<\/div>\n
\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0= 13<\/p>\n

\u0926\u0942\u0938\u0930\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0\u00a0=\u00a0x + 1<\/p>\n

= 13\u00a0+ 1<\/p>\n<\/div>\n

= 14<\/p>\n

Ex 4.2 Class 10 \u0917\u0923\u093f\u0924\u00a0Q5. \u090f\u0915 \u0938\u092e\u0915\u094b\u0923 \u0924\u094d\u0930\u093f\u092d\u0941\u091c \u0915\u0940 \u090a\u0901\u091a\u093e\u0908 \u0907\u0938\u0915\u0947 \u0906\u0927\u093e\u0930 \u0938\u0947 7 cm \u0915\u092e \u0939\u0948 | \u092f\u0926\u093f \u0915\u0930\u094d\u0923 13 cm \u0915\u093e \u0939\u094b, \u0924\u094b \u0905\u0928\u094d\u092f \u0926\u094b \u092d\u0941\u091c\u093e\u090f\u0901 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u0938\u092e\u0915\u094b\u0923 \u0924\u094d\u0930\u093f\u092d\u0941\u091c \u0915\u093e \u0906\u0927\u093e\u0930 = x cm\u00a0<\/strong><\/p>\n

\u0938\u092e\u0915\u094b\u0923 \u0924\u094d\u0930\u093f\u092d\u0941\u091c \u0915\u0940 \u090a\u0901\u091a\u093e\u0908 =\u00a0x – 7cm<\/p>\n

\u0938\u092e\u0915\u094b\u0923 \u0924\u094d\u0930\u093f\u092d\u0941\u091c \u092e\u0947\u0902 \u0915\u0930\u094d\u0923 = 13 cm<\/p>\n

\u092a\u093e\u0908\u0925\u093e\u0917\u094b\u0930\u0938 \u092a\u094d\u0930\u092e\u0947\u092f \u0915\u0947 \u092a\u094d\u0930\u092f\u094b\u0917 \u0938\u0947
\n(\u0915\u0930\u094d\u0923)2<\/sup>\u00a0= (\u090a\u0901\u091a\u093e\u0908)2<\/sup>\u00a0+\u00a0(\u0906\u0927\u093e\u0930)2<\/sup><\/p>\n

AC2<\/sup>\u00a0= AB2<\/sup>\u00a0+ BC)2<\/sup><\/p>\n

(13)2<\/sup>\u00a0= (x – 7)2<\/sup>\u00a0+\u00a0(x)2<\/sup><\/p>\n

169\u00a0=\u00a0x2<\/sup>\u00a0– 14x + 49\u00a0+ x2<\/sup><\/p>\n

169 –\u00a049= 2x2<\/sup>\u00a0– 14x<\/div>\n

120 = 2(x2<\/sup>\u00a0– 7x)<\/p>\n

x2<\/sup>\u00a0– 7x = 2\/120<\/p>\n

x2<\/sup>\u00a0<\/sup>– 7x – 60 = 0<\/p>\n

x2<\/sup>\u00a0<\/sup>– 12x + 5x – 60\u00a0= 0<\/p>\n

x(x – 12) + 5(x –\u00a0<\/sup>12) = 0<\/p>\n

(x –\u00a012) (x + 5)\u00a0= 0<\/p>\n

x – 12\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x + 5\u00a0= 0<\/p>\n

x\u00a0= 12\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a0– 5<\/div>\n
<\/div>\n
\u091a\u0942\u0901\u0915\u093f<\/div>\n
\n

\u0938\u092e\u0915\u094b\u0923 \u0924\u094d\u0930\u093f\u092d\u0941\u091c \u0915\u093e \u0906\u0927\u093e\u0930 = x cm\u00a0<\/strong><\/p>\n

= 12 cm<\/p>\n

\u0938\u092e\u0915\u094b\u0923 \u0924\u094d\u0930\u093f\u092d\u0941\u091c \u0915\u0940 \u090a\u0901\u091a\u093e\u0908 =\u00a0x – 7 cm<\/p>\n<\/div>\n

\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 = 12 – 7<\/p>\n<\/div>\n

= 5 cm<\/p>\n

Ex 4.2 Class 10 \u0917\u0923\u093f\u0924\u00a0Q6. \u090f\u0915 \u0915\u0941\u091f\u0940\u0930 \u0909\u0927\u094b\u0917 \u090f\u0915 \u0926\u093f\u0928 \u092e\u0947\u0902 \u0915\u0941\u091b \u092c\u0930\u094d\u0924\u0928\u094b\u0902 \u0915\u093e \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0915\u0930\u0924\u093e \u0939\u0948 | \u090f\u0915 \u0935\u093f\u0936\u0947\u0937 \u0926\u093f\u0928 \u092f\u0939 \u0926\u0947\u0916\u093e \u0917\u092f\u093e \u0915\u0940 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0928\u093e\u0917 \u0915\u0940 \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0932\u093e\u0917\u0924 (\u0930\u0941\u092a\u092f\u094b\u0902 \u092e\u0947\u0902) \u0909\u0938 \u0926\u093f\u0928 \u0915\u0947 \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0915\u093f\u090f \u092c\u0930\u094d\u0924\u0928\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u0947 \u0926\u0941\u0917\u0941\u0928\u0947 \u0938\u0947 3 \u0905\u0927\u093f\u0915 \u0925\u0940 | \u092f\u0926\u093f \u0909\u0938 \u0926\u093f\u0928 \u0915\u0940 \u0915\u0941\u0932 \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0932\u093e\u0917\u0924 90 \u0930\u0942\u092a\u090f \u0925\u0940, \u0924\u094b \u0928\u093f\u0930\u094d\u092e\u093f\u0924 \u092c\u0930\u094d\u0924\u0928\u094b\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0914\u0930 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0928\u093e\u0917 \u0915\u0940 \u0932\u093e\u0917\u0924 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u092e\u093e\u0928\u093e \u0909\u0938 \u0926\u093f\u0928 \u0928\u093f\u0930\u094d\u092e\u093f\u0924 \u092c\u0930\u094d\u0924\u0928\u094b\u0902\u00a0\u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e = x<\/p>\n

\u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0928\u093e\u0917 \u0915\u0940 \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0932\u093e\u0917\u0924\u00a0= \u00a02x + 3<\/p>\n

\u0909\u0938 \u0926\u093f\u0928 \u0915\u0940 \u0915\u0941\u0932 \u0928\u093f\u0930\u094d\u092e\u093e\u0923 \u0932\u093e\u0917\u0924 = 90 \u0930\u0941\u092a\u092f\u0947<\/p>\n

x(2x + 3) = 90<\/p>\n

2x2\u00a0<\/sup>+ 3x\u00a0= 9<\/p>\n

2x2\u00a0<\/sup>+ 3x – 90 = 0<\/p>\n

2x2\u00a0<\/sup>\u200b+ 15x – 12x\u00a0<\/sup>– 90\u00a0= 0<\/p>\n

x(2x +\u00a015) –\u00a06(2x +\u00a015) = 0<\/p>\n

(2x +\u00a015)(x – 6) = 0<\/p>\n

2x +\u00a015\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x – 6 = 0<\/p>\n

x\u00a0= – 15 \u0924\u0925\u093e\u00a0x\u00a0=\u00a06<\/div>\n
<\/div>\n
\u092e\u093e\u0928\u093e \u0909\u0938 \u0926\u093f\u0928 \u0928\u093f\u0930\u094d\u092e\u093f\u0924 \u092c\u0930\u094d\u0924\u0928\u094b\u0902 \u00a0\u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e = x<\/div>\n
\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 = 6<\/div>\n
\n

\u0909\u00a0\u0938 \u0926\u093f\u0928 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0928\u093f\u0930\u094d\u092e\u093f\u0924\u00a0\u092c\u0930\u094d\u0924\u0928\u094b\u0902\u00a0\u0915\u093e \u0932\u093e\u0917\u0924 = 2x + 3<\/p>\n

= \u00a02 x 6 + 3<\/p>\n

= 12 + 3<\/p>\n

= 15\u00a0\u0930\u0942\u092a\u092f\u0947<\/p>\n

<\/a>\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0935\u0932\u0940 4.3<\/strong><\/span><\/p>\n

Ex 4.2 Class 10 \u0917\u0923\u093f\u0924 Q1. \u092f\u0926\u093f \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u0947 \u092e\u0942\u0932\u094b\u0902 \u0915\u093e \u0905\u0938\u094d\u0924\u093f\u0924\u094d\u0935 \u0939\u094b \u0924\u094b \u0907\u0928\u094d\u0939\u0947\u0902 \u092a\u0942\u0930\u094d\u0923 \u0935\u0930\u094d\u0917 \u092c\u0928\u093e\u090f \u0915\u0940 \u0935\u093f\u0927\u093f \u0926\u094d\u0935\u093e\u0930\u093e \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

(i)\u00a0 2x2<\/sup>\u00a0– 7x + 3 = 0<\/p>\n

(ii)\u00a0\u00a02x2<\/sup>\u00a0+ x – 4 = 0<\/p>\n

(iii)\u00a04x2<\/sup>\u00a0+4 3x + 3 = 0<\/p>\n

(iv) 2x2<\/sup>\u00a0+ x + 4 = 0<\/p>\n

\u0939\u0932 :\u00a0<\/strong>2x2\u00a0<\/sup>– 7x + 3 = 0<\/p>\n

a = 2, b = -7 \u0914\u0930 c = 3<\/p>\n

D = b2\u00a0<\/sup>– 4ac<\/p>\n

D = (7)2\u00a0<\/sup>– 4x2x3<\/p>\n

D = 49 – 24<\/p>\n

D = 25<\/p>\n

b2\u00a0<\/sup>– 4ac\u00a0> 0 \u0905\u0930\u094d\u0925\u093e\u0924 D > 0 \u0905\u0924: \u0907\u0938 \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u0947 \u0926\u094b \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u090f\u0935\u0902 \u0905\u0938\u092e\u093e\u0928 \u092e\u0942\u0932 \u0939\u094b\u0902\u0917\u0947\u00a0|<\/p>\n

2x2\u00a0<\/sup>– 7x + 3 = 0<\/p>\n

\u0926\u094b\u0928\u094b\u0902 \u092a\u0915\u094d\u0937\u094b\u0902 \u092e\u0947\u0902 8 \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\n

8(2x2\u00a0<\/sup>– 7x + 3 = 0)<\/p>\n

16x2\u00a0<\/sup>– 56x + 24 = 0<\/p>\n

( (4x)2\u00a0<\/sup>– 2.4x.7\u00a0+\u00a0(7)2\u00a0<\/sup>) – (7)2<\/sup>\u00a0+ 24\u00a0= 0 \u00a0 ( a2<\/sup>\u00a0<\/sup>– 2ab + b2<\/sup>\u00a0=\u00a0(a –\u00a0b)2<\/sup>\u00a0)<\/p>\n

(4x – 7)2\u00a0<\/sup>– 49\u00a0+ 24\u00a0= 0<\/p>\n

(4x – 7)2\u00a0<\/sup>– 25 = 0<\/p>\n

(4x – 7)2\u00a0<\/sup>= 25<\/p>\n

4x – 7\u00a0<\/sup>= 25<\/p>\n

\"NCERT<\/p>\n

\u0939\u0932 :<\/strong>\u00a0(ii)\u00a0\u00a02x2\u00a0<\/sup>+\u00a0x – 4 = 0<\/p>\n

a = 2, b =\u00a01\u00a0\u0914\u0930\u00a0c = -4<\/p>\n

D = b2\u00a0<\/sup>– 4ac<\/p>\n

D = (1)2\u00a0<\/sup>– 4x2x(-3)<\/p>\n

D = 1 + 24<\/p>\n

D = 25<\/p>\n

b2\u00a0<\/sup>– 4ac\u00a0> 0<\/p>\n

\u0905\u0924: \u0907\u0938 \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u0947 \u0926\u094b \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u0914\u0930 \u0905\u0938\u092e\u093e\u0928 \u092e\u0942\u0932 \u0939\u094b\u0902\u0917\u0947\u00a0|<\/p>\n

2x2\u00a0<\/sup>+\u00a0x – 4 = 0<\/p>\n

\u0926\u094b\u00a0\u0938\u0947 \u092d\u093e\u0917 \u0926\u0947\u0928\u0947 \u092a\u0930<\/p>\n

\"NCERT
\n\"NCERT<\/p>\n

\u0905\u0924: \u0907\u0938 \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u0947 \u0926\u094b \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u0914\u0930 \u0905\u0938\u092e\u093e\u0928 \u092e\u0942\u0932 \u0939\u094b\u0902\u0917\u0947\u00a0|<\/p>\n

2x2\u00a0<\/sup>+\u00a0x – 4 = 0<\/p>\n

\u0926\u094b\u00a0\u0938\u0947 \u092d\u093e\u0917 \u0926\u0947\u0928\u0947 \u092a\u0930<\/p>\n

\"Maths<\/p>\n

\u0939\u0932 :<\/strong>\u00a0(iv) 2x2<\/sup>\u00a0+ x + 4 = 0<\/p>\n

a = 2, b = 1, c = 4<\/p>\n

D = b2\u00a0<\/sup>– 4ac<\/p>\n

D = (1)2\u00a0<\/sup>– 4 \u00d7 2 \u00d7 4<\/p>\n

D = 1\u00a0–\u00a032<\/p>\n

D = -31<\/p>\n

b2\u00a0<\/sup>– 4ac\u00a0< 0\u00a0\u0905\u0930\u094d\u0925\u093e\u0924 D < 0<\/p>\n

\u0905\u0924: \u0907\u0938 \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u093e \u0915\u094b\u0908 \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u092e\u0942\u0932 \u0928\u0939\u0940\u0902 \u0939\u0948\u00a0|<\/p>\n

Ex 4.3 Class 10 \u0917\u0923\u093f\u0924\u00a0<\/strong>Q2. \u0909\u092a\u0930\u094d\u092f\u0941\u0915\u094d\u0924 \u092a\u094d\u0930\u0936\u094d\u0928 1 \u092e\u0947\u0902 \u0926\u093f\u090f \u0917\u090f \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u0947 \u092e\u0942\u0932, \u0926\u094d\u0935\u093f\u0918\u093e\u0924\u0940 \u0938\u0942\u0924\u094d\u0930 \u0915\u093e \u0909\u092a\u092f\u094b\u0917 \u0915\u0930\u0915\u0947, \u091c\u094d\u091e\u093e\u0924 \u00a0\u0915\u0940\u091c\u093f\u090f |<\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092a\u094d\u0930\u0936\u094d\u0928 1 \u092e\u0947\u0902 \u0935\u0947 \u092a\u094d\u0930\u0936\u094d\u0928 \u091c\u093f\u0928\u0915\u093e \u092e\u0942\u0932\u094b\u0902 \u0915\u093e \u0905\u0938\u094d\u0924\u093f\u0924\u094d\u0935 \u0939\u0948 –<\/p>\n

(i)\u00a0 2x2<\/sup>\u00a0– 7x + 3 = 0<\/p>\n

(ii)\u00a0\u00a02x2<\/sup>\u00a0+ x – 4 = 0<\/p>\n

\"NCERT<\/p>\n

\u0939\u0932 :<\/strong>\u00a0(i)\u00a0 2x2<\/sup>\u00a0– 7x + 3 = 0<\/p>\n

\u0926\u094d\u0935\u093f\u0918\u093e\u0924\u0940 \u0938\u0942\u0924\u094d\u0930 \u0926\u094d\u0935\u093e\u0930\u093e :<\/p>\n

a = 2, b = – 7, c = 3<\/p>\n

\"NCERT<\/p>\n

\u0939\u0932 :<\/strong>\u00a0(ii)\u00a0\u00a02x2<\/sup>\u00a0+ x – 4 = 0<\/p>\n

\u0926\u094d\u0935\u093f\u0918\u093e\u0924\u0940 \u0938\u0942\u0924\u094d\u0930 \u0926\u094d\u0935\u093e\u0930\u093e :<\/p>\n

a = 2, b = 1, c = – 4<\/p>\n

\"Solutions
\n\"NCERT<\/p>\n

Ex 4.3 Class 10 \u0917\u0923\u093f\u0924\u00a0Q3. \u0928\u093f\u092e\u094d\u0928 \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u0947 \u092e\u0942\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f :<\/strong><\/p>\n

\"Maths<\/p>\n

\u0926\u094d\u0935\u093f\u0918\u093e\u0924\u0940\u00a0\u0938\u0942\u0924\u094d\u0930 \u0938\u0947 –<\/p>\n

\"Solutions
\n\"NCERT
\n\"NCERT<\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u0930\u0939\u092e\u093e\u0928 \u0915\u0940 \u0935\u0930\u094d\u0924\u094d\u0924\u092e\u093e\u0928 \u0906\u092f\u0941 x \u0935\u0930\u094d\u0937 \u0939\u0948 |<\/p>\n

\u0924\u094b \u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0928\u0941\u0938\u093e\u0930, 3 \u0935\u0930\u094d\u0937 \u092a\u0942\u0930\u094d\u0935 \u0930\u0939\u092e\u093e\u0928 \u0915\u0940 \u0906\u092f\u0941 = x – 3 \u0935\u0930\u094d\u0937<\/p>\n

\"CBSE<\/p>\n

=>\u00a0x2<\/sup>\u00a0+ 2x – 15 = 3(2x + 2)<\/p>\n

=>\u00a0x2<\/sup>\u00a0+ 2x – 15 = 6x + 6<\/p>\n

=>\u00a0x2<\/sup>\u00a0+ 2x – 6x – 15 – 6 = 0<\/p>\n

=>\u00a0x2<\/sup>\u00a0– 4x – 21 = 0<\/p>\n

=> x2<\/sup>\u00a0– 7x + 3x – 21 = 0<\/p>\n

=> x(x – 7) + 3(x – 7) = 0<\/p>\n

=> (x – 7) (x + 3) = 0<\/p>\n

=> x – 7 = 0, x + 3 = 0<\/p>\n

=> x = 7 \u0914\u0930 x = – 3<\/p>\n

\u0905\u0924: \u0935\u0930\u094d\u0924\u094d\u0924\u092e\u093e\u0928 \u0906\u092f\u0941 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u0938\u0902\u0916\u094d\u092f\u093e 7 \u0932\u0947\u0902\u0917\u0947 | \u0905\u0924: \u0930\u0939\u092e\u093e\u0928 \u0915\u0940 \u0935\u0930\u094d\u0924\u094d\u0924\u092e\u093e\u0928 \u0906\u092f\u0941 7 \u0935\u0930\u094d\u0937 \u0939\u0948 |<\/p>\n

Ex 4.3 Class 10 \u0917\u0923\u093f\u0924\u00a0Q5. \u090f\u0915 \u0915\u094d\u0932\u093e\u0938 \u091f\u0947\u0938\u094d\u091f \u092e\u0947\u0902 \u0936\u0947\u092b\u093e\u0932\u0940 \u0915\u0947 \u0917\u0923\u093f\u0924 \u0914\u0930 \u0905\u0902\u0917\u094d\u0930\u0947\u091c\u0940 \u092e\u0947\u0902 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0915\u093f\u090f \u0917\u090f \u0905\u0902\u0915\u094b\u0902 \u0915\u093e \u092f\u094b\u0917 30 \u0939\u0948 |\u00a0\u092f\u0926\u093f \u0909\u0938\u0915\u094b \u0917\u0923\u093f\u0924 \u092e\u0947\u0902 2 \u0905\u0902\u0915 \u0905\u0927\u093f\u0915 \u0914\u0930 \u0905\u0902\u0917\u094d\u0930\u0947\u091c\u0940 \u092e\u0947\u0902 3 \u0905\u0902\u0915 \u0915\u092e \u092e\u093f\u0932\u0947 \u0939\u094b\u0924\u0947, \u0924\u094b \u0909\u0928\u0915\u0947 \u0905\u0902\u0915\u094b\u0902 \u0915\u093e\u00a0\u0917\u0941\u0923\u0928\u092b\u0932 210 \u0939\u094b\u0924\u093e | \u0909\u0938\u0915\u0947 \u0926\u094d\u0935\u093e\u0930\u093e \u0926\u094b\u0928\u094b\u0902 \u0935\u093f\u0937\u092f\u094b\u0902 \u092e\u0947\u0902 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0915\u093f\u090f \u0905\u0902\u0915 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u0917\u0923\u093f\u0924 \u092e\u0947\u0902 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0905\u0902\u0915 x \u0939\u0948 |<\/p>\n

\u0907\u0938\u0932\u093f\u090f, \u0905\u0902\u0917\u094d\u0930\u0947\u091c\u0940 \u092e\u0947\u0902 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0905\u0902\u0915 = 30 – x<\/p>\n

\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0928\u0941\u0938\u093e\u0930, (x + 2) (30 – x – 3) = 210<\/p>\n

\u092f\u093e\u00a0\u00a0 (x + 2) (27 – x) = 210<\/p>\n

\u092f\u093e\u00a0\u00a0\u00a027x – x2<\/sup>\u00a0+ 54 – 2x = 210<\/p>\n

\u092f\u093e\u00a0\u00a0\u00a025x – x2<\/sup>\u00a0+ 54 = 210<\/p>\n

\u092f\u093e\u00a0\u00a0\u00a0x2<\/sup>\u00a0– 25x + 210 – 54 = 0<\/p>\n

\u092f\u093e\u00a0\u00a0\u00a0x2<\/sup>\u00a0– 25x + 156 = 0<\/p>\n

\u092f\u093e\u00a0\u00a0\u00a0x2<\/sup>\u00a0– 12x – 13x + 156 = 0<\/p>\n

\u092f\u093e\u00a0\u00a0\u00a0x(x – 12) – 13(x – 12) = 0<\/p>\n

\u092f\u093e\u00a0\u00a0\u00a0(x – 12) (x – 13) = 0<\/p>\n

\u092f\u093e\u00a0\u00a0\u00a0x – 12 = 0, x – 13 = 0<\/p>\n

\u092f\u093e\u00a0\u00a0\u00a0x = 12\u00a0\u0905\u0925\u0935\u093e\u00a0x = 13<\/p>\n

\u0905\u092c \u092f\u0926\u093f x = 12 \u0924\u094b \u0917\u0923\u093f\u0924 \u092e\u0947\u0902 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0905\u0902\u0915 = 12 \u0914\u0930 \u0905\u0902\u0917\u094d\u0930\u0947\u091c\u0940 \u092e\u0947\u0902 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0905\u0902\u0915 = 30 – 12 = 18<\/p>\n

\u0914\u0930 \u092f\u0926\u093f x = 13 \u0924\u094b \u0917\u0923\u093f\u0924 \u092e\u0947\u0902 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0905\u0902\u0915 = 13 \u0914\u0930 \u0905\u0902\u0917\u094d\u0930\u0947\u091c\u0940 \u092e\u0947\u0902 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0905\u0902\u0915 = 30 – 13 = 17<\/p>\n

Ex 4.3 Class 10 \u0917\u0923\u093f\u0924\u00a0Q6. \u090f\u0915 \u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u0916\u0947\u0924 \u0915\u093e \u0935\u093f\u0915\u0930\u094d\u0923 \u0909\u0938\u0915\u0940 \u091b\u094b\u091f\u0940 \u092d\u0941\u091c\u093e \u0938\u0947 60 \u092e\u0940\u091f\u0930 \u0905\u0927\u093f\u0915 \u0932\u0902\u092c\u093e \u0939\u0948 | \u092f\u0926\u093f \u092c\u095c\u0940 \u092d\u0941\u091c\u093e \u091b\u094b\u091f\u0940 \u092d\u0941\u0901\u091c\u093e \u0938\u0947 30 \u092e\u0940\u091f\u0930 \u0905\u0927\u093f\u0915 \u0939\u094b, \u0924\u094b \u0916\u0947\u0924 \u0915\u0940 \u092d\u0941\u091c\u093e\u090f\u0901 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

\"NCERT<\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u0938\u092c\u0938\u0947 \u091b\u094b\u091f\u0940 \u092d\u0941\u091c\u093e = x m<\/p>\n

\u0924\u094b \u092c\u095c\u0940 \u092d\u0941\u091c\u093e = x + 30 m \u0914\u0930<\/p>\n

\u0935\u093f\u0915\u0930\u094d\u0923 = x + 60 m<\/p>\n

\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0928\u0941\u0938\u093e\u0930,<\/p>\n

\u091a\u0942\u0901\u0915\u093f ABCD \u090f\u0915 \u0906\u092f\u0924 \u0939\u0948 \u091c\u093f\u0938\u0915\u093e \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0915\u094b\u0923 \u0938\u092e\u0915\u094b\u0923 \u0939\u0948 \u0907\u0938\u0932\u093f\u090f\u00a0ABC\u00a0\u092e\u0947\u0902,<\/p>\n

\u092a\u0948\u0925\u093e\u0917\u094b\u0930\u0938 \u092a\u094d\u0930\u092e\u0947\u092f \u0915\u0947 \u092a\u094d\u0930\u092f\u094b\u0917 \u0938\u0947 –<\/p>\n

AC2<\/sup>\u00a0= AB2<\/sup>\u00a0+ BC2<\/sup><\/p>\n

=> (x + 60)2<\/sup>\u00a0= (x)2<\/sup>\u00a0+ (x + 30)2<\/sup><\/p>\n

=> x2<\/sup>\u00a0+ 120x + 3600 = x2<\/sup>\u00a0+ x2<\/sup>\u00a0+ 60x + 900<\/p>\n

=> x2<\/sup>\u00a0+ 120x + 3600 = 2x2<\/sup>\u00a0+ 60x + 900<\/p>\n

=> 2x2<\/sup>\u00a0– x2<\/sup>\u00a0+ 60x – 120x + 900 – 3600 = 0<\/p>\n

=> x2<\/sup>\u00a0– 60x – 2700 = 0<\/p>\n

=> x2<\/sup>\u00a0– 90x + 30x – 2700 = 0<\/p>\n

=> x(x – 90) + 30(x – 90) = 0<\/p>\n

=> (x – 90) (x + 30) = 0<\/p>\n

=> x – 90 = 0, x + 30 = 0<\/p>\n

=> x = 90 \u0914\u0930 x = – 30<\/p>\n

\u091a\u0942\u0901\u0915\u093f \u0906\u092f\u0924\u093e \u0915\u0940 \u0932\u0902\u092c\u093e\u0908 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u0939\u094b\u0924\u0940 \u0939\u0948 \u0907\u0938\u0932\u093f\u090f x = 90 \u090b\u0923\u093e\u0924\u094d\u092e\u0915 \u0928\u0939\u0940\u0902 \u0939\u094b\u0924\u0940<\/p>\n

\u0905\u0924: \u091b\u094b\u091f\u0940 \u092d\u0941\u091c\u093e = 90 m<\/p>\n

\u0924\u094b \u092c\u095c\u0940 \u092d\u0941\u091c\u093e = 90 + 30 = 120 m<\/p>\n

\u0914\u0930 \u0935\u093f\u0915\u0930\u094d\u0923 = 90 + 60 = 150 m<\/p>\n

Ex 4.3 Class 10 \u0917\u0923\u093f\u0924\u00a0Q7. \u0926\u094b \u0938\u0902\u0916\u094d\u092f\u093e\u0913\u0902 \u0915\u0947 \u0935\u0930\u094d\u0917\u094b\u0902 \u0915\u093e \u0905\u0928\u094d\u0924\u0930 180 \u0939\u0948 | \u091b\u094b\u091f\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u093e \u0935\u0930\u094d\u0917 \u092c\u095c\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u093e \u0906\u0920 \u0917\u0941\u0923\u093e \u0939\u0948 | \u0926\u094b\u0928\u094b\u0902 \u0938\u0902\u0916\u094d\u092f\u093e\u090f\u0901 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u092c\u095c\u0940 \u0938\u0902\u0916\u094d\u092f\u093e = x<\/p>\n

\u0924\u094b \u091b\u094b\u091f\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u093e \u0935\u0930\u094d\u0917 = 8x<\/p>\n

\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0928\u0941\u0938\u093e\u0930,<\/p>\n

\u092c\u095c\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u093e \u0935\u0930\u094d\u0917 – \u091b\u094b\u091f\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0915\u093e \u0935\u0930\u094d\u0917 = 180<\/p>\n

x2<\/sup>\u00a0– 8x = 180<\/p>\n

\u092f\u093e\u00a0 x2<\/sup>\u00a0– 8x – 180 = 0<\/p>\n

=>\u00a0 x2<\/sup>\u00a0– 18x + 10x – 180 = 0<\/p>\n

=> x(x – 18) + 10(x – 18) = 0<\/p>\n

=> (x – 18) (x + 10) = 0<\/p>\n

=> x – 18 = 0, x + 10 = 0<\/p>\n

=> x = 18 \u0914\u0930 x = -10<\/p>\n

\u0905\u0924: \u092c\u095c\u0940 \u0938\u0902\u0916\u094d\u092f\u093e 18 \u0939\u0948, x = – 10 \u0928\u0939\u0940\u0902 \u0932\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e |<\/p>\n

\u0905\u092c (\u091b\u094b\u091f\u0940 \u0938\u0902\u0916\u094d\u092f\u093e)2<\/sup>\u00a0= 8 \u00d7 18 = 144<\/p>\n

\"NCERT<\/p>\n

Ex 4.3 Class 10 \u0917\u0923\u093f\u0924\u00a0Q8. \u090f\u0915 \u0930\u0947\u0932\u0917\u093e\u095c\u0940 \u090f\u0915 \u0938\u092e\u093e\u0928 \u091a\u093e\u0932 \u0938\u0947 360km \u0915\u0940 \u0926\u0941\u0930\u0940 \u0924\u092f \u0915\u0930\u0924\u0940 \u0939\u0948 | \u092f\u0926\u093f \u092f\u0939 \u091a\u093e\u0932 5 km\/h\u00a0\u0905\u0927\u093f\u0915 \u0939\u094b\u0924\u0940, \u0924\u094b \u0935\u0939 \u0909\u0938\u0940 \u092f\u093e\u0924\u094d\u0930\u093e \u092e\u0947\u0902 1 \u0918\u0902\u091f\u093e \u0915\u092e \u0938\u092e\u092f \u0932\u0947\u0924\u0940 | \u0930\u0947\u0932\u0917\u093e\u095c\u0940 \u0915\u0940 \u091a\u093e\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u0930\u0947\u0932\u0917\u093e\u095c\u0940 \u0915\u0940 \u0938\u092e\u093e\u0928\u094d\u092f \u091a\u093e\u0932 = x km\/h<\/p>\n

\u0924\u092f \u0926\u0941\u0930\u0940 = 360 km<\/p>\n

\"CBSE<\/p>\n

\u091a\u093e\u0932 \u092c\u095d\u0928\u0947 \u0938\u0947 \u0938\u092e\u092f \u0918\u091f \u091c\u093e\u0924\u093e \u0939\u0948 \u091a\u093e\u0932 \u0918\u091f\u093e \u0926\u0947\u0928\u0947 \u0938\u0947 \u0932\u093f\u092f\u093e \u0917\u092f\u093e \u0938\u092e\u092f \u092c\u095d \u091c\u093e\u0924\u093e \u0939\u0948 |<\/p>\n

\"NCERT
\n\"NCERT<\/p>\n

\u091a\u0942\u0901\u0915\u093f\u00a0\u0917\u093e\u095c\u0940 \u0915\u0940 \u091a\u093e\u0932 \u090b\u0923\u093e\u0924\u094d\u092e\u0915 \u0928\u0939\u0940\u0902 \u0939\u094b \u0938\u0915\u0924\u0940 \u0939\u0948 \u0907\u0938\u0932\u093f\u090f \u091a\u093e\u0932 = 40 km\/h<\/p>\n

\"NCERT<\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u091b\u094b\u091f\u093e \u0928\u0932, \u091f\u0902\u0915\u0940 \u0915\u094b \u0905\u0915\u0947\u0932\u0947 x \u0918\u0902\u091f\u0947 \u092e\u0947\u0902 \u092d\u0930\u0924\u093e \u0939\u0948 |<\/p>\n

\u0924\u094b \u092c\u095c\u093e \u092c\u094d\u092f\u093e\u0938 \u0935\u093e\u0932\u093e \u0928\u0932 \u091f\u0902\u0915\u0940 \u092d\u0930\u0947\u0917\u093e = x – 10 \u0918\u0902\u091f\u0947 \u092e\u0947\u0902<\/p>\n

\"NCERT
\n\"NCERT<\/p>\n

(x = 30\/8 \u0938\u0902\u092d\u0935 \u0928\u0939\u0940\u0902 \u0939\u0948 \u0915\u094d\u092f\u094b\u0902\u0915\u093f \u092f\u0939 10 \u0918\u0902\u091f\u093e \u0938\u0947 \u092d\u0940 \u0915\u092e \u0939\u0948 )<\/p>\n

\u0905\u0924: \u091b\u094b\u091f\u093e \u092c\u094d\u092f\u093e\u0938 \u0935\u093e\u0932\u093e \u0928\u0932 \u0905\u0915\u0947\u0932\u093e \u092d\u0930\u0947\u0917\u093e – 25 \u0918\u0902\u091f\u0947 \u092e\u0947\u0902<\/p>\n

\u0924\u094b \u092c\u095c\u093e \u0935\u094d\u092f\u093e\u0938 \u0935\u093e\u0932\u093e \u0928\u0932 \u092d\u0930\u0947\u0917\u093e 25 – 10 = 15 \u0918\u0902\u091f\u0947 \u092e\u0947\u0902<\/p>\n

Ex 4.3 Class 10 \u0917\u0923\u093f\u0924\u00a0Q10. \u092e\u0948\u0938\u0942\u0930 \u0914\u0930 \u092c\u0948\u0902\u0917\u0932\u094b\u0930 \u0915\u0947 \u092c\u0940\u091a \u0915\u0947 132 km \u092f\u093e\u0924\u094d\u0930\u093e \u0915\u0930\u0928\u0947 \u092e\u0947\u0902 \u090f\u0915 \u090f\u0915\u094d\u0938\u092a\u094d\u0930\u0947\u0938 \u0930\u0947\u0932\u0917\u093e\u095c\u0940, \u0938\u0935\u093e\u0930\u0940 \u0917\u093e\u095c\u0940 \u0938\u0947 1 \u0918\u0902\u091f\u093e \u0938\u092e\u092f \u0915\u092e \u0932\u0947\u0924\u0940 \u0939\u0948 (\u092e\u0927\u094d\u092f \u0915\u0947 \u0938\u094d\u091f\u0947\u0936\u0928\u094b\u0902 \u092a\u0930 \u0920\u0939\u0930\u0928\u0947 \u0915\u093e \u0938\u092e\u092f \u0927\u094d\u092f\u093e\u0928 \u092e\u0947\u0902 \u0928 \u0932\u093f\u092f\u093e \u091c\u093e\u090f )| \u092f\u0926\u093f \u090f\u0915\u094d\u0938\u092a\u094d\u0930\u0947\u0938 \u0930\u0947\u0932\u0917\u093e\u095c\u0940 \u0915\u0940 \u0914\u0938\u0924 \u091a\u093e\u0932, \u0938\u0935\u093e\u0930\u0940 \u0917\u093e\u095c\u0940 \u0915\u0940 \u091a\u093e\u0932 \u0938\u0947 11 km\/h\u00a0\u0905\u0927\u093f\u0915 \u0939\u094b, \u0924\u094b \u0926\u094b\u0928\u094b\u0902 \u0930\u0947\u0932\u0917\u093e\u095c\u0940 \u0915\u0940 \u0914\u0938\u0924 \u091a\u093e\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u0938\u0935\u093e\u0930\u0940 \u0917\u093e\u095c\u0940 \u0915\u0940 \u0938\u092e\u093e\u0928\u094d\u092f \u091a\u093e\u0932 = x km\/h<\/p>\n

\u0924\u094b \u090f\u0915\u094d\u0938\u092a\u094d\u0930\u0947\u0938 \u0917\u093e\u095c\u0940 \u0915\u0940 \u0938\u092e\u093e\u0928\u094d\u092f \u091a\u093e\u0932 = x + 11 km\/h<\/p>\n

\u092e\u0948\u0938\u0942\u0930 \u0914\u0930 \u092c\u0948\u0902\u0917\u0932\u094b\u0930 \u0915\u0940 \u092c\u0940\u091a \u0915\u0940 \u0926\u0941\u0930\u0940 = 132 km<\/p>\n

\"NCERT
\n\"NCERT<\/p>\n

–\u00a044 \u090f\u0915 \u0930\u0947\u0932\u0917\u093e\u095c\u0940 \u0915\u0940 \u091a\u093e\u0932 \u0928\u0939\u0940\u0902 \u0939\u094b \u0938\u0915\u0924\u093e \u0907\u0938\u0932\u093f\u090f x = 33 \u0932\u0947\u0902\u0917\u0947<\/p>\n

\u0905\u0924: \u0938\u0935\u093e\u0930\u0940 \u0917\u093e\u095c\u0940 \u0915\u0940 \u091a\u093e\u0932 = 33 km\/h \u0914\u0930<\/p>\n

\u090f\u0915\u094d\u0938\u092a\u094d\u0930\u0947\u0938 \u0917\u093e\u095c\u0940 \u0915\u0940 \u091a\u093e\u0932 = 33 + 11 = 44 km\/h<\/p>\n

Ex 4.3 Class 10 \u0917\u0923\u093f\u0924\u00a0Q11 \u00a0\u0926\u094b \u0935\u0930\u094d\u0917\u094b\u0902 \u0915\u0947 \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932\u094b\u0902 \u0915\u093e \u092f\u094b\u0917 468 m2<\/sup>\u00a0\u00a0\u0939\u0948 | \u092f\u0926\u093f \u0909\u0928\u0915\u0947 \u092a\u0930\u093f\u092e\u093e\u092a\u094b\u0902 \u0915\u093e \u0905\u0928\u094d\u0924\u0930 24m \u0939\u094b, \u0924\u094b\u00a0\u0926\u094b\u0928\u094b\u0902 \u0915\u0940 \u092d\u0941\u091c\u093e\u090f\u0901 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f|<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u090f\u0915 \u0935\u0930\u094d\u0917 \u0915\u0940 \u090f\u0915 \u092d\u0941\u091c\u093e = x m \u0914\u0930 \u0926\u0941\u0938\u0930\u0947 \u0935\u0930\u094d\u0917 \u0915\u0940 \u092d\u0941\u091c\u093e = y m<\/p>\n

\u092a\u0939\u0932\u093e \u0915\u093e \u092a\u0930\u093f\u092e\u093e\u092a = 4x m \u0914\u0930 \u0926\u0941\u0938\u0930\u0947 \u0915\u093e \u092a\u0930\u093f\u092e\u093e\u092a = 4y m<\/p>\n

\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0928\u0941\u0938\u093e\u0930,\u00a0<\/strong>\u0938\u094d\u0925\u093f\u0924<\/strong>\u00a0I<\/strong><\/p>\n

4x – 4y = 24<\/p>\n

\"NCERT<\/p>\n

x = 18, x = – 12 (\u0935\u0930\u094d\u0917 \u0915\u0940 \u092d\u0941\u091c\u093e \u090b\u0923\u093e\u0924\u094d\u092e\u0915 \u0928\u0939\u0940\u0902 \u0939\u094b \u0938\u0915\u0924\u0940 \u0907\u0938\u0932\u093f\u090f x = -12 \u0928\u0939\u0940\u0902 \u0932\u0947 \u0938\u0915\u0924\u0947 \u0939\u0948\u0902 )<\/p>\n

\u092a\u0939\u0932\u0947 \u0935\u0930\u094d\u0917 \u0915\u0940 \u092d\u0941\u091c\u093e = 18 m \u0924\u094b \u0926\u0941\u0938\u0930\u0947 \u0915\u0940 \u092d\u0941\u091c\u093e = 18 – 6 = 12 m<\/p>\n

<\/a>\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0935\u0932\u0940 4.4<\/strong><\/span><\/p>\n

Ex 4.4 Class 10 \u0917\u0923\u093f\u0924 Q1. \u0928\u093f\u092e\u094d\u0928 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u0947 \u092e\u0942\u0932\u094b\u0902 \u0915\u0940 \u092a\u094d\u0930\u0915\u0943\u0924\u093f \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f | \u092f\u0926\u093f \u092e\u0942\u0932\u094b\u0902 \u0915\u093e \u0905\u0938\u094d\u0924\u093f\u0924\u094d\u0935 \u0939\u094b \u0924\u094b \u0909\u0928\u094d\u0939\u0947\u0902 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f :<\/strong><\/p>\n

(i) \u00a02x2\u00a0<\/sup>– 3x + 5 = 0\u00a0<\/strong><\/p>\n

(ii) 3x2\u00a0<\/sup>\u200b\u00a0– 4\u221a3x + 4 = 0\u00a0<\/strong><\/p>\n

(iii) 2x2<\/sup>\u00a0+ 6x + 3 = 0\u00a0\u00a0<\/strong><\/p>\n

{\u0928\u094b\u091f<\/strong>\u00a0– \u092e\u0942\u0932\u094b\u0902 \u0915\u0940 \u092a\u094d\u0930\u0915\u0943\u0924\u093f \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0928\u0947 \u0915\u0947 \u0932\u093f\u090f \u0935\u093f\u0935\u093f\u0924\u0915\u0930 (Discriminant) \u0905\u0930\u094d\u0925\u093e\u0924 D = b2<\/sup>\u00a0– 4ac \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902\u0917\u0947 |<\/p>\n

\u092f\u0926\u093f D \u0915\u093e \u092e\u093e\u0928 0 \u0939\u0948 (D = 0) \u0924\u094b \u092a\u094d\u0930\u0915\u0943\u0924\u093f – \u0926\u094b \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u0914\u0930 \u0938\u092e\u093e\u0928 \u092e\u0942\u0932 \u0939\u094b\u0902\u0917\u0947, \u0914\u0930 D \u0915\u093e \u092e\u093e\u0928 0 \u0938\u0947 \u0905\u0927\u093f\u0915 \u0905\u0930\u094d\u0925\u093e\u0924 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u0939\u0948 (D > 0) \u0924\u094b \u092a\u094d\u0930\u0915\u0943\u0924\u093f – \u0926\u094b \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u0914\u0930 \u0905\u0938\u092e\u093e\u0928 \u092e\u0942\u0932 \u0939\u094b\u0917\u093e \u0914\u0930 \u092f\u0926\u093f D \u0915\u093e \u092e\u093e\u0928 0 \u0938\u0947 \u0915\u092e \u0939\u0948 \u0905\u0930\u094d\u0925\u093e\u0924 \u090b\u0923\u093e\u0924\u094d\u092e\u0915 \u0939\u0948 (D < 0) \u0924\u094b \u092e\u0942\u0932 \u0915\u093e \u0915\u094b\u0908 \u0905\u0938\u094d\u0924\u093f\u0924\u094d\u0935 \u0928\u0939\u0940\u0902 \u0939\u094b\u0917\u093e \u0905\u0930\u094d\u0925\u093e\u0924\u0915\u094b\u0908 \u092e\u0942\u0932 \u0928\u0939\u0940\u0902 \u0939\u094b\u0917\u093e |}<\/p>\n

\u0939\u0932 :<\/strong>\u00a0(i) \u00a02x2\u00a0<\/sup>– 3x + 5 = 0<\/p>\n

a = 2, b = -3 \u0914\u0930 c = 5<\/p>\n

D = b2\u00a0<\/sup>– 4ac<\/p>\n

= (-3)2<\/sup>\u00a0– 4\u00a0\u00d7 2\u00a0\u00d7 5<\/p>\n

= 9 – 40<\/p>\n

= -31<\/p>\n

\u091a\u0942\u0901\u0915\u093f D \u0915\u093e \u090b\u0923\u093e\u0924\u094d\u092e\u0915 \u092e\u093e\u0928 \u092f\u0939 \u092c\u0924\u093e\u0924\u093e \u0939\u0948 \u0915\u093f D < 0 \u0938\u0947 \u0905\u0924: \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u093e \u0915\u094b\u0908 \u092e\u0942\u0932 \u0928\u0939\u0940\u0902 \u0939\u0948 |<\/p>\n

\u0939\u0932 :<\/strong>\u00a0(ii) 3x2\u00a0<\/sup>\u200b\u00a0– 4\u221a3x + 4 = 0<\/p>\n

\u200ba = 3, b = – 4\u221a3 \u0914\u0930 c = 4<\/p>\n

D = b2<\/sup>\u00a0– 4ac<\/p>\n

= (-4\u221a3)2<\/sup>\u00a0– 4\u00a0\u00d7 3\u00a0\u00d7 4<\/p>\n

= 48 – 48<\/p>\n

= 0<\/p>\n

\u091a\u0942\u0901\u0915\u093f D = 0 \u0939\u0948 \u0905\u0924: \u0907\u0938\u0915\u0947 \u0926\u094b \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u090f\u0935\u0902 \u0938\u092e\u093e\u0928 \u092e\u0942\u0932 \u0939\u094b\u0902\u0917\u0947 |<\/p>\n

\"NCERT<\/p>\n

\u0939\u0932<\/strong>\u00a0:<\/strong>\u00a0(iii) 2x2<\/sup>\u00a0+ 6x + 3 = 0<\/p>\n

a = 2, b = 6 \u0914\u0930 c = 3<\/p>\n

D = b2<\/sup>\u00a0– 4ac<\/p>\n

= (6)2<\/sup>\u00a0– 4 \u00d7 2 \u00d7 3<\/p>\n

= 36 – 24<\/p>\n

= 12<\/p>\n

\u091a\u0942\u0901\u0915\u093f D > 0 \u0938\u0947 \u0905\u0924: \u0907\u0938 \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u0947 \u0926\u094b \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u090f\u0935\u0902 \u0905\u0938\u092e\u093e\u0928 \u092e\u0942\u0932 \u0939\u094b\u0902\u0917\u0947 |<\/p>\n

\"Download<\/p>\n

Ex 4.4 Class 10 \u0917\u0923\u093f\u0924\u00a0Q2. \u0928\u093f\u092e\u094d\u0928 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u092e\u0947\u0902 k \u0915\u093e \u0910\u0938\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f \u0915\u093f \u0909\u0938\u0915\u0947 \u0926\u094b \u092c\u0930\u093e\u092c\u0930 \u092e\u0942\u0932 \u0939\u094b\u0902 |<\/strong><\/p>\n

(i) 2x2\u00a0<\/sup>+ kx + 3 = 0\u00a0<\/strong><\/p>\n

(ii) kx (x – 2 ) + 6 = 0<\/strong><\/p>\n

\u0939\u0932<\/strong>\u00a0:<\/strong>\u00a0(i) 2x2\u00a0<\/sup>+ kx + 3 = 0<\/p>\n

a = 2, b = k \u0914\u0930 c = 3<\/p>\n

\u091a\u0942\u0901\u0915\u093f \u0926\u093f\u090f \u0917\u090f \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u0947 \u0926\u094b \u092c\u0930\u093e\u092c\u0930 \u092e\u0942\u0932 \u0939\u0948 \u0905\u0930\u094d\u0925\u093e\u0924<\/p>\n

\"NCERT<\/p>\n

\u0939\u0932 :<\/strong>\u00a0(ii) kx (x – 2 ) + 6 = 0<\/p>\n

=>\u00a0kx2<\/sup>\u00a0– 2kx + 6 = 0<\/p>\n

a = k, b =\u00a0–\u00a02k, c = 6<\/p>\n

\u091a\u0942\u0901\u0915\u093f \u0926\u093f\u090f \u0917\u090f \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u0947 \u0926\u094b \u092c\u0930\u093e\u092c\u0930 \u092e\u0942\u0932 \u0939\u0948 \u0905\u0930\u094d\u0925\u093e\u0924<\/p>\n

\"Solutions<\/p>\n

Ex 4.4 Class 10 \u0917\u0923\u093f\u0924\u00a0Q3. \u0915\u094d\u092f\u093e \u090f\u0915 \u0910\u0938\u0940 \u0906\u092e \u0915\u0940 \u092c\u0917\u093f\u092f\u093e \u092c\u0928\u093e\u0928\u093e \u0938\u0902\u092d\u0935 \u0939\u0948 \u091c\u093f\u0938\u0915\u0940 \u0932\u0902\u092c\u093e\u0908, \u091a\u094c\u095c\u093e\u0908 \u0938\u0947 \u0926\u0941\u0917\u0941\u0928\u0940 \u0939\u094b \u0914\u0930 \u0909\u0938\u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 800 m2\u00a0<\/sup>\u0939\u094b? \u092f\u0926\u093f \u0939\u0948, \u0924\u094b \u0909\u0938\u0915\u0940 \u0932\u0902\u092c\u093e\u0908 \u0914\u0930 \u091a\u094c\u095c\u093e\u0908 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

\u0939\u0932 :\u00a0<\/strong>\u092e\u093e\u0928\u093e \u0906\u092e \u0915\u0940 \u092c\u0917\u093f\u092f\u093e \u0915\u0940 \u091a\u094c\u095c\u093e\u0908 = x m<\/p>\n

\u0924\u094b \u0932\u0902\u092c\u093e\u0908 = 2x m<\/p>\n

\u0905\u092c, \u0932\u0902\u092c\u093e\u0908 \u00d7 \u091a\u094c\u095c\u093e\u0908 = \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932<\/p>\n

\"NCERT<\/p>\n

\u0905\u0924: \u091a\u094c\u095c\u093e\u0908 = 20 m \u0914\u0930<\/p>\n

\u0932\u0902\u092c\u093e\u0908 = 2x = 2 \u00d7 20 = 40 m<\/p>\n

\u0939\u093e\u0901, \u0910\u0938\u0940 \u0906\u092e \u0915\u0940 \u092c\u0917\u093f\u092f\u093e \u0938\u0902\u092d\u0935 \u0939\u0948 |<\/p>\n

Ex 4.4 Class 10 \u0917\u0923\u093f\u0924\u00a0Q4. \u0915\u094d\u092f\u093e \u0928\u093f\u092e\u094d\u0928 \u0938\u094d\u0925\u093f\u0924\u093f \u0938\u0902\u092d\u0935 \u0939\u0948 ? \u092f\u0926\u093f \u0939\u0948 \u0924\u094b \u0909\u0928\u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0906\u092f\u0941 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f | \u0926\u094b \u092e\u093f\u0924\u094d\u0930\u094b\u0902 \u0915\u0940\u00a0\u0906\u092f\u0941 \u0915\u093e \u092f\u094b\u0917 20 \u0935\u0930\u094d\u0937 \u0939\u0948| \u091a\u093e\u0930 \u0935\u0930\u094d\u0937 \u092a\u0942\u0930\u094d\u0935 \u0909\u0928\u0915\u0940 \u0906\u092f\u0941 (\u0935\u0930\u094d\u0937\u094b\u0902 \u092e\u0947\u0902) \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 48 \u0925\u093e |<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u090f\u0915 \u092e\u093f\u0924\u094d\u0930 \u0915\u0940 \u0935\u0930\u094d\u0924\u094d\u0924\u092e\u093e\u0928 \u0906\u092f\u0941 = x \u0935\u0930\u094d\u0937<\/p>\n

\u0924\u094b \u0926\u0941\u0938\u0930\u0947 \u092e\u093f\u0924\u094d\u0930 \u0915\u0940 \u0935\u0930\u094d\u0924\u094d\u0924\u092e\u093e\u0928 \u0906\u092f\u0941 = 20 – x \u0935\u0930\u094d\u0937<\/p>\n

4 \u0935\u0930\u094d\u0937 \u092a\u0942\u0930\u094d\u0935 \u0909\u0928\u0915\u0940 \u0906\u092f\u0941 \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 =<\/p>\n

=>\u00a0\u00a0\u00a0 (x – 4) (20 – x – 4) = 48<\/p>\n

=>\u00a0\u00a0\u00a0 (x – 4) (16 – x) = 48<\/p>\n

=>\u00a0\u00a0\u00a0 16x – x2<\/sup>\u00a0– 64 + 4x = 48<\/p>\n

=>\u00a0\u00a0\u00a0 20x – x2<\/sup>\u00a0– 64 – 48 = 0<\/p>\n

=>\u00a0\u00a0\u00a0 20x – x2<\/sup>\u00a0– 112 = 0<\/p>\n

=>\u00a0\u00a0\u00a0 x2<\/sup>\u00a0– 20x + 112 = 0<\/p>\n

\u0907\u0938 \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u0947 \u092e\u0942\u0932 \u0915\u093e \u0905\u0938\u094d\u0924\u093f\u0924\u094d\u0935 \u0939\u0948 \u092f\u093e \u0928\u0939\u0940\u0902 \u092f\u0939 \u091c\u093e\u0901\u091a \u0915\u0930\u0947\u0902\u0917\u0947 |<\/p>\n

a = 1, b = – 20 \u0914\u0930 c = 112<\/p>\n

D = b2<\/sup>\u00a0– 4ac<\/p>\n

= (-20)2<\/sup>\u00a0– 4(1)(112)<\/p>\n

= 400 – 448<\/p>\n

= – 48<\/p>\n

\u091a\u0942\u0901\u0915\u093f D < 0 \u0939\u0948 \u0907\u0938\u0932\u093f\u090f \u0907\u0938 \u0938\u092e\u0940\u0915\u0930\u0923 \u0915\u093e \u0915\u094b\u0908 \u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u092e\u0942\u0932 \u0928\u0939\u0940\u0902 \u0939\u0948 \u0905\u0924: \u092f\u0939 \u0938\u0902\u092d\u0935 \u0928\u0939\u0940\u0902 \u0939\u0948 |<\/p>\n

Ex 4.4 Class 10 \u0917\u0923\u093f\u0924\u00a0Q5. \u0915\u094d\u092f\u093e \u092a\u0930\u093f\u092e\u093e\u092a 80 m \u0924\u0925\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 400m2\u00a0<\/sup>\u0915\u0947 \u090f\u0915 \u092a\u093e\u0930\u094d\u0915 \u0915\u094b \u092c\u0928\u093e\u0928\u093e \u0938\u0902\u092d\u0935 \u0939\u0948 ? \u092f\u0926\u093f \u0939\u0948, \u0924\u094b\u00a0\u00a0\u0909\u0938\u0915\u0940 \u0932\u0902\u092c\u093e\u0908 \u0914\u0930 \u091a\u094c\u095c\u093e\u0908 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |<\/strong><\/p>\n

\u0939\u0932 :<\/strong>\u00a0\u092e\u093e\u0928\u093e \u092a\u093e\u0930\u094d\u0915 \u0915\u093e \u0932\u0902\u092c\u093e\u0908 = x m<\/p>\n

\u0914\u0930 \u091a\u094c\u095c\u093e\u0908 = y m<\/p>\n

\u0924\u094b, 2(\u0932\u0902\u092c\u093e\u0908 + \u091a\u094c\u095c\u093e\u0908) = \u092a\u0930\u093f\u092e\u093e\u092a<\/p>\n

2(x + y) = 80 m<\/p>\n

x + y = 40 m<\/p>\n

y = 40 – x m<\/p>\n

\u0905\u0924: \u091a\u094c\u095c\u093e\u0908 = 40 – x m<\/p>\n

\u0905\u092c, \u0932\u0902\u092c\u093e\u0908 \u00d7 \u091a\u094c\u095c\u093e\u0908 = \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932<\/p>\n

x(40 – x) = 400<\/p>\n

=> 40x – x2<\/sup>\u00a0= 400<\/p>\n

=>\u00a0 x2<\/sup>\u00a0– 40x + 400 = 0<\/p>\n

=>\u00a0 x2<\/sup>\u00a0– 20x – 20x + 400 = 0<\/p>\n

=>\u00a0 x(x – 20) – 20(x – 20) = 0<\/p>\n

=>\u00a0 (x – 20) (x -20) = 0<\/p>\n

=>\u00a0 x – 20 = 0, x – 20 = 0<\/p>\n

=>\u00a0 x = 20 \u0914\u0930 x = 20<\/p>\n

\u0905\u0924: \u092a\u093e\u0930\u094d\u0915 \u0915\u0940 \u0932\u0902\u092c\u093e\u0908 = 20 \u092e\u0940\u091f\u0930 \u0924\u094b \u091a\u094c\u095c\u093e\u0908 = 40 – 20 = 20 \u092e\u0940\u091f\u0930<\/p>\n

Hope given NCERT Solutions for Class 10 Maths Chapter 4\u00a0are helpful to complete your homework.<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) These Solutions are part of NCERT Solutions for Class 10 Maths in Hindi Medium. Here we have given NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations\u00a0. Chapter 4. \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0935\u0932\u0940 4.1 Ex 4.1 Class 10 \u0917\u0923\u093f\u0924 Q1. \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f …<\/p>\n

NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)<\/span> Read More »<\/a><\/p>\n","protected":false},"author":5,"featured_media":7606,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[2],"tags":[14,23,13,22,11,20,12,21,18,19],"yoast_head":"\nNCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) - NCERT Solutions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) - NCERT Solutions\" \/>\n<meta property=\"og:description\" content=\"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) These Solutions are part of NCERT Solutions for Class 10 Maths in Hindi Medium. Here we have given NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations\u00a0. Chapter 4. \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0935\u0932\u0940 4.1 Ex 4.1 Class 10 \u0917\u0923\u093f\u0924 Q1. \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f … NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) Read More »\" \/>\n<meta property=\"og:url\" content=\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/\" \/>\n<meta property=\"og:site_name\" content=\"NCERT Solutions\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/NCERTSolutionsGuru\/\" \/>\n<meta property=\"article:published_time\" content=\"2021-07-23T00:46:05+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2021-07-23T13:06:34+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/ncertsolutions.guru\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png\" \/>\n\t<meta property=\"og:image:width\" content=\"1280\" \/>\n\t<meta property=\"og:image:height\" content=\"720\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@ncertsolguru\" \/>\n<meta name=\"twitter:site\" content=\"@ncertsolguru\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Raju\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"8 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Organization\",\"@id\":\"https:\/\/ncertsolutions.guru\/#organization\",\"name\":\"NCERT Solutions\",\"url\":\"https:\/\/ncertsolutions.guru\/\",\"sameAs\":[\"https:\/\/www.facebook.com\/NCERTSolutionsGuru\/\",\"https:\/\/www.instagram.com\/ncertsolutionsguru\/\",\"https:\/\/www.linkedin.com\/in\/ncertsolutionsguru\/\",\"https:\/\/in.pinterest.com\/ncertsolutionsguru\/\",\"https:\/\/en.wikipedia.org\/wiki\/National_Council_of_Educational_Research_and_Training\",\"https:\/\/twitter.com\/ncertsolguru\"],\"logo\":{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/ncertsolutions.guru\/#logo\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2020\/05\/NCERT-Solutions.png?fit=460%2C45&ssl=1\",\"contentUrl\":\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2020\/05\/NCERT-Solutions.png?fit=460%2C45&ssl=1\",\"width\":460,\"height\":45,\"caption\":\"NCERT Solutions\"},\"image\":{\"@id\":\"https:\/\/ncertsolutions.guru\/#logo\"}},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/ncertsolutions.guru\/#website\",\"url\":\"https:\/\/ncertsolutions.guru\/\",\"name\":\"NCERT Solutions\",\"description\":\"NCERT Solutions for Class 1 to 12\",\"publisher\":{\"@id\":\"https:\/\/ncertsolutions.guru\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/ncertsolutions.guru\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#primaryimage\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png?fit=1280%2C720&ssl=1\",\"contentUrl\":\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png?fit=1280%2C720&ssl=1\",\"width\":1280,\"height\":720,\"caption\":\"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#webpage\",\"url\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/\",\"name\":\"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) - NCERT Solutions\",\"isPartOf\":{\"@id\":\"https:\/\/ncertsolutions.guru\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#primaryimage\"},\"datePublished\":\"2021-07-23T00:46:05+00:00\",\"dateModified\":\"2021-07-23T13:06:34+00:00\",\"breadcrumb\":{\"@id\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/ncertsolutions.guru\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)\"}]},{\"@type\":\"Article\",\"@id\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#webpage\"},\"author\":{\"@id\":\"https:\/\/ncertsolutions.guru\/#\/schema\/person\/af617eea64a84db47d4ed295a25aaa52\"},\"headline\":\"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)\",\"datePublished\":\"2021-07-23T00:46:05+00:00\",\"dateModified\":\"2021-07-23T13:06:34+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#webpage\"},\"wordCount\":1552,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/ncertsolutions.guru\/#organization\"},\"image\":{\"@id\":\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png?fit=1280%2C720&ssl=1\",\"keywords\":[\"Maths NCERT Solutions For Class 10\",\"Maths NCERT Solutions For Class 10 Hindi Medium\",\"NCERT Maths Solutions For Class 10\",\"NCERT Maths Solutions For Class 10 Hindi Medium\",\"NCERT Solutions For Class 10 Maths\",\"NCERT Solutions For Class 10 Maths Hindi Medium\",\"NCERT Solutions For Class 10 Maths PDF\",\"NCERT Solutions For Class 10 Maths PDF Hindi Medium\",\"NCERT Solutions For Maths Class 10\",\"Solutions For NCERT Maths Class 10\"],\"articleSection\":[\"CBSE Class 10\"],\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#respond\"]}]},{\"@type\":\"Person\",\"@id\":\"https:\/\/ncertsolutions.guru\/#\/schema\/person\/af617eea64a84db47d4ed295a25aaa52\",\"name\":\"Raju\",\"image\":{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/ncertsolutions.guru\/#personlogo\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/38ccf4a5413b0ede9fc79802993d6981?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/38ccf4a5413b0ede9fc79802993d6981?s=96&d=mm&r=g\",\"caption\":\"Raju\"},\"url\":\"https:\/\/ncertsolutions.guru\/author\/raju\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) - NCERT Solutions","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/","og_locale":"en_US","og_type":"article","og_title":"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) - NCERT Solutions","og_description":"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) These Solutions are part of NCERT Solutions for Class 10 Maths in Hindi Medium. Here we have given NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations\u00a0. Chapter 4. \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0935\u0932\u0940 4.1 Ex 4.1 Class 10 \u0917\u0923\u093f\u0924 Q1. \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f … NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) Read More »","og_url":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/","og_site_name":"NCERT Solutions","article_publisher":"https:\/\/www.facebook.com\/NCERTSolutionsGuru\/","article_published_time":"2021-07-23T00:46:05+00:00","article_modified_time":"2021-07-23T13:06:34+00:00","og_image":[{"width":1280,"height":720,"url":"https:\/\/ncertsolutions.guru\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png","path":"\/home\/412375.cloudwaysapps.com\/bmvvpkvjjm\/public_html\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png","size":"full","id":7606,"alt":"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)","pixels":921600,"type":"image\/png"}],"twitter_card":"summary_large_image","twitter_creator":"@ncertsolguru","twitter_site":"@ncertsolguru","twitter_misc":{"Written by":"Raju","Est. reading time":"8 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Organization","@id":"https:\/\/ncertsolutions.guru\/#organization","name":"NCERT Solutions","url":"https:\/\/ncertsolutions.guru\/","sameAs":["https:\/\/www.facebook.com\/NCERTSolutionsGuru\/","https:\/\/www.instagram.com\/ncertsolutionsguru\/","https:\/\/www.linkedin.com\/in\/ncertsolutionsguru\/","https:\/\/in.pinterest.com\/ncertsolutionsguru\/","https:\/\/en.wikipedia.org\/wiki\/National_Council_of_Educational_Research_and_Training","https:\/\/twitter.com\/ncertsolguru"],"logo":{"@type":"ImageObject","@id":"https:\/\/ncertsolutions.guru\/#logo","inLanguage":"en-US","url":"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2020\/05\/NCERT-Solutions.png?fit=460%2C45&ssl=1","contentUrl":"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2020\/05\/NCERT-Solutions.png?fit=460%2C45&ssl=1","width":460,"height":45,"caption":"NCERT Solutions"},"image":{"@id":"https:\/\/ncertsolutions.guru\/#logo"}},{"@type":"WebSite","@id":"https:\/\/ncertsolutions.guru\/#website","url":"https:\/\/ncertsolutions.guru\/","name":"NCERT Solutions","description":"NCERT Solutions for Class 1 to 12","publisher":{"@id":"https:\/\/ncertsolutions.guru\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/ncertsolutions.guru\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"ImageObject","@id":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#primaryimage","inLanguage":"en-US","url":"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png?fit=1280%2C720&ssl=1","contentUrl":"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png?fit=1280%2C720&ssl=1","width":1280,"height":720,"caption":"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)"},{"@type":"WebPage","@id":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#webpage","url":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/","name":"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium) - NCERT Solutions","isPartOf":{"@id":"https:\/\/ncertsolutions.guru\/#website"},"primaryImageOfPage":{"@id":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#primaryimage"},"datePublished":"2021-07-23T00:46:05+00:00","dateModified":"2021-07-23T13:06:34+00:00","breadcrumb":{"@id":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/ncertsolutions.guru\/"},{"@type":"ListItem","position":2,"name":"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)"}]},{"@type":"Article","@id":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#article","isPartOf":{"@id":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#webpage"},"author":{"@id":"https:\/\/ncertsolutions.guru\/#\/schema\/person\/af617eea64a84db47d4ed295a25aaa52"},"headline":"NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations (Hindi Medium)","datePublished":"2021-07-23T00:46:05+00:00","dateModified":"2021-07-23T13:06:34+00:00","mainEntityOfPage":{"@id":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#webpage"},"wordCount":1552,"commentCount":0,"publisher":{"@id":"https:\/\/ncertsolutions.guru\/#organization"},"image":{"@id":"https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#primaryimage"},"thumbnailUrl":"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png?fit=1280%2C720&ssl=1","keywords":["Maths NCERT Solutions For Class 10","Maths NCERT Solutions For Class 10 Hindi Medium","NCERT Maths Solutions For Class 10","NCERT Maths Solutions For Class 10 Hindi Medium","NCERT Solutions For Class 10 Maths","NCERT Solutions For Class 10 Maths Hindi Medium","NCERT Solutions For Class 10 Maths PDF","NCERT Solutions For Class 10 Maths PDF Hindi Medium","NCERT Solutions For Maths Class 10","Solutions For NCERT Maths Class 10"],"articleSection":["CBSE Class 10"],"inLanguage":"en-US","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/ncertsolutions.guru\/ncert-solutions-for-class-10-maths-chapter-4-hindi\/#respond"]}]},{"@type":"Person","@id":"https:\/\/ncertsolutions.guru\/#\/schema\/person\/af617eea64a84db47d4ed295a25aaa52","name":"Raju","image":{"@type":"ImageObject","@id":"https:\/\/ncertsolutions.guru\/#personlogo","inLanguage":"en-US","url":"https:\/\/secure.gravatar.com\/avatar\/38ccf4a5413b0ede9fc79802993d6981?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/38ccf4a5413b0ede9fc79802993d6981?s=96&d=mm&r=g","caption":"Raju"},"url":"https:\/\/ncertsolutions.guru\/author\/raju\/"}]}},"jetpack_featured_media_url":"https:\/\/i1.wp.com\/ncertsolutions.guru\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Hindi-Medium.png?fit=1280%2C720&ssl=1","_links":{"self":[{"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/posts\/57"}],"collection":[{"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/comments?post=57"}],"version-history":[{"count":0,"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/posts\/57\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/media\/7606"}],"wp:attachment":[{"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/media?parent=57"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/categories?post=57"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ncertsolutions.guru\/wp-json\/wp\/v2\/tags?post=57"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}