Answer<\/span><\/summary>\nAnswer: (c) (HCF)(LCM) = ab
\n7. (HCF) (LCM) = product of nos. a and b.<\/p>\n<\/details>\n
\nQuestion 16.
\nIf we write 0.9 as a rational number, we get:
\n(a) \\(\\frac{9}{10}\\)
\n(b) 1
\n(c) \\(\\frac{1}{2}\\)
\n(d) \\(\\frac{1}{10}\\)<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (b) 1
\n8. Let x = 0.9
\n10x =9.9
\n9x = 9
\nx = 1<\/p>\n<\/details>\n
\nQuestion 17.
\nWrite an irrational number between 2 and 3.
\n(a) 2.5
\n(b) 2.001
\n(c) 2.1333333456…
\n(d) 2.13<\/p>\n\nAnswer<\/span><\/summary>\nAnswer:(c) 2.1333333456…
\nnon terminating non repeating<\/p>\n<\/details>\n
\nQuestion 18.
\nWhich of the following are irrational whose sum and product are both rationals :
\n(a) \u221a2 + 3,\u221a2 – 3
\n(b) \u221a2 + \u221a3,\u221a2 – \u221a3
\n(c) 3 + \u221a2, 3 – \u221a2
\n(d) \u221a2 + 1,\u221a2 – 1<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) 3 + \u221a2, 3 – \u221a2
\n3 + \u221a2 + 3 – \u221a2 = 6 and (3+\u221a2) (3-\u221a2) =7<\/p>\n<\/details>\n
\nQuestion 19.
\nFind the value of x from the following such that x2<\/sup> is irrational but x4<\/sup> is rational:
\n(a) \u221a2
\n(b) 3\u221a2
\n(c) 4\u221a2
\n(d) 2<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) 4\u221a2
\n\u221a2 is a irrational number.<\/p>\n<\/details>\n
\nQuestion 20.
\nA rational number between 72 and 73 is:
\n(a) \\(\\frac{\u221a2 + \u221a3}{2}\\)
\n(b) \\(\\frac{\u221a2 – \u221a3}{2}\\)
\n(c) 1.5
\n(d) 1.8<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) 1.5<\/p>\n<\/details>\n
\nQuestion 21.
\nThe rational number that corresponds
\nto 0.6+0.\\(\\bar{7}\\)+0.4\\(\\bar{7}\\) is :
\n(a) \\(\\frac{83}{90}\\)
\n(b) \\(\\frac{7}{9}\\)
\n(c) \\(\\frac{43}{90}\\)
\n(d) \\(\\frac{167}{90}\\)<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (d) \\(\\frac{167}{90}\\)
\n0.7 = 7\/9
\n0.6 + 0.7 + 0.47
\n= 6\/10 + 7\/9 + 43\/90
\n= \\(\\frac{167}{90}\\)<\/p>\n<\/details>\n
\nQuestion 22.
\nThe greatest number which divides 87 and 97, leaving 7 as remainder is :
\n(a) 10
\n(b) 1
\n(c) 87 x 97
\n(d) 6300<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (a) 10
\nGreatest number which divides 87 and 97, leaving 7 as remainder = HCF of 80 and 90<\/p>\n<\/details>\n
\nQuestion 23.
\nThe least number, which when divided by 10,14 and 18, leaves remainder 4, is :
\na) 630
\n(b) 634
\n(c) 252
\n(d) 496<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (b) 634
\nRequired number is the LCM of 10, 14 and 18 (is 630) + 4
\n= 630 + 4
\n= 634<\/p>\n<\/details>\n
\nQuestion 24.
\nThe greatest number which divides 17, 28 and 34 leaving remainders 2, 3 and 4 respectively is:
\n(a) 5
\n(b) 24
\n(c) 1
\n(d) 17<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (a) 5
\nHere 17 – 2 = 15, 28 – 3 = 25, 34 – 4 = 30 Required number is the HCF of 15,25 and 30 = 5<\/p>\n<\/details>\n
\nQuestion 25.
\n72 litres of liquid A and 108 litres of liquid B are to be packed in containers of the same size. The minimum number of containers required are:
\na) 36
\n(b) 18
\n(c) 5
\n(d) 10<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) 5
\nFor minimum number of containers required, each container should contain the maximum liquid.
\nVolume of each container should be the HCF of 72 and 108, which is 36. Number of containers required for liquid
\nA = \\(\\frac{72}{36}\\) = 2
\nNumber of containers required for liquid
\nB = \\(\\frac{108}{36}\\) = 3
\ntotal = 5<\/p>\n<\/details>\n
\nQuestion 26.
\nhe HCF of two consecutive rational numbers x and x +1 is :
\n(a) x
\n(b)x + 1
\n(c)1
\n(d) 0<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c)1
\nHCF of two consecutive numbers is always 1.<\/p>\n<\/details>\n
\nQuestion 27.
\nThe HCF of a number which is neither prime nor composite and any other number x is:
\n(a) x
\n(b) x + 1
\n(c) 1
\n(d) Any number<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) 1
\nAs, 1 is neither prime nor a composite number, thus, required number is the HCF of 1 and x, which is 1<\/p>\n<\/details>\n
\nQuestion 28.
\nFind q and r, if 12560 = 215 q + r.
\n(a) q = 58, r = 0
\n(b) q = 58, r = 10
\n(c) q = 58, r = 4
\n(d) q = 58, r = 90<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (d) q = 58, r = 90
\nUsing Euclid’s Lemma, 12560 when divided by 215, gives quotient as 58 and remainder as 90.
\n=> 12560 = 215 (58) + 90
\n=>q = 58 and r = 90<\/p>\n<\/details>\n
\nQuestion 29.
\nUsing Euclid’s Lemma, if d is the HCF of 1155 and 506, find ‘d’
\n(a) 11
\n(b) 143
\n(c) 77
\n(d) 66<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (a) 11
\n1155=506×2 + 143
\n506 = 143 x 3 + 77
\n143 =77×1 + 66
\n77 =66 x 1 + 11
\n66 =11×6 + 0
\nLast divisor = 11 =>
\n11= HCF (66,11) =
\nHCF (1155,506)
\n=>d = 11<\/p>\n<\/details>\n
\nQuestion 30.
\nAn army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups have to march in the same number of columns. Find the maximum number of columns in which they can march ?
\n(a) 32
\n(b) 60
\n(c) 40
\n(d) 8<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (d) 8
\nRequired number is the HCF of 616 and 32 616 = 32 x 19 + 8\u00a0 32 =8 x 4 + 0
\nHCF (616,32) = 8<\/p>\n<\/details>\n
\nQuestion 31.
\nThe factor tree of a number has some unknowns, find the values of a, b, c, d, e,f and g.
\n<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: a = 277720, b = 6930, c = 3465, d = 3, e = 385, f = 77, g = 11<\/p>\n<\/details>\n
\nQuestion 32.
\nWhich of the following is a rational number ?
\n(a)
\n(b)
\n(c)
\n(d) <\/p>\n\nAnswer<\/span><\/summary>\nAnswer: <\/p>\n
<\/p>\n<\/details>\n
\nQuestion 33.
\n\\(\\frac{91}{625}\\) ,when written in decimal form 625 terminates; as factors of denominator are in the form m2<\/sup> x n5<\/sup>. This number will terminate after how many digits ?
\n(a) 3
\n(b) 2
\n(c) 1
\n(d) 4<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (d) 4
\n= 91 x 16\/104<\/sup>
\n= 1456\/104<\/sup> = 0.1456<\/p>\n<\/details>\n
\nQuestion 34.
\nSelect the incorrect answer,
\n(2 + \u221a5)(2-\u221a5) is:
\n(a) a natural number
\n(b) a rational number
\n(c) a whole number
\n(d) an irrational number<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (d) an irrational number
\nwhich is a natural number, a whole number and also a rational number.<\/p>\n<\/details>\n
\nQuestion 35.
\nWhich of the following rational numbers, in decimal form, terminates ?
\n(a) \\(\\frac{64}{455}\\)
\n(b) \\(\\frac{77}{210}\\)
\n(c) \\(\\frac{31}{200}\\)
\n(d) \\(\\frac{29}{343}\\)<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) \\(\\frac{31}{200}\\)
\n(a) \\(\\frac{64}{455}\\)
\n= \\(\\frac{64}{5 \u00d7 7 \u00d7 13}\\)
\n= non terminating
\n(b) \\(\\frac{77}{210}\\)
\n= \\(\\frac{77}{7 \u00d7 2 \u00d7 3 x 5}\\)
\n= non terminating
\n(c) \\(\\frac{31}{200}\\)
\n= 31\/23<\/sup> \u00d7 52<\/sup>
\n= terminating
\n(d) \\(\\frac{29}{343}\\)
\n= 29\/73<\/sup>
\n= non terminating<\/p>\n<\/details>\n
\nQuestion 36.
\n\\(\\frac{91}{625}\\) ,when written in decimal form 625 terminates; as factors of denominator are in the form m2<\/sup> x n5<\/sup>. This number will terminate after how many digits ?
\n(a) 3
\n(b) 2
\n(c) 1
\n(d) 4<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (d) 4
\n= 91 x 16\/104<\/sup>
\n= 1456\/104<\/sup> = 0.1456<\/p>\n<\/details>\n
\nQuestion 37.
\nSelect the incorrect answer,
\n(2 + \u221a5)(2-\u221a5) is:
\n(a) a natural number
\n(b) a rational number
\n(c) a whole number
\n(d) an irrational number<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (d) an irrational number
\nwhich is a natural number, a whole number and also a rational number.<\/p>\n<\/details>\n
\nQuestion 38.
\nThe least positive integer divisible by 20 and 24 is
\n(a) 360
\n(b) 120
\n(c) 480
\n(d) 240<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (b) 120<\/p>\n<\/details>\n
\nQuestion 39.
\nThe HCF and LCM of two numbers is 9 and 459 respectively. If one of the numbers is 27, then the other number is
\n(a) 459
\n(b) 153
\n(c) 135
\n(d) 150<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (b) 153<\/p>\n<\/details>\n
\nQuestion 40.
\nThe largest number which divides 615 and 963 leaving remainder 6 in each case is
\n(a) 82
\n(b) 95
\n(c) 87
\n(d) 93<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) 87<\/p>\n<\/details>\n
\nQuestion 41.
\nThe product of three consecutive integers is divisible by
\n(a) 5
\n(b) 6
\n(c) 7
\n(d) none of these<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (b) 6<\/p>\n<\/details>\n
\nQuestion 42.
\nThe least number that is divisible by all the numbers from 1 to 8 (both inclusive) is
\n(a) 840
\n(b) 2520
\n(c) 8
\n(d) 420<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (a) 840<\/p>\n<\/details>\n
\nQuestion 43.
\nThe smallest composite number is:
\n(a) 1
\n(b) 2
\n(c) 3
\n(d) 4<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) 3<\/p>\n<\/details>\n
\nQuestion 44.
\nFor some integer p, every odd integer is of the form
\n(a) 2p + 1
\n(b) 2p
\n(c) p + 1
\n(d) p<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (a) 2p + 1<\/p>\n<\/details>\n
\nQuestion 45.
\nThe smallest composite number is:
\n(a) 1
\n(b) 2
\n(c) 3
\n(d) 4<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) 3<\/p>\n<\/details>\n
\nQuestion 46.
\nA lemma is an axiom used for proving
\n(a) other statement
\n(b) no statement
\n(c) contradictory statement
\n(d) none of these<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (a) other statement<\/p>\n<\/details>\n
\nQuestion 47.
\nHCF of 8, 9, 25 is
\n(a) 8
\n(b) 9
\n(c) 25
\n(d) 1<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (d) 1<\/p>\n<\/details>\n
\nQuestion 48.
\n\u221a7 is
\n(a) An integer
\n(b) An irrational number
\n(c) A rational number
\n(d) None of these<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (b) An irrational number<\/p>\n<\/details>\n
\nQuestion 49.
\nThe product of a rational and irrational number is
\n(a) rational
\n(b) irrational
\n(c) both of above
\n(d) none of above<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (b) irrational<\/p>\n<\/details>\n
\nQuestion 50.
\nA number when divided by 61 gives 27 as quotient and 32 as remainder. find the number
\n(a) 1967
\n(b) 1796
\n(c) 1679
\n(d) 1569<\/p>\n\nAnswer<\/span><\/summary>\nAnswer: (c) 1679<\/p>\n<\/details>\n
\nQuestion 51.
\nFor any two positive integers a and b, there exist (unique) whole numbers q and r such that
\n(a) q = ar + b , 0 = r < b.
\n(b) a = bq + r , 0 = r < b.
\n(c) b = aq + r , 0 = r < b.
\n(d) none of these<\/p>\n\nAnswer<\/span><\/summary>\n